How do I made path a like api.get('/view/:search/:userid', search) work with /view//12, giving params.search an empty value?
Can you please try the following:
api.get('/view/:search?/:userid', search)
or if you define a new route
api.get('/view//:userid', search)
Related
I am building an online store and I'm using category paths like this /electronics/phones/samsung in my models.
What I want to do is have a route like this /categories/electronics/phones/samsung that retrieves all items that matches this category path.
I have implemented the way to actually find the items given the path but how would I go about parsing this as URL?
I'm using express framework for Node JS
If you're using MongoDB as a Database try to order routes as it goes in the database. For example you have in DB:
"product": {"product1": { "product2": {...} }}
Yout route should be like /product/product1/product2
Go with: req.originalUrl
Then parse it like:
req.originalUrl.split("/")
and you'll get array:
["","categories","electronics","phones","Samsung"]
In my MVC project I have a route like this:
routes.Add("MyRoute", new MyRoute("{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = UrlParameter.Optional }));
I also have some bundles (showing only constructor with URL here):
new Bundle("~/Scripts/companyname", typeof(JsMinify));
new Bundle("~/Content/themes/companyname/css", typeof(Microsoft.Web.Optimization.CssMinify));
new Bundle("~/Content/skin/css", typeof(Microsoft.Web.Optimization.CssMinify));
new Bundle("~/Content/companyname_css", typeof(Microsoft.Web.Optimization.CssMinify));
new Bundle("~/Content/print_css", typeof(Microsoft.Web.Optimization.CssMinify));
I want those bundles to not be matched by "MyRoute". How can I achieve that?
Found it. This is what RouteCollection.IgnoreRoute is for. I do find the documentation in this area pretty scarce, so I'll add a few details here.
routes.IgnoreRoute("Content/{*pathInfo}");
routes.IgnoreRoute("Scripts/{*pathInfo}");
Those lines tell the routing system to ignore URL:s that start with Content/ and Scripts/ respectively, and has "anything" after the /. The asterisk * in {*pathInfo} means that the pathInfo token should be assigned the remainder of the URL.
I have not been able to determine if the name pathInfo matters, or could be anything, but it appears that the pattern needs a placeholder there, with the leading asterisk, to match anything after the /.
Here is below my code of route:-
app.get('/server/lead/get/:id?', leadCtrl.get);
app.get('/server/lead/filter/:filterQuery', leadCtrl.get);
As you see above i am using different route to access same controller method leadCtrl.get.
Now, i want something like route app.get('/server/lead/get/:id?:filter?', leadCtrl.get);. So, i can get params either req.params.id or req.params.filter but only one at a time.
What you asked in the question is not possible in the form that you describe it.
Now, i want something like route
app.get('/server/lead/get/:id?:filter?', leadCtrl.get);. So, i can get
params either req.params.id or req.params.filter but only one at a
time.
Your router would have no way to differentiate those two parameters. If it got a request to /server/lead/get/X then what is X? A filter or an ID?
Your options
You have few solutions here:
You can either keep using two routes like you did before.
You can use a common parameter for both cases as Robert explained in the comments.
Or you can use what seems to me the perfect solution for your use case - named query parameters - just use a route /server/lead/get and use query parameters to pass id and the filter.
Example URLs:
/server/lead/get?id=xxx
/server/lead/get?filterQuery=xxx
You will only have to make sure in your handler that only one of those two are set at a time with something like:
if (req.query.id && req.query.filterQuery) {
// respond with error
}
You can even mix the two if you have app.get('/server/lead/get/:id?') route you can have the id in the route and filterQuery as a query parameter. Now the URLs would be:
/server/lead/get/xxx (for id)
/server/lead/get?filterQuery=xxx (for filter)
For more info see: http://expressjs.com/en/api.html#req.query
Better way
If you follow some REST conventions then you can use:
app.get('/server/lead/:id') for one object with id (not optional)
app.get('/server/lead') for a list of objects (with optional filterQuery passed as a query parameter)
That way you would always know that when you access:
/server/lead/xxx - then it's one object with ID = xxx
/server/lead - then it's a list of any objects
/server/lead?filterQuery=xxx - then it's a list of objects that match the query
If you follow the REST conventions for things like this instead of inventing your own, it would be much easier for you to design the routes and handlers, and it would be much easier for other people to use your system.
You may also want to use plural /server/leads instead of /server/lead which is common with REST. That way it will be more obvious that leads is a list and leads/id is one of its elements.
