In node application i need to get all the files in the directory except that hidden files.
I have tried fs.readdir but it displaying hidden files also.
Using the regex from this answer, this simple solution removes all hidden files from the result:
fs.readdir('/path/to/directory', (err, list) => {
list = list.filter(item => !(/(^|\/)\.[^\/\.]/g).test(item));
// Your code
});
You can use:
fs.readdir('/path/to/directory', function(err, list) {
list.forEach(function (filename) {
if(! /^\..*/.test(filename)) {
// display files
}
});
});
The promise way
const fs = require('fs').promises;
const readdir = path => {
return fs
.readdir(path)
.then(list => list.filter(item => !/(^|\/)\.[^/.]/g.test(item)));
};
I use junk package to ignore hidden files.
var fs = require('fs');
var junk = require('junk');
fs.readdir('path', function (err, files) {
console.log(files.filter(junk.not));
});
Using a regular expression like the solution provided may remove some filesystems but not all files. And using the "Junk" module is using regular expressions on some defined system filenames. So the solution is simply to write a personal script managing the different cases by adding cases as they are discovered.
Related
I'm building a node.js application in which I need to read all the folders in a parent folder and display their names in the order they were created on the page. Here is what I have so far:
function getMixFolders() {
const { readdirSync } = require('fs');
const folderInfo = readdirSync('./shahspace.com/music mixes/')
.filter(item => item.isDirectory() && item.name !== 'views');
return folderInfo.map(folder => folder.name);
}
As you can see, I haven't implemented sorting. This is because readdirSync doesn't return the information I need. The only things it returns are the name of the folder and something called the Symbol(type) (which seems to indicate whether its a folder or file).
Is there another method for getting more details about the folders I'm reading from the parent folder? Specifically the created date?
There is no super efficient way in nodejs to get a directory listing and get statistics on each item (such as createDate). Instead, you have to distill the listing down to the files/folders you're interested in and then call fs.statSync() (or one of the similar variants) on each one to get that info. Here's a working version that looks like it does what you want:
Get directory list using the {withFileTypes: true} option
Filter to just folders
Ignore any folders named "views"
Get createDate of each folder
Sort the result by that createDate in ascending order (oldest folders first)
This code can be run as it's own program to test:
const fs = require('fs');
const path = require('path');
const mixPath = './shahspace.com/music mixes/';
function getMixFolders() {
const folderInfo = fs.readdirSync(mixPath, { withFileTypes: true })
.filter(item => item.isDirectory() && item.name !== 'views')
.map(folder => {
const fullFolderPath = path.join(path.resolve(mixPath), folder.name);
const stats = fs.statSync(fullFolderPath);
return { path: fullFolderPath, ctimeMs: stats.ctimeMs }
}).sort((a, b) => {
return a.ctimeMs - b.ctimeMs;
});
return folderInfo;
}
let result = getMixFolders();
console.log(result);
If you wanted the final array to be only the folder names without the createDates you could add one more .map() to transform the final result.
When reading a directory, I currently have this:
fs.readdir(tests, (err, items) => {
if(err){
return cb(err);
}
const cmd = items.filter(v => fs.lstatSync(tests + '/' + v).isFile());
k.stdin.end(`${cmd}`);
});
first of all I need a try/catch in there around fs.lstatSync, which I don't want to add. But is there a way to use fs.readdir to only find files?
Something like:
fs.readdir(tests, {type:'f'}, (err, items) => {});
does anyone know how?
Starting from node v10.10.0, you can add withFileTypes as options parameter to get fs.Dirent instead of string.
// or readdir to get a promise
const subPaths = fs.readdirSync(YOUR_BASE_PATH, {
withFileTypes: true
});
// subPaths is fs.Dirent[] type
const directories = subPaths.filter((dirent) => dirent.isFile());
// directories is string[] type
more info is located at node documentation:
fs.Dirent
fs.readdirSync
fs.readdir
Unfortunately, fs.readdir doesn't have an option to specify that you're only looking for files, not folders/directories (per docs). Filtering the results from fs.readdir to knock out the directories is your best bet.
https://nodejs.org/dist/latest-v10.x/docs/api/fs.html#fs_fs_readdir_path_options_callback
The optional options argument can be a string specifying an
encoding, or an object with an encoding property specifying the
character encoding to use for the filenames passed to the callback. If
the encoding is set to 'buffer', the filenames returned will be
passed as Buffer objects.
