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Let's say I've typed "abcdefg", with the cursor at the end. I want to delete back to the c, so that I only have "abc" left.
Is there a command like d that includes the current character? I know I could do dTcx, but the x feels like a work-around and I suppose there's a better solution.
No. Backward motions always start on the left of the current character for c, y and d which is somehow logical but also unnerving.
The only "clean" solutions I could think of either imply moving to the char after c first and then do a forward delete:
Tcde
or using visual mode:
vTcd
v3hd
But, given your sample and assuming you are entering normal mode just for that correction, the whole thing sounds extremely wasteful to me.
What about staying in insert mode and simply doing ←←←←?
try this:
TcD
this will leave abc for your example... well if the abcdefg is the last word of the line.
if it is not the last word in that line, you may do:
ldTc
or golfing, do it within 3 key-stroke:
3Xx or l4X
See this answer to a similar question : there is a setting to be allowed to go beyond the end of the line
From the doc :
Virtual editing means that the cursor can be positioned where there is
no actual character. This can be halfway into a tab or beyond the end
of the line. Useful for selecting a rectangle in Visual mode and
editing a table.
"onemore" is not the same, it will only allow moving the cursor just
after the last character of the line. This makes some commands more
consistent. Previously the cursor was always past the end of the line
if the line was empty. But it is far from Vi compatible. It may also
break some plugins or Vim scripts. For example because |l| can move
the cursor after the last character. Use with care!
Using the $ command will move to the last character in the line, not
past it. This may actually move the cursor to the left!
The g$ command will move to the end of the screen line.
It doesn't make sense to combine "all" with "onemore", but you will
not get a warning for it.
In short, you could try :set virtualedit=onemore, and see if your environment is stable or not with it.
Use d?c
That will start d mode, search back to 'c' and then delete up to your cursor position.
Edit: nope, that does not include current position...
I may be misunderstanding your request, but does 3hd$ do it?
I would use vFdd in this example. I think it's nicer than the other solutions since the command explicitly shows what to delete. It includes the current character and the specified character when deleting.
v: enter visual mode (mark text)
F: find/goto character backwards
d: the character "d" that will be included for removal.
d: delete command
Since it is visual mode, the cursor can also be moved before executing the actual removal d. This makes the command powerful even for deleting up to a non unique character by first marking a special character close to the character and then adjusting the position.
What is the shortest combo?
P.S. I usually do ACtrl+wCtrl+wCtrl+wEsc.
In other words, I have to jump into Insert mode.
P.P.S. d3b doesn't work.
This sequence of commands,
$3bD
is the shortest way to do it I can think of at the moment but it leaves out an ugly trailing space.
$3gelD
is another way that gets rid of the trailing space.
You can also think outside the box and play with spaces instead of words:
$3F D
$ 3b D which translates to
$ to the end of a line
3 three of whatever is next
b backward three [one without modifier] words
D delete the characters under the cursor until the end of the line
In addition, you can also use the normal command in ex mode to achieve the same
:norm! $3bD
$3bD
Or
$3bDx
...if you also want to delete the trailing space.
Go to the end of the line, go back 3 words, then delete to the end of the line: $ 3b D
or
Go to the end of the line, delete back 3 words, then delete the extra character: $ 3db x
As others have mentioned, $3bD is the shortest, and $3bDx will suffice to remove the remaining whitespace, assuming it's exactly one space or tab.
In order to account for all whitespace, $3gelD can be used. This option has the benefit of cleaning up properly in most cases, but it fails when a line contains exactly 3 words because the 3ge motion jumps back to the previous line.
An alternative approach is based on daw. Since 3daw acts forward, either $daw.. or $3b3daw must be used. For 3 words, $daw.. is shorter and probably more desirable, but $3b3daw is more Vim-esque and can easily be extended to more words.
b, ge, and w can be replaced with B, gE, and W in order to remove WORDs instead of words.
I have the following characters being repeated at the end of every line:
^[[00m
How can I remove them from each line using the Vim editor?
