When I run the BASH script from the command line, it is executed.
When I try to run it as a cron task, it fails. By an exception method, I found a problem. It consists in the fact that the "which iptables" command returns an empty string. This happens with all the programs that I try to find in the "/sbin" directory.
Example:
# crontab -e
* * * * * /root/test.sh >> /root/test.log 2>&1
test.sh
#!/bin/bash
IPT=$(which iptables);
echo ${IPT} >> /root/test.log
But in test.log written empty string.
Tested on Ubuntu 16.04 and Debian 8.
It's not related to privileges.
which looks for the command in $PATH. cron scripts have a limited path, that doesn't include iptables, so it's not found.
$ /usr/bin/which iptables
/sbin/iptables
$ PATH=/bin:/usr/bin /usr/bin/which iptables
$ echo $?
1
When you have a limited path, it will return a empty string (on my other machine it reports that no iptables in (/usr/bin:/bin) so YMMV) and exit with non-zero code.
if you do something like echo $PATH >> /root/test.log you will see that cron has a path with just /usr/bin and /bin
You have to either set the $PATH to contain the iptables location, or use full path when calling iptables
I have a bash script which I want to run as a cron job.
It works fine except one command.
I redirected its stderr to get the error and found out that the error it shows was the command not recognized.
It is a root crontab.
Both the current user and root execute the command successfully when I type it in the terminal.
Even the script executes the command when I run it through the terminal.
Startup script :
#!/bin/bash
sudo macchanger -r enp2s0 > /dev/null
sudo /home/deadpool/.logkeys/logger.sh > /dev/null
logger.sh :
#!/bin/bash
dat="$(date)"
echo " " >> /home/deadpool/.logkeys/globallog.log
echo $dat >> /home/deadpool/.logkeys/globallog.log
echo " " >> /home/deadpool/.logkeys/globallog.log
cat /home/deadpool/.logkeys/logfile.log >> /home/deadpool/.logkeys/globallog.log
cat /dev/null > /home/deadpool/.logkeys/logfile.log
cat /dev/null > /home/deadpool/.logkeys/error.log
logkeys --start --output /home/deadpool/.logkeys/logfile.log 2> /home/deadpool/.logkeys/error.log
error.log
/home/deadpool/.logkeys/logger.sh: line 10: logkeys: command not found
Remember cron runs with a different environment then your user account or root does and might not include the path to logkeys in its PATH. You should try the absolute path for logkeys (find it with which logkeys from your user) in your script. Additionally I recommend looking at this answer on serverfault about running scripts like they are running from cron when you need to find out why it's working for you and not in a job.
I have a script that checks if the PPTP VPN is running, and if not it reconnects the PPTP VPN. When I run the script manually it executes fine, but when I make a cron job, it's not running.
* * * * * /bin/bash /var/scripts/vpn-check.sh
Here is the script:
#!/bin/sh
/bin/ping -c3 192.168.17.27 > /tmp/pingreport
result=`grep "0 received" /tmp/pingreport`
truncresult="`echo "$result" | sed 's/^\(.................................\).*$$'`"
if [[ $truncresult == "3 packets transmitted, 0 received" ]]; then
/usr/sbin/pppd call home
fi
finally i found a solution ... instead of entering the cronjob with
crontab -e
i needed to edit the crontab file directly
nano /etc/crontab
adding e.g. something like
*/5 * * * * root /bin/bash /var/scripts/vpn-check.sh
and its fine now!
Thank you all for your help ... hope my solution will help other people as well.
After a long time getting errors, I just did this:
SHELL=/bin/bash
PATH=/bin:/sbin:/usr/bin:/usr/sbin
* * * * * /bin/bash /home/joaovitordeon/Documentos/test.sh
Where test.sh contains:
#!/bin/bash
/usr/bin/python3 /home/joaovitordeon/Documentos/test.py;
In my case, the issue was that the script wasn't marked as executable. To make sure it is, run the following command:
chmod +x your_script.sh
If you're positive the script runs outside of cron, execute
printf "SHELL=$SHELL\nPATH=$PATH\n* * * * * /bin/bash /var/scripts/vpn-check.sh\n"
Do crontab -e for whichever crontab you're using and replace it with output of the above command. This should mirror most of your environment in case there is some missing path issue or something else. Also check logs for any errors it's getting.