Yeah fs.readdir can't do this currently (only read files or only read dirs).
I filed an issue with Node.js and looks like it may be a good feature to add.
https://github.com/nodejs/node/issues/21804
If your use case is scripting/automation. You might try fs-jetpack library. That can find files in folder for you, but also can be configured for much more sophisticated searches.
const jetpack = require("fs-jetpack");
// Find all files in my_folder
const filesInFolder = jetpack.find("my_folder", { recursive: false }));
console.log(filesInFolder);
// Example of more sophisticated search:
// Find all `.js` files in the folder tree, with modify date newer than 2020-05-01
const borderDate = new Date("2020-05-01")
const found = jetpack.find("foo", {
matching: "*.js",
filter: (file) => {
return file.modifyTime > borderDate
}
});
console.log(found);
I wanted to ask if anyone knows of a good solution for how to use node.js to look in a .scss file and grab all the classes listed and to then put them in either an object or an array?
The thing with this is that you are going to need the sass folder to be available to you server, this is not a recommended practice since you only publish the css compiled file, there is no need to also publish the dev assets.
However if you do so, you will need to read .scss file using node and from there use a regex to match the .class strings inside the file.
This will make the reading of the file:
var fs = require('fs');
function readSassFile () {
fs.readFile('./public/scss/components/_styles.scss', 'utf8', function (err, data) {
if (err) {
console.log(err);
return;
}
regexArray(data);
});
}
As you can see, at the end if the readFile retrieves the file with success, I'm calling a function regexArray() and sending the data of the file loaded.
In the regexArray function you need to define a regex to evaluate the string of the file loaded.
function regexArray (data) {
var re = /\.\S*/g;
var m;
var classArray = [];
while ((m = re.exec(data)) !== null) {
if (m.index === re.lastIndex) {
re.lastIndex++;
}
classArray.push(m[0]);
}
console.log(classArray);
}
the var re is the regular expression matching any string starting with a . and ending with a non-whitespace character which will match your css class names.
then we evaluate the m variable when is different from null and store the results in the array classArray, then you can log it to see the results.
I made the test with the path that is in the fs.readFile method, you can change it for you own path.
I have a file(data.file an image), I would like to save this image. Now an image with the same name could exist before it. I would like to overwrite if so or create it if it does not exist since before. I read that the flag "w" should do this.
Code:
fs.writeFile('/avatar/myFile.png', data.file, {
flag: "w"
}, function(err) {
if (err) {
return console.log(err);
}
console.log("The file was saved!");
});
Error:
[Error: ENOENT: no such file or directory, open '/avatar/myFile.png']
errno: -2,
code: 'ENOENT',
syscall: 'open',
path: '/avatar/myFile.png'
This is probably because you are trying to write to root of file system instead of your app directory '/avatar/myFile.png' -> __dirname + '/avatar/myFile.png' should do the trick, also check if folder exists. node.js won't create parent folder for you.
Many of us are getting this error because parent path does not exist. E.g. you have /tmp directory available but there is no folder "foo" and you are writing to /tmp/foo/bar.txt.
To solve this, you can use mkdirp - adapted from How to write file if parent folder doesn't exist?
Option A) Using Callbacks
const mkdirp = require('mkdirp');
const fs = require('fs');
const getDirName = require('path').dirname;
function writeFile(path, contents, cb) {
mkdirp(getDirName(path), function (err) {
if (err) return cb(err);
fs.writeFile(path, contents, cb);
});
}
Option B) Using Async/Await
Or if you have an environment where you can use async/await:
const mkdirp = require('mkdirp');
const fs = require('fs');
const writeFile = async (path, content) => {
await mkdirp(path);
fs.writeFileSync(path, content);
}
I solved a similar problem where I was trying to create a file with a name that contained characters that are not allowed. Watch out for that as well because it gives the same error message.
