I need to make my batch file replace a setting in "config.ini" for example:
color = 1A
how can I find and replace ONLY the 1A part instead of making another line.
Are you in Unix-like OS? if so, just use the sed command:
sed 's/1A/replacedstring/' config.ini
For more information: http://en.wikipedia.org/wiki/Sed
Related
I tried gedit, nano, vi, leafpad and other text editors , it won't open, I tried cat and other file looking commands, and I ensure you it's a file not a directory!
This type of approach has a lot of misunderstanding because using - as an argument refers to STDIN/STDOUT i.e dev/stdin or dev/stdout .So if you want to open this type of file you have to specify the full location of the file such as ./- .For eg. , if you want to see what is in that file use cat ./-
Both cat < - and ./- command will give you the output
you can use redirection
cat < -file_name
It looks like the rev command doesn't treat - as a special character.
From the man page
The rev utility copies the specified files to standard output, reversing the order of characters in every line.
so
rev - | rev
should show what's in the file in the correct order.
I tried with pico or vi command.pico readme which allowed me open in editor and read the contents.
if you want to open this type of file you have to specify the full location of the file such as ./- .For eg. , if you want to see what is in that file use cat ./-
cat ./- is the syntax that reveals the correct password for bandit the "rev -" reveals something else
Why does this shell script add a return to the filename of the output file?
#!/bin/bash
/usr/bin/tail -n 1 /path/logchanged.csv >> "/path/logcontatenated.csv"
The filename is not called "logcontatenated.csv", but "logcontatenated.csv
"
I really can't find on the internet why this happens.
Could it be that you created that script using Windows? If the line ends in \r\n without trailing spaces the file name is interpreted as logcontatenated.csv\r. Try hd yourscript.sh to display a hexdump of your script. Line breaks should be only a single byte of 0a rather than two bytes of 0d 0a, i.e. make sure the byte before any 0a is NOT 0d. You could use dos2unix yourscript.sh to fix your script. You might need to install dos2unix first.
EDIT: Replaced 0c with 0d.
I am new to Linux.
I was debugging some code. I encountered the following command:
PROGRAM_ID=$(echo $PROGRAM_ID|sed 's/-/,/g')
Can anybody explain what the g represents here?
I understand hyphen is being replaced with comma.
The /g flag means, perform the substitution globally on a line. Without that flag, only the first hyphen on every line would get substituted.
A better way with Bash would be
PROGRAM_ID=${PROGRAM_ID//-/,}
but if you have to be portable to Bourne shell in general, this replacement facility is not available.
(In which case you should take care to keep "$PROGRAM_ID" in double quotes in the echo.)
Its easy to see how g (global) works with these two example:
echo "test-one-two-three" | sed 's/-/,/g'
test,one,two,three
echo "test-one-two-three" | sed 's/-/,/'
test,one-two-three
Without the g it only replace the first hit.
I have separated some tracks from mp3 mixes using mp3splt.
BASH: (mp3splt -c('**!!***use .cue file***!!**') [cuefile.cue] [nonstopmix.mp3] ~for anyone interested, is in the Ubu repos~)
And I ended up with these filenames: "Antares" - 01 - "Xibalba".mp3 which is not a format I prefer, now I've made it a little project to change them with a shell script but its more difficult than I anticipated.
I want to change the filename from:
"Antares" - 01 - "Xibalba".mp
to:
01-Antares_-_Xibalba.mp3
so far I've used :
for var in *.mp3; do mv $var {var/"/}; done
and I could repeat that until I'm through, delete the 0x number and add one but I'd like to do it more efficient.
Could anyone give me a pointer (!not a script!) ?
I'd still like to write it myself but there's so much options that I'm a bit lost.
so far I thought to use this program flow:
read all the filenames containing .mp3 and declare as variable $var
strip $var from quotes
select 0x number, append delimiter _ (0x_)
move 0x_ to the beginning of the string
select remaining ' - - ' and change to '-'
done
which bash programs to use? especially changing the 0x puzzles me cuz I need a loop which increments this number and test if it is present in the filename variable and then it has to be changed.
It is easy to do in python 2.x. You can use this logic in any language you want.
import string
a=raw_input('Enter the name of song')
a=a.replace('"', "")
a=a.replace('.mp', ' .mp3')
words = a.split()
print words[2]+'-'+words[0]+'_-_'+words[4]+words[5]
Logic:
I removed ", then make .mp to .mp3, then splitted the string, which created a list ( array ) and then printed the elements according to need.
Try doing this :
rename -n 's/"(\w+)"\s+-\s*(\d+)\s*-\s*"(\w+)"\.mp/$2-$1_-_$3.mp3/' *mp
from the shell prompt. It's very useful, you can put some perl tricks like I does in a substitution.
You can remove the -n (dry-run mode switch) when your tests become valids.
There are other tools with the same name which may or may not be able to do this, so be careful.
If you run the following command (linux)
$ file $(readlink -f $(type -p rename))
and you have a result like
.../rename: Perl script, ASCII text executable
then this seems to be the right tool =)
If not, to make it the default (usually already the case) on Debian and derivative like Ubuntu :
$ sudo update-alternatives --set rename /path/to/rename
Last but not least, this tool was originally written by Larry Wall, the Perl's dad.
I'm looking for a command in VI/VIM to search for particular text in the file and grab the whole line and output in either on the screen or separate file. e.g.
This is some line with this _word_ and some other text.
This is some line with this some other text and some other text.
so this would output only the first line..
:redir > output.txt
:g/_word_/p
:redir END
The line will be output to the screen and to output.txt. See :h :redir.
EDIT: I agree with others who suggest using plain old *nix grep if you can. Situations where you might not be able to use grep:
You're searching buffer text that doesn't exist in a file on the filesystem.
You're using Vim-specific regex extensions, like cursor location, column number, marks, etc.
You want do this in a cross-platform way, and grep might not exist on the system you're using.
redir can be useful in these situations.
use the g (global) command:
:g/_word_/y
will yank all lines containing _word_
having mentioned the DOS find command, you probably want to use grep:
grep -h '_word_' * > results
in vi, from command mode
search for _word_
/_word_
yank the line
yy
paste the line
p