For more info see:
https://en.wikipedia.org/wiki/Representational_state_transfer
http://www.restapitutorial.com/lessons/whatisrest.html
https://spring.io/understanding/REST
You have to realize that the following two routes match exactly the same:
app.get('/server/lead/get/:id?', leadCtrl.get);
app.get('/server/lead/get/:filter?', leadCtrl.get);
Express doesn't care about how you name the placeholders, so any requests for /server/lead/get/SOMEVALUE will always match the first (the one with :id).
You can add a distinction yourself, by only allowing a parameter to match a particular regular expression. From your code, it looks like :id should match MongoDB ObjectId's, so you can create a specific match for those:
app.get('/server/lead/get/:id([a-fA-F0-9]{24})?', leadCtrl.get);
If SOMEVALUE matches an ObjectId, it will call leadCtrl.get and populate req.params.id. If you also add another router for "the rest", you can also cover the req.params.filter case:
app.get('/server/lead/get/:filter?', leadCtrl.get);
As an aside: you're saying that you're passing JSON to the "filter" routes, in the URL. I would strongly suggest using a POST route for that, and post the JSON as request body content.
How to put checks on pattern in Express?
I have a url:
http://localhost:3030/total?id=1234#12
I get the complete url by req.url which contains:
/total?id=1234#12
Is there any string pattern match syntax in Express, like I would like to separate the /total?id= part.
It looks like you're looking for req.query. That will give you an object based on the keys and values in your query string.
You can use both req.path and req.query to separate /total?id=1234#12.
req.path will give you "/total"
req.query.id will give you "1234#12"
I need to redirect the URLs like this http://mysite.com/store/store-name to http://mysite.com/stores/products/store-id. Note that i need to get the store id from the database. So is it possible to do db operations in routes.php?
And in documentation the syntax is give as $route['store/:any']. How to get the value of second parameter here which is mentioned as :any.
There's not really any good nor simple way of running database queries through the routes. You can however have in the beginning of the controller function a validation.
I asume your store-name is some sort of slug for the product? Basicly you can validate if value is numeric or not, and if not find by slug and then redirect.
config/routes.php
$route["store/(.*)"] = 'stores/products/$1';
/* () and $1 together passes the values */
controllers/stores.php
/* Class etc. */
function products($mix) {
if (is_numeric($mix))
$int_id = $mix;
else {
$row = $this->get_where('products', array('slug' => $mix))->row();
$this->load->helper('url');
redirect("stores/products/{$row->id}");
}
/* Do stuff with the $int_id */
}
This asumes that you have:
A table named products
A column named id that's your products id
A column named slug that that's based on your store-name
I may be a little late to the party, but I may have an alternative suggestion.
I use the following for my routes:
http://mysite.com/store/1/store-name
Reason being... Based on your method, if you create
http://mysite.com/store/store-name
but then after a period of time (of which no doubt Google has indexed your page) you decide for what ever reason you have to change the name of the store to "Wonderful store name", you would naturally change your link to
http://mysite.com/store/wonderful-store-name
Which kills your SEO and any index links.
My solution of using http://mysite.com/store/1/store-name means that you can change store-name to anything you want, but it will always reference 1 meaning the user will still see the related page.
Anything is possible with CodeIgniter routes. Its all in the way you code it. Routing in CI is really flexible. You can use regular expressions besides the standard CI wildcards (:any)(:num). You can even add prefixes or suffixes to the path variables if you have to like:
$route['store/(:any)'] = "redircontroller/redirfunction/$1";
// for instance the namelookup method of the mystores controller
$route['stores/products/(:any)'] = "mystores/namelookup/$1";
You get the second parameter(and third and so on) by defining the variables in your route value which get passed to the controller method you define. If 'products' in you new url is also a variant you should start your wildcard expression there instead. You could also pull parameters out of the url using the URI class ($this->uri->segment(n)).
You don't, however, do database operations in routes.php. You do your database operations in the controller where you route to. My guess is that you'll have to match the store id using whatever is used in the url in a query.
In any case the path that you are using the routes file for is the path the user will see. To do the redirect you have to accept the original path and then redirect the user to the new path like so:
// in some controller that's attached to the original url
public function redirfunct($var){
$this->load->helper('url');
redirect(base_url('stores/products/' . $var));
}
I hope this helps you.
Yes that is easy, you only need to show the ID instead of the name,
you must be doing like storeName> Click to view details
Make it as
storeId> Click to view details
and when you are passing the parameter to the database, change the check of mysql, change it to id instead of name , that can be some like
" select yourRequiredColumn from table_name where id=".parameter."
Thanks