When I give the command :%s/^[[00m//g, it doesn't work.
You could use :%s/.\{6}$// to literally delete 6 characters off the end of each line.
The : starts ex mode which lets you execute a command. % is a range that specifies that this command should operate on the whole file. The s stands for substitute and is followed by a pattern and replace string in the format s/pattern/replacement/. Our pattern in this case is .\{6}$ which means match any character (.) exactly 6 times (\{6}) followed by the end of the line ($) and replace it with our replacement string, which is nothing. Therefore, as I said above, this matches the last 6 characters of every line and replaces them with nothing.
I would use the global command.
Try this:
:g/$/norm $xxxxxx
or even:
:g/$/norm $5Xx
I think the key to this problem is to keep it generic and not specific to the characters you are trying to delete. That way the technique you learn will be applicable to many other situations.
Assuming this is an ANSI escape sequence, the ^[ stands for a single <Esc> character. You have to enter it by pressing Ctrl + V (or Ctrl + Q) on many Windows Vim installations), followed by Esc. Notice how this is then highlighted in a slightly different color, too.
It's easy enough to replace the last six characters of every line being agnostic to what those characters are, but it leaves considerable room for error so I wouldn't recommend it. Also, if ^[ is an escape character, you're really looking for five characters.
Escape code
Using ga on the character ^[ you can determine whether it's an escape code, in which case the status bar would display
<^[> 27, Hex 1b, Octal 033
Assuming it is, you can replace everything using
:%s/\%x1b\[00m$//gc
With \%x1b coming from the hex value above. Note also that you have to escape the bracket ([) because it's a reserved character in Vim regex. $ makes sure it occurs at the end of a line, and the /gc flags will make it global and confirm each replacement (you can press a to replace all).
Not escape code
It's a simple matter of escaping then. You can use either of the two below:
:%s/\^\[\[00m$//gc
:%s/\V^[[00m\$//gc
If they are all aligning, you can do a visual-block selection and delete it then.
Otherwise, if you have a sequence unknown how to input, you can visually select it by pressing v, then mark and yank it y (per default into register "). Then you type :%s/<C-R>"//g to delete it.
Note:
<C-R>" puts the content of register " at the cursor position.
If you yanked it into another register, say "ay (yank to register a - the piglatin yank, as I call it) and forgot where you put it, you can look at the contents of your registers with :reg.
<C-R> is Vim speak for Ctrl+R
This seems to work fine when the line is more than 5 chars long:
:perldo $_ = substr $_, 0, -5
but when the line is 5 or less chars long it does nothing.
Maybe there is a easy way in perl to delete the last 5 chars of a string, but I don't really know it:)
Use this to delete:
:%s/^[[00m//gc
For example if I have some code like:
foo = bar("abc", "def", true, callback);
Is there a nice command to move true to the 1st or 2nd position leaving the commas intact?
P.S as a bonus my friend want to know if this works in Emacs too.
In Vim if you place the cursor at the start of the first word and do dWWP then it will have the desired effect. Here is a breakdown:
dW delete the current word, including the comma and the following whitespace
W move to the start of the next word
P insert the deleted text before the cursor
This will work if there are further parameters after the pair to be swapped - it will need to be modified if there are only two parameters or you want to swap the last two parameters, since it will paste the text after the closing bracket.
Alternatively you could use a regex substitution:
:%s/(\([^,]\+\),\s*\([^,)]\+\)/(\2, \1/
This will find the first two arguments after the open bracket and swap them.
update:
A search of vim.org found the swap parameters plugin, which should do exactly what you want and can handle situations that either of the above methods cannot.
I don't know the answer for vi, but in Emacs, transpose-sexps (C-M-t) will swap two arguments either side of the cursor. Actually transpose-words (M-t) was my first guess, but that leaves the quotes behind.
You need a transpose emacs command. But its limited to not guessing that its transposing in lists, it only considers text (it can't guess the 1st, 2nd word of list). Try this.
