Finding average file size in MB in given directory - c#-4.0

I need to display the average file size in MB of given directory.
I started coding like this
string filePath = #"DesiredFilePath";
var getFiles = Directory.GetFiles(filePath);
var length = getFiles.Select(f => new FileInfo(f).Length);
how to extend the code to find average file size?


You are almost near.
Try this
string filePath = #"DesiredFilePath";
var getFiles = Directory.GetFiles(filePath);
var avg = getFiles.Select(f =>
new FileInfo(f).Length).Average();
Console.WriteLine("The Average file size in {0} directory is {1} MB",
filePath,Math.Round(avg/1048576,1));


You could use the Average extension method:
// using System.Linq;
string filePath = #"DesiredFilePath";
double averageFileSize = Directory
.EnumerateFiles(filePath)
.Average(x => new FileInfo(x).Length);


It think this is the shortest way (less code) to do it:
string filePath = "My Path";
double averageBytes = new DirectoryInfo(filePath)
.EnumerateFiles()
.Average(file => file.Length);
double averageMb = averageBytes / 1048576.0;

Related

Failed to execute 'atob' on 'Window': The string to be decoded is not correctly encoded - hex is different

I have a legacy classic asp application, that allows us to upload pdf files. The file is saved as hex into a MS SQL DB into an image column. Here is a snip of the data in the column:
0x4A564245526930784C6A634E436957317462573144516F784944416762324A7144516F...
We are now working on a rework of the app using node.js as our backend and angular4 as the front end. As part of that, we need to be able to download the same file in the new app. If I upload the same file using angular4 then the image data looks like this:
0x255044462D312E370D0A25B5B5B5B50D0A312030206F626A0D0A3C3C2F547970652F43...
As you can see the hex is completely different and I am not sure what is causing this. I have tried to look at the classic asp code, but its very old and there is no special encoding or such that is happening that would cause this.
In Angular4 we are using the standard input type file control with the change event to capture the contents of the file and then saving it into our db:
myReader.onloadend = (f) => {
let image64;
if (myReader.result.toString()) {
let base64id = ';base64,';
image64 = myReader.result.substr(myReader.result.indexOf(base64id) + base64id.length);
}
someService.upload(image64);
}
So nothing crazy going on, right? The problem now is that I am able to download the file uploaded via angular fine, but not the ones that were uploaded via classic asp. I receive the following error when I try:
Failed to execute 'atob' on 'Window': The string to be decoded is not
correctly encoded.
Here is the code used to upload the files via classic ASP:
Public Function Load()
Dim PosBeg, PosEnd, PosFile, PosBound, boundary, boundaryPos, Pos
Dim Name, Value, FileName, ContentType
Dim UploadControl
PosBeg = 1
PosEnd = InstrB(PosBeg,m_FormRawData,getByteString(chr(13)))
boundary = MidB(m_FormRawData,PosBeg,PosEnd-PosBeg)
boundaryPos = InstrB(1,m_FormRawData,boundary)
'Get all data inside the boundaries
Do until (boundaryPos=InstrB(m_FormRawData,boundary & getByteString("--")))
Set UploadControl = Server.CreateObject("Scripting.Dictionary")
Pos = InstrB(BoundaryPos,m_FormRawData,getByteString("Content-Disposition"))
Pos = InstrB(Pos,m_FormRawData,getByteString("name="))
PosBeg = Pos+6
PosEnd = InstrB(PosBeg,m_FormRawData,getByteString(chr(34)))
Name = getString(MidB(m_FormRawData,PosBeg,PosEnd-PosBeg))
PosFile = InstrB(BoundaryPos,m_FormRawData,getByteString("filename="))
PosBound = InstrB(PosEnd,m_FormRawData,boundary)
If PosFile<>0 AND (PosFile<PosBound) Then
PosBeg = PosFile + 10
PosEnd = InstrB(PosBeg,m_FormRawData,getByteString(chr(34)))
FileName = getString(MidB(m_FormRawData,PosBeg,PosEnd-PosBeg))
UploadControl.Add "FileName", FileName
Pos = InstrB(PosEnd,m_FormRawData,getByteString("Content-Type:"))
PosBeg = Pos+14
PosEnd = InstrB(PosBeg,m_FormRawData,getByteString(chr(13)))
ContentType = getString(MidB(m_FormRawData,PosBeg,PosEnd-PosBeg))
UploadControl.Add "ContentType",ContentType
PosBeg = PosEnd+4
PosEnd = InstrB(PosBeg,m_FormRawData,boundary)-2
Value = MidB(m_FormRawData,PosBeg,PosEnd-PosBeg)
UploadControl.Add "value" , Value
m_dicFileData.Add LCase(name), UploadControl
Else
Pos = InstrB(Pos,m_FormRawData,getByteString(chr(13)))
PosBeg = Pos+4
PosEnd = InstrB(PosBeg,m_FormRawData,boundary)-2
Value = getString(MidB(m_FormRawData,PosBeg,PosEnd-PosBeg))
UploadControl.Add "value" , Value
End If
m_dicForm.Add LCase(name), UploadControl
BoundaryPos=InstrB(BoundaryPos+LenB(boundary),m_FormRawData,boundary)
Loop
Load = m_blnSucceed
End Function
Any idea what I can do here to fix this? I need to be able to download the old files as well. Is there an encoding or something else I am missing here?
After further looking into this, it seems the following is causing the error: Node.js will send a buffer to the front-end. On the front-end I then convert the buffer into base64 using the below code:
_arrayBufferToBase64(buffer) {
let base64 = '';
let bytes = new Uint8Array(buffer);
let len = bytes.byteLength;
for (let i = 0; i < len; i++) {
bbase64 += String.fromCharCode(bytes[i]);
}
return base64;
}
The returned base64 from the old classic asp is returned as garbage and looks like this:
*R{£ÌõGpÃì#j¾é>i¿ê A l Ä ð!!H!u!¡!Î!û"'"U""¯"Ý#
(?(q(¢(Ô))8)k))Ð5*hÏ++6+i++Ñ,,9,n,¢,×-''I'z'«'Ü(
3F33¸3ñ4+4e44Ø55M55Â5ý676r6®6é7$7`77×88P88È99B99¼9ù:6:t
I am still not sure how to fix this though.