Though it definitly looks like the script has an error or you messed something up when copying it here
sed: -e expression #1, char 44: unterminated `s' command
./bad.sh: 5: ./bad.sh: [[: not found
Simple alternate script
#!/bin/bash
if [[ $(ping -c3 192.168.17.27) == *"0 received"* ]]; then
/usr/sbin/pppd call home
fi
Your script can be corrected and simplified like this:
#!/bin/sh
log=/tmp/vpn-check.log
{ date; ping -c3 192.168.17.27; } > $log
if grep -q '0 received' $log; then
/usr/sbin/pppd call home >>$log 2>&1
fi
Through our discussion in comments we confirmed that the script itself works, but pppd doesn't, when running from cron. This is because something must be different in an interactive shell like your terminal window, and in cron. This kind of problem is very common by the way.
The first thing to do is try to remember what configuration is necessary for pppd. I don't use it so I don't know. Maybe you need to set some environment variables? In which case most probably you set something in a startup file, like .bashrc, which is usually not used in a non-interactive shell, and would explain why pppd doesn't work.
The second thing is to check the logs of pppd. If you cannot find the logs easily, look into its man page, and it's configuration files, and try to find the logs, or how to make it log. Based on the logs, you should be able to find what is missing when running in cron, and resolve your problem.
Was having a similar problem that was resolved when a sh was put before the command in crontab
This did not work :
#reboot ~myhome/mycommand >/tmp/logfile 2>&1
This did :
#reboot sh ~myhome/mycommand >/tmp/logfile 2>&1
my case:
crontab -e
then adding the line:
* * * * * ( cd /directory/of/script/ && /bin/sh /directory/of/script/scriptItself.sh )
in fact, if I added "root" as per the user, it thought "root" was a command, and it didn't work.
As a complement of other's answers, didn't you forget the username in your crontab script ?
Try this :
* * * * * root /bin/bash /var/scripts/vpn-check.sh
EDIT
Here is a patch of your code
#!/bin/sh
/bin/ping -c3 192.168.17.27 > /tmp/pingreport
result=`grep "0 received" /tmp/pingreport`
truncresult=`echo "$result" | /bin/sed 's/^\(.................................\).*$/\1/'`
if [[ $truncresult == "3 packets transmitted, 0 received" ]]; then
/usr/sbin/pppd call home
fi
In my case, it could be solved by using this:
* * * * * root ( cd /directory/of/script/ && /directory/of/script/scriptItself.sh )
I used some ./folder/-references in the script, which didn't work.
The problem statement is script is getting executed when run manually in the shell but when run through cron, it gives "java: command not found" error -
Please try below 2 options and it should fix the issue -
Ensure the script is executable .If it's not, execute below -
chmod a+x your_script_name.sh
The cron job doesn’t run with the same user with which you are executing the script manually - so it doesn't have access to the same $PATH variable as your user which means it can't locate the Java executable to execute the commands in the script. We should first fetch the value of PATH variable as below and then set it(export) in the script -
echo $PATH can be used to fetch the value of PATH variable.
and your script can be modified as below - Please see second line starting with export
#!/bin/sh
export PATH=<provide the value of echo $PATH>
/bin/ping -c3 192.168.17.27 > /tmp/pingreport
result=`grep "0 received" /tmp/pingreport`
truncresult="`echo "$result" | sed 's/^\(.................................\).*$$'`"
if [[ $truncresult == "3 packets transmitted, 0 received" ]]; then
/usr/sbin/pppd call home
fi
First of all, check if cron service is running. You know the first question of the IT helpdesk: "Is the PC plugged in?".
