Have searched and have come up short on any solutions to this. I am relatively new to VB for the record. The variable minDate here is declared in the module outside of the procedure. I have tried declaring it inside the procedure, using set, let, and passing the argument as a range variable. Nothing.
Sub SocialTimeSinceFirstComment()
'
' SocialTimeSinceFirstComment Macro
'
Range("A11").Select
ActiveCell.FormulaR1C1 = "=MIN(SocialTransform!C[4])"
minDate = Application.WorksheetFunction.Min(Workbook.SocialTransform!.Range("c4").End(xlDown))
Apparently you have a worsheet named SocialTransform so use this:
Dim ws as Worksheet
set ws = ThisWorkbook.Worksheets("SocialTransform")
Dim minRange as Range
set minRange = ws.range(ws.Range("c4"), ws.Range("c4").End(xlDown))
minRange.Select 'use this when testing so you can see exactly what is included
minDate = Application.WorksheetFunction.Min(minRange)
Hopefully you have minDate declared as a date Dim MinDate As Date otherwise you'll just get a number; which could of course be transformed back to the corresponding date.
Also I might explain that the error you got was not because of minDate but because SocialTransform! is not an object of Workbook. You need to use Worksheets("SocialTransform")
EDIT: Actually you can use the code name to reference a sheet within the workbook like this: Debug.Print Sheet1.Name
In this example the user renamed the first sheet to "Data" and the Sheet1.Name will return "Data". The only way to change the code name is by change the "(Name)" property in the VBA editor window.
See: Worksheet.CodeName Property (Excel)
The error message is clear, and you don't "clearly have an object". (The compiler is almost always more aware of the code and syntax than we are, so if it says something is wrong you should probably believe it until you can prove otherwise.)
Workbook.SocialTransform!.Range in the last line of code you posted is invalid (WOrkbook.SocialTransform! isn't valid code the way you're using it), and therefore it doesn't return an object. However, you're referencing it as one, which generates the error.
It's valid inside quotes as you're using it in the line that precedes it.
Related
I'm creating small project in Excel, and because I'm a VBA newbie I do encounter a lot of problems that I'm trying to resolve on my own. However i can't cope with this:
I created Sub that accepts two objects: FormName and ControlName.
What i want it to do, is to loop through every Control in specific UserForm and populate every ListBox it encounters, from another ListBox.
I created this funny string comparison, because I need to operate on objects in order to execute the line with AddItem. This comparison actually works well, no matter how ridiculous it is. However when I launch the program, I got
Type Mismatch error
and to my surprise "Next" is being highlighted. I have no idea how to fix this, nor what is wrong.
Public Sub deploy(ByRef FormName As Object, ByRef ControlName As Object)
Dim i As Integer
Dim O As msforms.ListBox
i = 0
For Each O In FormName.Controls
If Left(FormName.Name & O.Name, 16) = Left(FormName.Name & ControlName.Name, 16) Then
O.AddItem (FormName.Podgląd.List(i))
i = i + 1
End If
Next
End Sub
I call this sub using:
Call deploy(UserForm1, UserForm1.ListBox3)
Above, I use Listbox3 because otherwise i got error saying that variable is not defined. However in my comparison I kinda override this.
If someone can explain in simple words, how to fix this type mismatch issue or how to write it in more elegant way
I have a VBA project that was working. I think the only change was to move a variable from local to global. The String is as a parameter to a sub. I am now getting a 'ny idea why? "Database" is one of the sheets in the workbook...
It worked before, and I just changed from local to global (Public Const) variable declarations. Hovering over the variables shows sh="Database" and rng="C9:AK47" as expected. Also that sheet and range is found in the active workbook.
--- error: The 'Set' line below errors out as 'subscript not in range'
--- question: Why? Sorry I'm not more clear, but it was working, and I just changed one thing...
''' globals
Option Explicit
Public Const gshDb As String = "Database"
Public Const grgDb As String = "C9:AK47"
''' call
breakFormulas True, gshDb, grgDb
''' sub
Sub breakFormulas(switch As Boolean, sh As String, rng As String)
Dim shRng As Range
Set shRng = Sheets(sh).Range(rng) ' yellow highlighted error - subscript out of range
This all works fine. I had a brain fart and the sheet name is "Dashboard" not "Database". The listed error told me 'check the sheet name' pretty clearly. And I did like 10 times, but I had to look 11 times to see it. I'm just dumb sometimes.
