I would appreciate it if someone can answer this.
Lets say I got multiple rows with three column with min, max and the return value . And I wanted to create a single formula to search the min and max value and then gave back a return value based on the row . Let me just show it :
Min Max Return
0.01 10 0
10.01 20 5
20.01 30 12
30.01 40 15
Input 7 <---- User input
Return 0 <---- This should be calculated based on the user input against the table
Input 33 <---- User input
Return 15 <---- This should be calculated based on the user input against the table
If you mean a SQL Query, here is the query that jsut do the job for you :
SELECT Return from TABLE_Name
WHERE
Input >= Min AND Input < Max
Ok, I'll attempt another try:
=SUMPRODUCT(C2:C5*(F1>=A2:A5)*(F1<=B2:B5))
C2:C5 are the results, A2:A5 the minmum values, B2:B5 the maximum values and F1 the actual value.
Basically, SUMPRODUCT can be used as it does the calculation for every row and sums up the results. If the test succeeds, 1 is returned, otherwise 0. Thus, only the successful test will have a 1, all others will multiply their result with 0.
If I understood the question correctly, some nested IFs would do like (assuming input in A4 and the ranges like in the table):
=IF(AND(A4>B1,A4<B2),B3,IF(AND(A4>C1,A4<C2),C3,...
For more complex (meaning longer) tables you could also use a "helper" column (Column D):
IF(AND($A$4>B1,$A$4<B2),B3,"")
"drag" this down to copy it and then sum the column to get the result.
All a bit of a mess, but I can't think of any more elegant solution using excel formulas.
Related
Consider the following sheet/table:
A B
1 90 71
2 40 25
3 60 16
4 110 13
5 87 82
I want to have a general formula in cell C1 that sums the greatest value in column A (which is 110), plus the sum of the other values in column B (which are 71, 25, 16 and 82). I would appreciate if the formula wasn't an array formula (as in requiring Ctrl + Shift + Enter). I don’t have Office 365, I have Excel 2019.
My attempt
Getting the greatest value in column A is easy, we use MAX(A1:A5).
So the formula I want in cell C1 should be something like:
=MAX(A1:A5) + SUM(array_of_values_to_be_summed)
Obtaining the values of the other rows in column B (what I called array_of_values_to_be_summed in the previous formula) is the hard part. I've read about using INDEX, MATCH, their combination, and obtaining arrays by using parenthesis and equal signs, and I've tried that, without success so far.
For example, I noticed that NOT((A1:A5 = MAX(A1:A5))) yields an array/list containing ones (or TRUEs) for the relative position of the rows to be summed, and containing a zero (or FALSE) for the relative position of the row to be omitted. Maybe this is useful, I couldn't find how.
Any ideas? Thanks.
Edit 1 (solution)
I managed to obtain what I wanted. I simply multiplied the array obtained with the NOT formula, by the range B1:B5. The final formula is:
=MAX(A1:A5) + SUM(NOT((A1:A5 = MAX(A1:A5))) * B1:B5)
Edit 2 (duplicate values)
I forgot to explain what the formula should do if there are duplicates in column A. In that case, the first term of my final formula (the term that has the MAX function) would be the one whose corresponding value in column B is smallest, and the value in column B of the other duplicates would be used in the second term (the one containing the SUM function).
For example, consider the following sheet/table:
A B
1 90 71
2 110 25
3 60 16
4 110 13
5 110 82
Based on the above table, the formula should yield 110 + (71 + 25 + 16 + 82) = 304.
Just to give context, the reason I want such a formula is because I’m writing a spreadsheet that automatically calculates the electric current rating of the short-circuit protective device of the feeder of a group of electric motors in a house or building or mall, as required by the article 430.62(A) of the US National Electrical Code. Column A is the current rating of the short-circuit protective device of the branch-circuit of each motors, and column B is the full-load current of each motor.
You can use this formula
=MAX(A1:A5)
+SUM(B1:B5)
-AGGREGATE(15,6,(B1:B5)/(A1:A5=MAX(A1:A5)),1)
Based on #Anupam Chand's hint for max-value-duplicates there could also be min-value-duplicates in column B for corresponding max-value-duplicates in column A. :) This formula would account for that
=SUM(B1:B5)
+(MAX(A1:A5)-AGGREGATE(15,6,(B1:B5)/(A1:A5=MAX(A1:A5)),1))
*SUMPRODUCT((A1:A5=MAX(A1:A5))*(B1:B5=AGGREGATE(15,6,(B1:B5)/(A1:A5=MAX(A1:A5)),1)))
Or with #Anupam Chand's shorter and better readable and overall better style :)
=SUM(B1:B5)
+(MAX(A1:A5)-MINIFS(B1:B5,A1:A5,MAX(A1:A5)))
*COUNTIFS(A1:A5,MAX(A1:A5),B1:B5,MINIFS(B1:B5,A1:A5,MAX(A1:A5)))
The explanation works for bot solutions:
The SUM-part just sums the whole list.
The second line gets the max-value for column A and the corresponding min-value of column B for the max-values in column A and adds or subtracts it respectively.
The third line counts, how many times the corresponding min-value for the max-value occurs and multiplies it with the second line.
Can you try this ?
=MAX(A1:A5)+SUM(B1:B5)-MINIFS(B1:B5,A1:A5,MAX(A1:A5))
What we're doing is adding the max of A to all rows of B and then subtracting the min value of B where A is the max.