For me, this was happening because the cronjob was executing from /root directory but my shell script (a script to pull the latest code from GitHub and run the tests) were in a different directory. So, I had to edit my script to have a cd to my scripts folder. My debug steps were
Verified that my script run independent of cron job
Checked /var/log/cron to see if the cron jobs are running. Verified that the job is running at the intended time
Added an echo command to the script to log the start and end times to a file. Verified that those were getting logged but not the actual commands
Logged the result of pwd to the same file and saw that the commands were getting executed from /root
Tried adding a cd to my script directory as the first line in the script. When the cron job kicked off this time, the script got executed just like in step 1.
it was timezone in my case. I scheduled cron with my local time but server has different timezone and it does not run at all. so make sure your server has same time by date cmd
first run command env > env.tmp
then run cat env.tmp
copy PATH=.................. Full line and paste into crontab -e, line before your cronjobs.
try this
/home/your site folder name/public_html/gistfile1.sh
set cron path like above
Apologies for the confusing Question title. I am trying to launch an interactive bash shell from a shell script ( say shel2.sh) which has been launched by a parent script (shel1.sh) in a sudo-ed environment. ( I am creating a guided deployment
script for my software which needs to be installed as super-user , hence the sudo, but may need the user to access the shell. )
Here's shel1.sh
#!/bin/bash
set -x
sudo bash << EOF
echo $?
./shel2.sh
EOF
echo shel1 done
And here's shel2.sh
#!/bin/bash
set -x
bash --norc --verbose --noprofile -i
echo $?
echo done
I expected this to launch an interactive bash shell which waits for my input before returning to shel1.sh. This is what I see:
+ ./shel1.sh
+ sudo bash
0
+ bash --norc --verbose --noprofile -i
bash-4.3# exit
+ echo 0
0
+ echo done
done
+ echo shel1 done
shel1 done
The bash-4.3# calls an exit automatically and quits. Interestingly if I invoke the bash shell with -l (or --login) the automatic entry is logout !
Can someone explain what is happening here ?
When you use a here document, you are tying up the shell's -- and its spawned child processes' -- standard input to the here document input.
You can avoid using a here document in many situations. For example, replace the here document with a single-quoted string.
#!/bin/bash
set -x
sudo bash -c '
# Aside: How is this actually useful?
echo $?
# Spawned script inherits the stdin of "sudo bash"
./shel2.sh'
echo shel1 done
Without more details, it's hard to see where exactly you want to go with this, but most modern Linux platforms have package managers which allow all kinds of hooks for installation, so that you would typically not need to do this sort of thing. Have you looked into that?
I created a shell script to check a tomcat instance status. If the instance is not started, then start it:
if [ `ps -ef | grep 'travelco' | grep -v grep | wc -l` -eq 0 ];then
sudo /home/q/tools/bin/restart_tomcat.sh /home/www/travelco/
else
echo 'travelco started'
fi
Then I tested the script and it worked well. But after I added it as a crond job, this script didn't work as expected.
I used crontab -e, and added
*/1 * * * * /home/yuliang.jin/travelcoCheck.sh
After that, even though I can see the script executed in the crontab log(sudo tail -f /var/log/cron), the tomcat instance was not started. Why?
There's a sudo in your script but are you sure that your current user has the permission to execute /home/q/tools/bin/restart_tomcat.sh without password authentication?
You should add the script to /etc/sudoers to allow your current user to execute the script without password, or you can just sudo crontab -e to run the script as root (and don't forget to delete sudo in your script if you do so).
If there is any other option, don't sudo in a cron job.
travelcoCheck.sh will be matched by the grep travelco and is not cancelled by the grep -v grep, so wc -l will be at least 1 always. So restart_tomcat.sh will not run.
(As a side note: whether or not your ps-parsing stack gets caught by ps is something of a dark art and is full of corner cases and race conditions and generally difficult to get to work right. Stuff like this is why dbus was invented.)