dynamically run linux shell commands - linux

Question

I have a command that should be executed by a shell script.
Actually the command does not matter the only thing that is important the further command execution and the right escaping of the critical parts.
The command that usually is executed normally in putty is something like this(maybe some additional flags for ls)
rm -r `ls /test/parse_first/ | awk '{print $2}' | grep trash`
but now I have a batch of such command so I would like to execute them in a loop
like
for i in {0..100}
do
str=str$i
${!str}
done
where str is :
str0="rm -r `ls /test/parse_first/ | awk '{print $2}' | grep trash`"
str1="rm -r `ls /test/parse_second/ | awk '{print $2}' | grep trash`"
and that gives me a lot of headache cause the execution done by ${!str} brakes the quotations and inline shell between `...` marks

Answer 1

my_rm() { rm -r `ls /test/$1 | awk ... | grep ... `; }
for i in `whatevr`; do
my_rm $i
done;

Answer 2

Getting this right is surprisingly tricky, but it can be done:
for i in $(seq 0 100)
do
str=str$i
eval "eval \"\$$str\""
done

Answer 3

You can also do:
for i in {0..10}
do
<whatevercommand>
done

Answer 4

It's actually simpler to place them on arrays and use glob patterns:
#!/bin/bash
shopt -s nullglob
DIRS=("/test/parse_first/" "/test/parse_second/")
for D in "${DIRS[#]}"; do
for T in "$D"/*trash*; do
rm -r -- "$T"
done
done
And if rm could accept multiple arguments, you don't need to have an extra loop:
for D in "${DIRS[#]}"; do
rm -r -- "$D"/*trash*
done
UPDATE:
#!/bin/bash
readarray -t COMMANDS <<'EOF'
rm -r `ls /test/parse_first/ | awk '{print $2}' | grep trash
rm -r `ls /test/parse_second/ | awk '{print $2}' | grep trash
EOF
for C in "${COMMANDS[#]}"; do
eval "$C"
done
Or you could just read commands from another file:
readarray -t COMMANDS < somefile.txt