I ran into this error when creating some nested folders asynchronously right before creating the files. The destination folders wouldn't always be created before promises to write the files started. I solved this by using mkdirSync instead of 'mkdir' in order to create the folders synchronously.
try {
fs.mkdirSync(DestinationFolder, { recursive: true } );
} catch (e) {
console.log('Cannot create folder ', e);
}
fs.writeFile(path.join(DestinationFolder, fileName), 'File Content Here', (err) => {
if (err) throw err;
});
Actually, the error message for the file names that are not allowed in Linux/ Unix system comes up with the same error which is extremely confusing. Please check the file name if it has any of the reserved characters. These are the reserved /, >, <, |, :, & characters for Linux / Unix system. For a good read follow this link.
It tells you that the avatar folder does not exist.
Before writing a file into this folder, you need to check that a directory called "avatar" exists and if it doesn't, create it:
if (!fs.existsSync('/avatar')) {
fs.mkdirSync('/avatar', { recursive: true});
}
you can use './' as a prefix for your path.
in your example, you will write:
fs.writeFile('./avatar/myFile.png', data.file, (err) => {
if (err) {
return console.log(err);
}
console.log("The file was saved!");
});
I had this error because I tried to run:
fs.writeFile(file)
fs.unlink(file)
...lots of code... probably not async issue...
fs.writeFile(file)
in the same script. The exception occurred on the second writeFile call. Removing the first two calls solved the problem.
In my case, I use async fs.mkdir() and then, without waiting for this task to complete, I tried to create a file fs.writeFile()...
As SergeS mentioned, using / attempts to write in your system root folder, but instead of using __dirname, which points to the path of the file where writeFile is invoked, you can use process.cwd() to point to the project's directory. Example:
writeFile(`${process.cwd()}/pictures/myFile.png`, data, (err) => {...});
If you want to avoid string concatenations/interpolations, you may also use path.join(process.cwd(), 'pictures', 'myFile.png') (more details, including directory creation, in this digitalocean article).
I can't seem to get any search results that explain how to do this.
All I want to do is be able to know if a given path is a file or a directory (folder).
The following should tell you. From the docs:
fs.lstatSync(path_string).isDirectory()
Objects returned from fs.stat() and fs.lstat() are of this type.
stats.isFile()
stats.isDirectory()
stats.isBlockDevice()
stats.isCharacterDevice()
stats.isSymbolicLink() // (only valid with fs.lstat())
stats.isFIFO()
stats.isSocket()
NOTE:
The above solution will throw an Error if; for ex, the file or directory doesn't exist.
If you want a true or false approach, try fs.existsSync(dirPath) && fs.lstatSync(dirPath).isDirectory(); as mentioned by Joseph in the comments below.
Update: Node.Js >= 10
We can use the new fs.promises API
const fs = require('fs').promises;
(async() => {
const stat = await fs.lstat('test.txt');
console.log(stat.isFile());
})().catch(console.error)
Any Node.Js version
Here's how you would detect if a path is a file or a directory asynchronously, which is the recommended approach in node.
using fs.lstat
const fs = require("fs");
let path = "/path/to/something";
fs.lstat(path, (err, stats) => {
if(err)
return console.log(err); //Handle error
console.log(`Is file: ${stats.isFile()}`);
console.log(`Is directory: ${stats.isDirectory()}`);
console.log(`Is symbolic link: ${stats.isSymbolicLink()}`);
console.log(`Is FIFO: ${stats.isFIFO()}`);
console.log(`Is socket: ${stats.isSocket()}`);
console.log(`Is character device: ${stats.isCharacterDevice()}`);
console.log(`Is block device: ${stats.isBlockDevice()}`);
});
Note when using the synchronous API:
When using the synchronous form any exceptions are immediately thrown.
You can use try/catch to handle exceptions or allow them to bubble up.
try{
fs.lstatSync("/some/path").isDirectory()
}catch(e){
// Handle error
if(e.code == 'ENOENT'){
//no such file or directory
//do something
}else {
//do something else
}
}
Seriously, question exists five years and no nice facade?
function isDir(path) {
try {
var stat = fs.lstatSync(path);
return stat.isDirectory();
} catch (e) {
// lstatSync throws an error if path doesn't exist
return false;
}
}
Depending on your needs, you can probably rely on node's path module.