If you have Excel 365 you can use the following LET-Formula
=LET(A,A1:A5,
B,B1:B5,
MaxA,MAX(A),
MinBExclude, MINIFS(B,A,MaxA),
sumB1,SUMPRODUCT(B*(A=MaxA)*(B<>MinBExclude)),
sumB2,SUMPRODUCT(B*(A<>MaxA)),
MaxA +sumB1+sumB2
A and B are shortcuts for the two ranges
MaxA returns the max value for A (110)
MinBExclude filters the values of column B by the MaxA-value (25, 13, 82) and returns the min-value of the filtered result (13)
sumB1 returns the sum of the other MaxA values from column B (26 + 82)
sumB2 returns the sum of the values from B where value in A <> MaxA (71 + 60)
and finally the result is returned
If you don't have Excel 365 you can add helper columns for MaxA, MinBExclude, sumB1 and sumB2 and the final result
I have a few hundred rows of data, and each has a number between 1 and 200, and I'd like to put them in categories of 1-5 depending on where that number is.
The categories look like this:
Zones Min Max
1 0 35
2 35 60
3 60 85
4 85 110
5 110 200
I want to assign it a Zone if it is greater than the Min, but less than the Max.
I have 2 formulas I've been working with to solve it. One is a nested IF AND statement:
=IF(A1<=35,1,IF(AND(A1<=60,A1>35),2,IF(AND(A1<=85,A1>60),3,IF(AND(A1<=110,A1>85),4,IF(AND(A1<=200,A1>110),2,"TOO BIG")))))
The 2nd formula attempts to use a SUMPRODUCT function:
=INDEX($C$2:$C$6,SUMPRODUCT(--(A1<=$E$2:$E$6),-- (A1>$D2:$D$6),ROW($2:$6)))
Rather than have to continue to adjust the numeric values manually, I set them as absolutes, which is why this formula is slightly different. The E column is the Max value set, and the D is the Min value set.
Any help would be appreciated!
Use this:
=MATCH(A1,{0,35,60,85,110})
Another way is to use VLOOKUP and you just need to set the min number:
=VLOOKUP(D2,$A$2:$B$6,2,1)
The key is the 4th parameter needs to set to 1 which means TRUE. It will find the closest value and return the zone for you.
But noticed that you have overlaps like 35 or 60 etc. that you will need to adjust your value column.
I have a table in Excel that has the following columns:
My table
dm: Can be 0 or 1
gdr: Can be 0 or 1
smk: Can be 0 or 1
agemin: min age number
agemax: max age number
sbpmin: min sbp number
sbpmax: max sbp number
chlmin: min chl number
chlmax: max chl number
The table is big with all possible combinations.
What i need is a way to find the value in result based on the input of:
dm, gd, smk, age, sbp and chl. As i mention the first 3 can be a 0 or a 1 but the other 3 is a number that must be contain in the range given by the columns min and max.
Has anyone have a clue on how can i solve this?
Thanks,
Using the provided table and assuming the parameters for a lookup are in column M (as shown in the below picture), then the formula in cell M9 and copied right to get the result is:
=IFERROR(INDEX($J$2:$J$4,MATCH(1,INDEX((M2=$A$2:$A$4)*(M3=$B$2:$B$4)*(M4=$C$2:$C$4)*(M5>=$D$2:$D$4)*(M5<=$E$2:$E$4)*(M6>=$F$2:$F$4)*(M6<=$G$2:$G$4)*(M7>=$H$2:$H$4)*(M7<=$I$2:$I$4),),0)),"No matches found")
I have a data set something like this
Units Price
1 15
100 10
150 9
200 8
50000 7
I need the output as Price with respect to quantity.
Example- If Input value is 90 it should give price as 15
If input is 210 it should give value as 8.
However,sadly I cannot use IF statement.
Thanks in advance.
You can use a combination of INDEX and MATCH
=INDEX(B1:B5,MATCH(lookup_value,A1:A5,1))
This assumes Units are in column A and Price is in column B
Make sure you understand both functions:
INDEX
MATCH - particularly the reason for the ,1) at the end
You can also use VLOOKUP. This is probably a bit easier although INDEX/MATCH is more versatile:-
=VLOOKUP(Lookup_value,$A$2:$B$6,2,TRUE)
I have a rather big (long) table and need to do something quite simple but I'm currently with a sort of blackout...
Imagine that you have:
Date 1 Value 1 Date 2 Value 2 Date 3 Value 3 Date of MAX
... ... ... ... ... ... ????
I want to deploy in ???? a formula that will result in the date at which the maximal value (between Value 1...3) was registered. For instance:
Date 1 Value 1 Date 2 Value 2 Date 3 Value 3 Date of MAX
20160501 10 20160722 47 20161002 9 20160722
meaning, the Date of MAX is of Date 2 because that was the date at which the MAX was measured.
Thanks in advance.
You could do a more general solution using offset:-
=MAX(N(OFFSET(D2,0,COLUMN(A:D)*3)))
to find the largest value - put this in (say) R2.
Then find a match for it and pick out the corresponding date:-
=OFFSET(C2,0,MATCH(R2,N(OFFSET(D2,0,COLUMN(A:D)*3)),0)*3)
assuming the dates and values are every third column.
These are array formulae and must be entered with CtrlShiftEnter
If the last value really was in P21 you would have to give a row offset as well as a column offset.
OK, I found a dirty but simple solution (don't know why I didn't think of it at first):
=IF(G2>=MAX(G2,J2,M2,P21),F2,IF(J2>=MAX(G2,J2,M2,P21),I2,IF(M2>=MAX(G2,J2,M2,P21),L2,O2)))
where the pairs (4 of them) are at FG, IJ, LM, OP. Not elegant but does the job.