I'm leaving this posted here, but maybe it's best to delete. Code works just fine though, so maybe that will be helpful for someone, especially considering the troubleshooting listed in the OP.
I meet a problem which is probably very simple when I use a VBA function into a formula of a cell, I get the cell content "#NAME" (not found function ? while a macro using the function (for test) is executed normally (displays the wished content for the cell, the returned value by the function, which extracts the filename from a fullpath).
context :
I had by the past (more than 12 years ago) developed, may be 50,000, VBA instructions, using office2003.
Today I have to develop again some macros with Office365. So I have forgotten a lot since this time and some features can have changed which can become tricking (I need to read again my old soft to recall all my knowledge, but I have no access to for now)
The problem
I get the error "#name" when I use a function created into VBA
associated to the current workbook. No explanation, no help, I tried to
find something during several hours and I found nothing.
I have developed too for testing (see code) a "sub" which calls the function, and his execution is successful, but...
I cannot run the function from the formula of any cell.
I have tested the security parameters of macro and fully unlocked the execution temporarily, and too declare the local directory as confident area.
Note : this code is detailed as an example
The code
Public Function FNameOf(CellPointed As Range)
Dim CurCell As Range
Dim Text1 As String
Dim Text2 As String
Set CurCell = CellPointed
Text1 = CurCell.Value
Text2 = Mid$(Text1, InStrRev(Text1, "\") + 1, Len(Text1))
FNameOf = Text2
End Function
Sub DispFileName2()
Dim style, disp, titre
Dim Cursel As Range
'Cursel = ActiveCell
disp = FNameOf(ActiveCell)
style = vbOKOnly
titre = "Nom du fichier extrait du texte (fullpath) de la cellule courante"
MsgBox disp, style, titre
End Sub
If I submit the macro DispFileName2 if get the message with the file name extracted from the path which is the content of the current cell
If I set the formule of a cell :
=FNameOf(AnotherCell) 'which contains a fullpath to a file
I get always the error "#NOM" (in French version) or, I think so, "#NAME" (in english Version) as if the function name (ref) was unknown from the workbook (the code is not reached, a stop is set on the first instruction)
What can be the reason ?
Please place your user defined function somewhere in a module (neither in "ThisWorkbook" nor in the individual worksheet's code, e. g. "Feuil1").
You should add the result declaration As String also.
I understood the example is for reference only, but you may shorten it:
Public Function FNameOf(CellPointed As Range) As String
FNameOf = Mid(CellPointed.Value, InStrRev(CellPointed.Value, "\") + 1)
End Function
I just got the solution while reading in more details previous edited threads in several tabs.
It is explained into a remark of : thread 12351339
The text is :
Microsoft Excel Objects such as 'Sheet1' or 'ThisWorkbook' are
classes. I don't believe you can access Functions which you put in
these classes through a cell. You could access them in VBA e.g.
ThisWorkbook.Square2() but it's recommended to put all UDF's into as
standard module and not a worksheet module. – Eddie Sep 28 '17 at
13:49
By default the creation panel defines code associated to current worksheet, then the function is not visible for the worksheet while the sub is a macro of the worksheet.
I have created a module and the function has run immediately.
Best regards
Trebly
Note : I never met this problem of visibility before because the developments where since the beginning concerning VBA user classes and modules combining multiple Excel workbooks and Word and a Mail manager activeX and so on...
I keep the subject because of the explanations, code and keywords may be to find more easily the solution for anybody else.
i am trying t assign the values of a named range to an array of variants. I get an application or object defined error almost at the level of assignment code
Material = ThisWorkbook.Names("RMInStoreName").RefersToRange
i got this example from here and have used it before sucessfully.