You may not be able to hit the filesystem (e.g. the file hasn't been created yet) and tbh you probably want to avoid hitting the filesystem unless you really need the extra validation. If you can make the assumption that what you are checking for follows .<extname> format, just look at the name.
Obviously if you are looking for a file without an extname you will need to hit the filesystem to be sure. But keep it simple until you need more complicated.
const path = require('path');
function isFile(pathItem) {
return !!path.extname(pathItem);
}
If you need this when iterating over a directory (Because that's how I've found this question):
Since Node 10.10+, fs.readdir has a withFileTypes option which makes it return directory entry fs.Dirent instead of strings. Directory entries has a name property, and useful methods such as isDirectory or isFile, so you don't need to call fs.lstat explicitly.
import { promises as fs } from 'fs';
// ./my-dir has two subdirectories: dir-a, and dir-b
const dirEntries = await fs.readdir('./my-dir', { withFileTypes: true });
// let's filter all directories in ./my-dir
const onlyDirs = dirEntries.filter(de => de.isDirectory()).map(de => de.name);
// onlyDirs is now [ 'dir-a', 'dir-b' ]
Here's a function that I use. Nobody is making use of promisify and await/async feature in this post so I thought I would share.
const promisify = require('util').promisify;
const lstat = promisify(require('fs').lstat);
async function isDirectory (path) {
try {
return (await lstat(path)).isDirectory();
}
catch (e) {
return false;
}
}
Note : I don't use require('fs').promises; because it has been experimental for one year now, better not rely on it.
The answers above check if a filesystem contains a path that is a file or directory. But it doesn't identify if a given path alone is a file or directory.
The answer is to identify directory-based paths using "/." like --> "/c/dos/run/." <-- trailing period.
Like a path of a directory or file that has not been written yet. Or a path from a different computer. Or a path where both a file and directory of the same name exists.
// /tmp/
// |- dozen.path
// |- dozen.path/.
// |- eggs.txt
//
// "/tmp/dozen.path" !== "/tmp/dozen.path/"
//
// Very few fs allow this. But still. Don't trust the filesystem alone!
// Converts the non-standard "path-ends-in-slash" to the standard "path-is-identified-by current "." or previous ".." directory symbol.
function tryGetPath(pathItem) {
const isPosix = pathItem.includes("/");
if ((isPosix && pathItem.endsWith("/")) ||
(!isPosix && pathItem.endsWith("\\"))) {
pathItem = pathItem + ".";
}
return pathItem;
}
// If a path ends with a current directory identifier, it is a path! /c/dos/run/. and c:\dos\run\.
function isDirectory(pathItem) {
const isPosix = pathItem.includes("/");
if (pathItem === "." || pathItem ==- "..") {
pathItem = (isPosix ? "./" : ".\\") + pathItem;
}
return (isPosix ? pathItem.endsWith("/.") || pathItem.endsWith("/..") : pathItem.endsWith("\\.") || pathItem.endsWith("\\.."));
}
// If a path is not a directory, and it isn't empty, it must be a file
function isFile(pathItem) {
if (pathItem === "") {
return false;
}
return !isDirectory(pathItem);
}
Node version: v11.10.0 - Feb 2019
Last thought: Why even hit the filesystem?
I could check if a directory or file exists using this:
// This returns if the file is not a directory.
if(fs.lstatSync(dir).isDirectory() == false) return;
// This returns if the folder is not a file.
if(fs.lstatSync(dir).isFile() == false) return;
Function that returns type
I like coffee
type: (uri)-> (fina) ->
fs.lstat uri, (erro,stats) ->
console.log {erro} if erro
fina(
stats.isDirectory() and "directory" or
stats.isFile() and "document" or
stats.isSymbolicLink() and "link" or
stats.isSocket() and "socket" or
stats.isBlockDevice() and "block" or
stats.isCharacterDevice() and "character" or
stats.isFIFO() and "fifo"
)
usage:
dozo.type("<path>") (type) ->
console.log "type is #{type}"