I have a table in DB2 say METAATTRIBUTE wherein a column say "content" might contain any special character including the unicode characters.
For any special character, Eg: "#" I can simply search by :
Select * from METAATTRIBUTE where content like '%#%';
but how to search for unicode characters like "u201B" or "u201E" ???
Thanks in advance.
Assuming you are talking about DB2 LUW, the Unicode string literals are designated by the symbols "u&", followed by a regular string literal in single quotes. Unicode code points are designated by an escape character, backslash by default. For example:
$ db2 "values u&'\201b'"
1
---
‛
1 record(s) selected.
So your query would look like:
Select * from METAATTRIBUTE where content like u&'%\201b%';
Recently, I have had the same problem. This worked for me
select *
from METAATTRIBUTE
where MEDEDELINGSZONE like '%' || UX'201B' || '%'
Related
I have db structure like this :
"selfId": "cd29433e-f36b-1410-851b-009d805073d7",
"selfName" : "A",
"bookIds": [
"2f51bfd4",
"2f3a1010",
"090436c0",
"1078c3b2",
"b63b06e0"
]
I am working in C# and get bookId as a string.
I am writing query as :
string SQLquery = string.Format("select c.selfName from c where ARRAY_CONTAINS(c.bookIds,\""+bookId+"\"");
But When bookId contains special character, then query is giving error. For example if bookId = "AK"s" book" (please note id itself contains ") , then executing sqlQuery is giving error.
When a text contains quotes, slashes, special characters, you can use Escape Sequence
The quoted property operator [""] can also be used to access properties. for example, SELECT food.id and SELECT food["id"] are equal. This syntax can be used to escape a property with spaces, special characters, or a name that is the same as a SQL keyword or reserved term.
Example:
SELECT food["id"]
FROM food
WHERE food["foodGroup"] = "Snacks" and food["id"] = "19015"
Reference :- https://learn.microsoft.com/en-us/azure/cosmos-db/sql/sql-query-constants#bk_arguments
I have a query that looks like this:
INSERT INTO table VALUES ('47677;2019;2019;10T-1001-10010AS;A05;International;TieLineKoman-KosovoB;L_KOM-KOSB;2018;NULL;NULL;;NULL;Tieline;NULL;10XAL-KESH-----J;0;3')
that is produced by parsing a csv file.
The query is not in a valid form, I have to replace all semicolons with the string ',' (comma inside single quotes). What I want to get is:
('47677','2019','2019','10T-1001-10010AS','A05','International','TieLineKoman-KosovoB','L_KOM-KOSB','2018','NULL','NULL','','NULL','Tieline','NULL','10XAL-KESH-----J','0','3')
I have tried to do this in many different ways, but I end up with backshlashes added in my string. This is what I get:
"INSERT INTO AllocatedEICDetail VALUES ('47677\\',\\'2019\\',\\'2019\\',\\'10T-1001-10010AS\\',\\'A05\\',\\'International\\',\\'TieLineKoman-KosovoB\\',\\'L_KOM-KOSB\\',\\'2018\\',\\'NULL\\',\\'NULL\\',\\'\\',\\'NULL\\',\\'Tieline\\',\\'NULL\\',\\'10XAL-KESH-----J\\',\\'0\\',\\'3')"
Any ideas how to do this properly without having the backslashes added?
Thank you!
//the string you have
const string = '47677;2019;2019;10T-1001-10010AS;A05;International;TieLineKoman-KosovoB;L_KOM-KOSB;2018;NULL;NULL;;NULL;Tieline;NULL;10XAL-KESH-----J;0;3';
//the string you need:
const targetString = string.replace(/\;/g,',');
You specify a small regex between the forward slashes in replace which is a simple ';', give it a 'g' flag for global which will replace all instances, and in the second argument supply what you need it replaced with.
I have a large file of around 130MB containing 10 A characters in each line and \t at the end of 10th "A" character, I want to extract this text file and then change all A's to B's. Can any one help with its code snippet?
this is what I have wrote till now
USE DATABASE imodelanalytics;
#searchlog =
EXTRACT characters string
FROM "/iModelAnalytics/Samples/Data/dummy.txt"
USING Extractors.Text(delimiter: '\t', skipFirstNRows: 1);
#modify =
SELECT characters AS line
FROM #searchlog;
OUTPUT #modify
TO "/iModelAnalytics/Samples/Data/B.txt"
USING Outputters.Text();
I'm new to this, so any suggestions will be helpful ! Thanks
Assuming all of the field would be AAAAAAAAAA then you could write:
#modify = SELECT "BBBBBBBBBB" AS characters FROM #searchlog;
If only some are all As, then you would do it in the SELECT clause:
#modify =
SELECT (characters == "AAAAAAAAAA" ? "BBBBBBBBBB" : characters) AS characters
FROM #searchlog;
If there are other characters around the AAAAAAAAAA then you would use more of the C# string functions to find them and replace them in a similar pattern.
I have some hotels that contains characters which are not valie for when i want to insert these hotel names as a file name as file naming doesn't allow /, * or ? and want to know what this error means.
text?text
text?text
text**text**
text*text (text)
text *text*
text?
I am trying to use an if else statement so that if a hotel name contains any of these characters, then replace them with -. However I am receiving and error stating a dangling ?. I just want to check if I am using the replace correctly for these characters.
def hotelNameTrim = hotelName.toString()
if (hotelNameTrim.contains("/"))
{
hotelNameTrim.replaceAll("/", "-")
}
else if (hotelNameTrim.contains("*"))
{
hotelNameTrim.replaceAll("*", "-")
}
else if (hotelNameTrim.contains("?"))
{
hotelNameTrim.replaceAll("?", "-")
}
replaceAll accepts a regex as a search pattern. * and ? are special characters in regex and need to be escaped with a back slash. Which itself needs to be escaped in a Java string :)
Try this:
hotelNameTrim.replaceAll("[\\*\\?/]","-")
That will replace all you characters with a dash.
I have a string to modify as per the requirements.
For example:
The given string is:
str1 varchar = '123,456,789';
I want to show the string as:
'456,789'
Note: The first part (delimited) with comma, I want to remove from string and show the rest of string.
In SQL Server I used STUFF() function.
SELECT STUFF('123,456,789',1,4,'');
Result:
456,789
Question: Is there any string function in PostgreSQL 9.3 version to do the same job?
you can use regular expressions:
select substring('123,456,789' from ',(.*)$');
The comma matches the first comma found in the string. The part inside the brackets (.*) is returned from the function. The symbol $ means the end of the string.
A alternative solution without regular expressions:
select str, substring(str from position(',' in str)+1 for length(str)) from
(select '123,456,789'::text as str) as foo;
You could first turn the string to array and return second and third cell:
select array_to_string((regexp_split_to_array('123,456,789', ','))[2:3], ',')
Or you could use substring-function with regular expressions (pattern matching):
SELECT substring('123,456,789' from '[0-9]+,([0-9]+,[0-9]+)')
[0-9]+ means one or more digits
parentheses tell to return that part from the string
Both solutions work on your specific string.
Your The SQL Server example indicates you just want to remove the first 4 characters, which makes the rest of your question seem misleading because it completely ignores what's in the string. Only the positions matters.
Be that as it may, the simple and cheap way to cut off leading characters is with right():
SELECT right('123,456,789', -4);
SQL Fiddle.