I am still trying to figure out why this error is showing up, i seem to have run out of ideas, anybody can help me point in the right direction will realy save me alot
The code is below
Here is the code
Sub MonitorStore()
Dim ThreshHold As Variant, InStore As Variant, StatusReport As Variant
Dim Material As Variant 'is the name of the material
Status As Variant
'status is a variable which holds data on wether the user has seen msg and
'wants to supress msg
'the ThreshHold is the minimum allowed in store below which messages are firerd
'InStore is the volume of materials currently in store
'and be told of another error after solving error one, report all at once
Material = ThisWorkbook.Names("RMInStoreName").RefersToRange
ThreshHold = ThisWorkbook.Names("RMThreshHold").RefersToRange
InStore = ThisWorkbook.Names("RMInStore").RefersToRange
Status = ThisWorkbook.Names("RMStatus").RefersToRange
'other code.............
'dont expect error from unexecuted code
End Sub
Thanks for help
Stephen
The most likely reason is that you don't have all of the named ranges defined in the workbook.
You can verify the named ranges using the Formula tab.
Formula --> Name Manager
RefersToRange will return a range object. Its the value you are after then:
Material = ThisWorkbook.Names("RMInStoreName").RefersToRange.Value
or you can use:
Material = Evaluate("RMInStoreName")
or:
Material = Evaluate(ThisWorkbook.Names("RMInStoreName").RefersTo).Value
I have a VBA function within a spreadsheet which operates on another spreadsheet that is opened in an earlier stage of my macro. The macro used to work fine but just recently has started causing a 1004 error ("Unable to get RoundDown property of the WorksheetFunction class") when it runs.
I believe I understand what the error would be caused by (a problem running RoundDown) but I cannot see why it is getting triggered in my macro and the odd part is that when I go into Debug mode and step through the code in the VBE the error does not recur (despite nothing obviously changing).
Does anyone have a similar experience of this sort of error occuring inconsistently and know what I could do to resolve it?
I'm reasonably VBA/Excel-savvy, but any suggestions on further steps to diagnose it would be appreciated. I am wondering if there is some issue with the opened spreadsheet not being ready but I cannot see how.
The code is here. The error occurs on the line marked with a comment.
Public Function GetDatesA(sWorkbookname As String, sSheetname As String, sCell As String) As Variant
Dim vDateList() As Variant
Dim currentCell As Range
Dim n As Long
Set currentCell = Workbooks(sWorkbookname).Worksheets(sSheetname).Range(sCell)
n = 0
Do
If Trim(currentCell.Value) = "" Then
Exit Do
Else
ReDim Preserve vDateList(0 To 1, 0 To n)
vDateList(0, n) = WorksheetFunction.RoundDown(currentCell.Value, 0) 'error occcurs on this line
vDateList(1, n) = currentCell.Column
'Debug.Print currentCell.Value
End If
Set currentCell = currentCell.Offset(0, 1)
n = n + 1
Loop While currentCell.Column < XL_LAST_COLUMN
GetDatesA = vDateList
End Function
Other details are:
Excel version: 2010
File being opened resides locally on my C: drive; my macro is in a spreadsheet on the network
File format for both files is .xls (i.e. Excel 2003) - I don't have the option of changing this
Windows 7 (not that I think it would be relevant)
Two points I've tried already are:
Substitute a different worksheet function (e.g. Min(currentCell)) and that also causes the same problem
Having the file open already seems to stop the problem - I wonder if there is some way that the workbook which is being opened (rather than my main workbook with the macro in it) is not enabled for macros and this is interfering. But even if this is the cause I'm not sure how to get around it!
Any ideas?
This error occurs often when any argument passed to the worksheet function is not of the correct type or simply doesn't make sense.
For example, I've had this problem when calling WorksheetFunction.Asin with an argument bigger than 1. In your case, I'd guess currentCell.Value is a non-numeric value or one not according to your region settings regarding numbers.
Yes, the error message is really misguiding.
I got the "Unable to get * property of WorksheetFunction Class" error using Transpose, MMult,MDterm, and MInverse functions.
I was able to get my code to run by putting "Option Base 1" in the Declarations (before the actual code) section of the particular Module in the Editer.
Excel assumes "Option Base 0" which will add an extra row and column of empty cells. This will cause the error to occur and isn't immediately obvious to see.
I have come accross this before, and for me it was becase the criteria range made no sense, as Andre said above.
See example formula below:
.Cells(11, i).Formula = Application.WorksheetFunction.CountIfs(Sheets("Sheet1").Range("AC8:C" & n), "S")
Have a look at the Range... it makes no sense. Amended the range from "AC8:C" to "AC8:AC" and it will work perfectly