I have a column of numbers which varying in length (some of the numbers are 9 characters, while others are 7). I need them to all be 9 characters so I want to add 0s in front of the numbers. For example, if I have the number 0294843 which is 7 characters long, I want to add 2 zeros in the front, so 000284843. Since every number has different lengths (some are 9, 8, 7, 6, etc.) I'd like to find a function that will automatically add zeros dependent on the length. So far I have this:
=IF(LEN(D5)<9, D5, ...)
Where the ... is what I'm not sure what to put in. Thanks!
=TEXT(A1,"000000000")
Where A1 is the cell to pad and the number of 0s is the length you want.
There's no need to use formulas for formatting.
Simply use a custom format. From here:
When you want to display leading zeros for a fixed-length number,
create a custom format with the same number of zeros (0) as digits
that you want to display. For example, if you want to display a
fixed-length number with five digits, create a custom number format
with five zeros.
In your case the custom format would be 000000000
Related
I want to convert a series of numbers < 1000 into binary to do some bitwise analysis in Excel
But the DEC2BIN function in Excel doesn't seem to allow me to specify leading zeroes for the smaller numbers. The BASE(x,2) functionn will handle the larger numvbers better than DEC2BIN, but still drops leading zeroes of the smaller numbers.
=BASE(999,2) returns 1111100111 but =BASE(511,2) returns 111111111
I would really like it to return 0111111111
Is it possible to do that in Excel?
You can just specify the minimum number of digits when using Base e.g.
=BASE(511,2,10)
Since your numbers are all less than 1000, 10 digits are sufficient.
I have a column of data with numbers stored in text.
The numbers look like this: 735999114002665788
If I select any cell in this column and refer to it with the function =value(), the number shows up as 735999114002665000.
As you can see the last three digits are 0. This happens all the time with numbers this long - but NOT with numbers containing less digits.
Am I trying to convert a number that's too large or what's up? Please help! I've tried every form of text-to-number method with identical results :(
Excel's number precision is 15 digits, which is why you're losing the last three digits when converting your 18 character string
https://support.office.com/en-us/article/excel-specifications-and-limits-1672b34d-7043-467e-8e27-269d656771c3#ID0EBABAAA=Excel_2016-2013
Excel only allows a maximum of 15 digits of precision for each number in a cell. The reason why this number:
735999114002665788
becomes this:
735999114002665000
is because Excel is choosing to retain the 15 most significant digits in the number. This means that the ones, tens, and thousands digits are being tossed out.
By the way, this question has been asked before on SuperUser, and you can read about it here:
https://superuser.com/questions/437764/why-is-excel-truncating-my-16-digit-numbers
I have a large excel file the contains many way-points in Latitude and Longitude in the degree and minutes. My problem is that the numbers can't be rounded and must stay exactly the same, but the last 2 numbers need to be removed (in most cases)
I was wondering if there is a formula that would only allow three characters past the decimal. This is how most my numbers look.
26° 17.82964
However Sometimes they look like this
26° 9.82
I know I can format the cell as a number and set the decimal place to 3, however when I copy and paste it doesn't stay the same.
This formula will truncate (It does not Round) the numbers and give all if less:
=MID(A1,1,FIND(".",A1)+3)
This formula will round, but it will always fill out the numbers to three decimal places (I am aware the OP did not want rounding, this is for others that may want it.):
=LEFT(A1,FIND(" ",A1))&TEXT(ROUND(--MID(A1,FIND(" ",A1),LEN(A1)),3),"0.000")
I know how to isolate the decimal using the TRUNC() function, as well as taking the original value and subtracting this truncated part.
And I can then multiply to get whole number.
But that only works if all my decimals are the same place. I want something that will get me the amount after the decimal point as a whole number, regardless of how many places.
eg: 12.2 would return 2
12.21 would return 21
With data in A1, consider:
=IF(ISERROR(FIND(".",A1)),A1,--MID(A1,(FIND(".",A1)+1),9999))
Naturally leading zeros in the output are dropped:
I want to format a number with two decimals unless it's 0. Can I do this?
123.93
23.00
144.34
0
2.38
This works great:
Go to format cells and select custom. Then paste this 0.00;[=0]0 into the Type field
from http://www.ozgrid.com/Excel/CustomFormats.htm
Try this:
=IF(A1=0,"0",TEXT(A1,"0.00"))
An alternative that includes a separator for thousands, shows negative values in red font and aligns zeros with whole numbers:
#,##0.00;[Red]-#,##0.00;0
(for the alignment, there are three blanks at the end).
From Excel Help:
A number format can have up to four sections of code, separated by
semicolons. These code sections define the format for positive
numbers, negative numbers, zero values, and text, in that order.
;;;
So All you really need to do is something like 0.00,-0.00,0