I have the next command to delete files which are large than 100KB:
find . -size +100k -delete
I want that it doesn't delete 3 files: a.html b.txt and c.html
How can I do it?
This should make it:
find . -size +100k ! -name "a.html" ! -name "b.html" ! -name "c.html" -delete
This should work:
find . -size +100k ! -regex "^\./[abc]\.html$" -delete
Add -maxdepth 1 is you want to perform deletion in current directory only.
Check out this page : http://www.cyberciti.biz/faq/find-command-exclude-ignore-files/
At the end, they say this:
Find all .dot files but ignore .htaccess file:
$ find . -type f \( -iname ".*" ! -iname ".htaccess" \)
This should do the trick for you, just substitude the -iname ".htaccess" for the name of your files :)
Hope it helps!
Related
I am trying to write a command to remove recursively several files with different extensions (*.extension1, *.extension2 etc) from the current directory and all its related sub-directories.
So far I got this command from another post but I couldn't workout how to adapt it to more than one file in the same command line:
find . -name "*.extension1" -type f -delete
Is it as simple as below?
find . -name "*.extension1";"*.extension2" -type f -delete
Just as a side note, these are all output files that I do not need, but not all are necessarily always output so some of the extensions might not be present. This is just as a general clean-up command.
find . \( -name "*.extension1" -o -name "*.extension2" \) -type f -delete
find Documents ( -name ".py" -o -name ".html" ) -exec file {} \;
OR
find . -regextype posix-egrep -regex ".*\.(extension1|extension2)$" -type f -delete
Just add more options. A regex solution can also apply but this one's better and safer.
find . \( -name '*.ext1' -or -name '*.ext2' \) -type f -delete
Edit: You probably need -or as well. Before deleting, test it first without the -delete option. (2) Added a pair of () as suggested by gniourf_gniourf.
Maybe regexp will help you
find . -regextype posix-awk -regex "(.*.ext1|.*.ext2)" -type f -delete
Another solution using rm:
rm -rf ./**/*.{txt,nfo,jpg,jpeg,png,exe,url}
If you want to delete other files too for e.g. those starting with sample. just add that too:
rm -rf ./**/*.{txt,nfo,jpg,jpeg,png,exe,url} ./**/*/sample.*
This simple command will delete all the files with extension1 and extension2 recursively in that directory.
rm find . -name *.extension1 -o -name *.extentions2
I'm using this command to go through all files, directories and subdirectories to change any mentions of oldurl.com to newurl.org:
find . -type f -name '*.php' -exec sed -i 's|oldurl.com|newurl.org|g' {} +
It works fine, however, I need to exclude three sub-directories from ANY CHANGES: /cache, /archive and /etc as changing the urls with the above command in these paths breaks other scripts.
Haven't had much luck finding an answer... Is it even possible?
Many thanks for any suggestions/help.
Use finds -not Option:
find . -type f -name '*.php' -not \( -path './etc/*' -o -path './cache/*' -o -path './archive/*' \) -exec sed -i 's|oldurl.com|newurl.org|g' {} \;
Im trying to find all files modified during de last 24 hours in /var/www/vhost directory.
That is working ok with the find command, then, I want to filter the list because i don't want jpg files, jpeg files and so on.
Now i have this and it's working ok:
find /var/www/vhosts/ -ctime 0 -type f | grep -ve ".jpg$" | grep -ve ".jpeg"
I guess (and know) there's a better solution to my problem.
Any help?
change your find command itself to
find /var/www/vhosts/ -not \( -name "*.jpeg" -o -name "*.jpg" \) -ctime 0 -type f
You can do it all with one find command:
find /var/www/vhosts -ctime 0 -type f \! -iname \*.jpg \! -iname \*.jpeg
Use -regex and ! (negation):
find $DIR -regextype posix-extended ! -regex '.*\.(gif|jpg|pdf|png)$'
In the following command i want to search only only the directories which are non hidden how can i do this using the following command .Iwant to ignore hidden directories while searching the log file
find /home/tom/project/ -name '.log.txt'
ls /home/tom/project/
dir1
dir2
.backup
.snapshot/
.ignore/
Try
find /home/tom/project -type d -name '.*' -prune -o -name .log.txt -print
This will find all files but ignore those that start with a dot so hidden files.
find /home/tom/project/ -type f \( -iname ".log.txt" ! -iname ".*" \)
EDIT:
If the above those not work, this should do the trick. It has a better regex.
find /home/tom/project/ \( ! -regex '.*/\..*' \) -type f -name ".log.txt"
EDIT2:
The following will exclude hidden folders but will search for the hidden files that have the requested pattern:
find /home/tom/project/ \( ! -regex '.*/\..*/..*' \) -type f -name ".log.txt"
EDIT3:
The grep solution :) if this doesn't work i'm lost :)
find /home/tom/project/ \( ! -regex '.*/\..*/..*' \) -exec grep -l ".log.txt" {} \;
EDIT4:
Have you tried the simple solutions?
find /home/tom/project/ -type f -name ".log.txt"
OR
find /home/tom/project/ -type f -name "*" -exec grep -l ".log.txt" {} \;
I use Emacs and it sometimes makes backup for edited files. After a few days, I would have a lot of backup files whose name ends with a tilde.
Is there a way to find these files and delete them at once?
I tried this:
find "*" -type f -iname *~
But it doesn't work. I want the command to work recursively – something like ls -alR.
You need to escape from the shell. And you need to specify search path, not *
find . -type f -name '*~'
To delete the files:
find . -type f -name '*~' -exec rm -f '{}' \;
You can do something like that :
find . -type f -name '*~' -delete
If you want to delete also #*# file :
find . -type f -name '*~' -o -name '#*#' -delete
You can print all deleted files with "-print":
find . -type f -name '*~' -delete -print
Another way is by using grep.
lnydex99uhc:javastuff user$ ls
Permutation.java VigenereCipher.java VigenereCipher.java~
lnydex99uhc:javastuff user $ find . | grep .~$
./VigenereCipher.java~
You can also pass any command you want like this :
lnydex99uhc:javastuff zatef$ rm $(find . | grep .~$)