Keep your cursor at after comma of true. Use M-x transpose-words. By default it will transpose with next word from the point. Shortcut is M-t.
You can use C-u 2 M-t for transpose with next second word.
Now coming to your question. If you want to move true, to backward 1 word, use C-u -1 M-t, and for backward 2 words C-u -2 M-t.
Am not a VIM guy. So sorry bout that.
If you want to do this as a refactoring, not just as text manipulation, I'd suggest looking into Xrefactory, a refactoring tool for Emacsen (free for C/Java, commercial for C++).
Transposing previous (Ctrl-t p) and next (Ctrl-t n) argument ... add the
following into your .vimrc file:
map <C-t>p ?,\\|(<CR>wd/,\\|)<CR>?,\\|(<CR>"_dw?,\\|(<CR>a, <C-c>?,<CR>P/,<CR>w
map <C-t>n ?,\\|(<CR>wv/,<CR>d"_dw/\\,\\|)<CR>i, <C-r>"<C-c>?,<CR>?,\\|(<CR>w
My previous question seems to be a bit ambiguous, I will rephrase it:
I have a file like this:
copythis abc
replacethis1 xyz
qwerty replacethis2
hasfshd replacethis3 fslfs
And so on...
NOTE: replacethis1, replacethis2, replacethis3, ... could be any words
How do I replace "replacethis1","replacethis2","replacethis3",.. word by "copythis" word by using minimum vim commands.
One way I can do is by these steps:
delete "replacethis1","replacethis2","replacethis3",.. by using 'dw'
copy "copythis" using 'yw'
move cursor to where "replacethis1" was and do 'p'; move cursor to where "replacethis2" was and do 'p' and so on...
Is there a better way to do this in VIM (using less number of vim commands)?
Since you changed your question, I'd do it this way:
Move to the first "replacethis1" and type cw (change word), then type "copythis" manually.
Move to the next "replacethis", hit . (repeat last operation)
Move to the next "replacethis", hit .,
and so on, and so on.
If "copythis" is a small word, I think this is the best solution.
The digit needs to be included, and there could be more than one instance per line:
:%s/replacethis\d/copythis/g
Given that "replacethis[1-3]" can be arbitrary unrelated words, the quickest/simplest way to do this globally would be:
:%s/replacethis1\|replacethis2\|replacethis3/copythis/g
(Note that you need to use \| to get the pipes to function as "or". Otherwise, vim will look for the literal | character.)
I've been struggling with this for a long time too, I think I just worked out the cleanest way:
Use whichever command is cleanest to put copythis into register r:
/copythis
"rye
Then go to the replacement and replace it with the contents of r:
/replacethis
cw<CTRL-R>r<ESC>
Then you can just n.n.n.n.n.n.n. for the rest of them, or if they're wildly different just go to the beginning of each and hit .
The key is replacing and pasting in one step so you can use . later.
:%s/copythis/replacethis/g
To replace all occurrences of copythis with replacethis. Or you can specify a range of line numbers like:
:8,10 s/copythis/replacethis/g
Note, the /g on the end will tell it to replace all occurrences. If you leave that off it will just do the first one.
create this mapping:
:map z cwcopythis^[
( ^[ is the escape character, you can type it in vim using Ctrl+V Ctrl+[ )
go to each word you want to replace and press z
if u need to do essentially the same action multiple times - swap 1st word of one line with second word of the next line, I say you could record a macro and call it whenever you need to
Have you tried string replacement?
%s/replacethis/copythis
A host of other parameters are possible to fine-tune the replacement. Dive into the Vim help for more details. Some more examples here.
You can remap e.g. the m key in normal mode to delete the word under the cursor and paste the buffer: :nnoremap m "_diwP.
Then you can just copy the desired word, move the cursor anywhere onto the to-be-replaced word and type m.
EDIT: Mapping to m is a bad idea since it is used to mark locations. But you can use e.g. ; anyway.