Difficulty in finding end of row in VB Excel - excel

Question

I am reading in information from a .txt file, This text file has 2 row and 6 column; each element is separated by space or tab. I have the data to read all the strings but I find difficult in putting the data to the cells. How can I find end of first Row.
Text File:
$SUBCASE 1 1
$DISP 0 509 5 1 2
Below is the complete code, I'm getting only the first character string and rest not...
Private Sub PCH_Click()
Dim arTemp() As Variant
Dim lRet As String
Dim sVal As String
Dim Row As Long
Dim Col As Long
Dim ws As Worksheet
Set ws = Worksheets("Sheet1")
'Default method Uses Open Dialog To Show the Files
lRet = Application.GetOpenFilename("PCH files (*.pch), *.*")
'Reads the file into characters
sVal = OpenTextFileToString2(lRet)
Dim tmp As Variant
tmp = SplitMultiDelims(sVal, ",;$ ", True) ' Place the 2nd argument with the list of delimiter you need to use
Row = 0
For i = LBound(tmp, 1) To UBound(tmp, 1)
Row = Row + 1
Col = 1
While Not vbNewLine = ""
ws.Cells(Row, Col) = tmp(i) 'output on the first column
MsgBox (tmp(i))
Col = Col + 1
Wend
Next i
End Sub
Function OpenTextFileToString2(ByVal strFile As String) As String
' RB Smissaert - Author
Dim hFile As Long
hFile = FreeFile
Open strFile For Input As #hFile
OpenTextFileToString2 = Input$(LOF(hFile), hFile)
Close #hFile
End Function
Function SplitMultiDelims(ByRef Text As String, ByRef DelimChars As String, _
Optional ByVal IgnoreConsecutiveDelimiters As Boolean = False, _
Optional ByVal Limit As Long = -1) As String()
Dim ElemStart As Long, N As Long, M As Long, Elements As Long
Dim lDelims As Long, lText As Long
Dim Arr() As String
lText = Len(Text)
lDelims = Len(DelimChars)
If lDelims = 0 Or lText = 0 Or Limit = 1 Then
ReDim Arr(0 To 0)
Arr(0) = Text
SplitMultiDelims = Arr
Exit Function
End If
ReDim Arr(0 To IIf(Limit = -1, lText - 1, Limit))
Elements = 0: ElemStart = 1
For N = 1 To lText
If InStr(DelimChars, Mid(Text, N, 1)) Then
Arr(Elements) = Mid(Text, ElemStart, N - ElemStart)
If IgnoreConsecutiveDelimiters Then
If Len(Arr(Elements)) > 0 Then Elements = Elements + 1
Else
Elements = Elements + 1
End If
ElemStart = N + 1
If Elements + 1 = Limit Then Exit For
End If
Next N
'Get the last token terminated by the end of the string into the array
If ElemStart <= lText Then Arr(Elements) = Mid(Text, ElemStart)
'Since the end of string counts as the terminating delimiter, if the last character
'was also a delimiter, we treat the two as consecutive, and so ignore the last elemnent
If IgnoreConsecutiveDelimiters Then If Len(Arr(Elements)) = 0 Then Elements = Elements - 1
ReDim Preserve Arr(0 To Elements) 'Chop off unused array elements
SplitMultiDelims = Arr
End Function

Answer 1

You can read a file row by row with following code
Sub IOTest()
Dim fnum, i As Integer, j As Integer
Dim line As String
Dim lines As Variant
Dim regEx As Object
Set regEx = CreateObject("vbscript.regexp")
With regEx
.Pattern = "\s{1}" 'only one whitespace
.Global = True 'find all occurrences
End With
fnum = FreeFile()
Open ThisWorkbook.Path & "\IO_Test.txt" For Input As #fnum
Do Until EOF(fnum) 'until End of file
i = i + 1
Input #fnum, line 'load row into line
'First replace found sole whitespaces with ","
'Then split on the ","s
lines = Split(regEx.Replace(line, ","), ",")
For j = LBound(lines) To UBound(lines)
Cells(i, j + 1) = lines(j)
Next j
Loop
Close #fnum
End Sub
I tested this with the strings
"$SUBCASE" & vbTab & "1" & vbTab & vbTab & vbTab & vbTab & "1"
"$DISP" & vbTab & "0" & vbTab & "509" & vbTab & "5" & vbTab & "1" & vbTab & "2"
And it only works if you have one whitespace(eg. space, tab,...) separating the data. If you have more than one whitespace between the data it gets trickier. But if you can provide an example on how the data is separated I can take a look at it.
I hope it helps, let me know either way ;)