How to play a single audio file from a collection of 100k audio files split into two folders?

I have placed two media folders into a single zip folder, and the total is 100k media files in the zip folder. I need to play a single file from particular folder of the zip folder. The problem is, first the total content of the Zip folder is completely read and then the necessary file is accessed. So, it takes more than 55 seconds to play a single file. I need a solution to reduce the time consumed to play the audio files.
Below is my code :
long lStartTime = System.currentTimeMillis();
System.out.println("Time started");
String filePath = File.separator+"sdcard"+File.separator+"Android"+File.separator+"obb"+File.separator+"com.mobifusion.android.ldoce5"+File.separator+"main.9.com.mobifusion.android.ldoce5.zip";
FileInputStream fis = new FileInputStream(filePath);
ZipInputStream zis = new ZipInputStream(fis);
String zipFileName = "media"+File.separator+"aus"+File.separator+fileName;
String usMediaPath = "media"+File.separator+"auk"+File.separator;
ZipEntry entry;
int UnzipCounter = 0;
while((entry = zis.getNextEntry())!=null){
UnzipCounter++;
System.out.println(UnzipCounter);
if(entry.getName().endsWith(zipFileName)){
File Mytemp = File.createTempFile("TCL", "mp3", getActivity().getCacheDir());
Mytemp.deleteOnExit();
FileOutputStream fos = new FileOutputStream(Mytemp);
for (int c = zis.read(); c!=-1; c= zis.read()){
fos.write(c);
}
if(fos!=null){
mediaPlayer = new MediaPlayer();
}
fos.close();
FileInputStream MyFile = new FileInputStream(Mytemp);
mediaPlayer.setDataSource(MyFile.getFD());
mediaPlayer.prepare();
mediaPlayer.start();
mediaPlayer.setOnCompletionListener(this);
long lEndTime = System.currentTimeMillis();
long difference = lEndTime - lStartTime;
System.out.println("Elapsed milliseconds: " + difference);
mediaPlayer.setOnErrorListener(this);
}
zis.closeEntry();
}
zis.close();

Try to not re-unzip the file because it consume too much time.
Instead of re-unzip the file, you can follow the following step:
Unzip file when first time app is launch. Set flag that we have launch the app before, use preferences.
On the next launch, check the flag. If app never launched before, goto first step. If it had launched before find the file and play.
If you really can't use those step, because it's your requirement, you can try using truezip vfs. But be aware that I've never use it before.
Here the library:
https://truezip.java.net/, https://github.com/jruesga/android_external_libtruezip

NodeSchool IO Exercies 3

I've started learning node.js
I'm currently on exercise 3, where we have to, based on a file buffer, calculate the number of new line characters "\n"
I pass the tester but somehow if I create my own file file.txt, I am able to get the buffer, and print out the string, but it is unable to calculate the number of new lines (console.log(newLineNum)) returns 0
Here is the code
//import file system module
var fs = require("fs");
//get the buffer object based on argv[2]
var buf = fs.readFileSync(process.argv[2]);
//convert buffer to string
var str_buff = buf.toString();
//length of str_buff
var str_length = str_buff.length;
var numNewLines = 0;
for (var i = 0; i < str_length; i ++)
{
if(str_buff.charAt(i) == '\n')
{
numNewLines++;
}
}
console.log(numNewLines);

If i understand your question correctly, you are trying to get the line length of current file.
From the documentation:
The first element will be 'node', the second element will be the name
of the JavaScript file.
So you should replace process.argv[2] with process.argv[1].
Edit:
If you are passing a parameter for a file name on command-line like:
node server.py 'test.txt'
your code should work without any problem.

Your code is fine. You should check the file that you are using for the input.

Why does my image not show in SharePoint?

I upload an image in SharePoint:
I save the image file in the folder: IMAGES\\imagewebpart\\
Random rd = new Random();
int db = rd.Next(0, 100);
string filename =Path.GetFileNameWithoutExtension(imagefile) +
db.ToString() +
Path.GetExtension(imagefile);
string filepath ="\\_layouts\\IMAGES\\imagewebpart\\" + filename;
FileUpload1.SaveAs(Server.MapPath(filepath));
//ImageEdit.ImageUrl =filepath;
ImageEdit.ImageUrl = Server.MapPath(filepath);
I can save the file successfully, but I can't display the image to ImageEdit.
Why?

ImageEdit.ImageUrl = Server.MapPath(filepath);
Try this
ImageEdit.ImageUrl = filepath;
where filepath = "/_layouts/IMAGES/imagewebpart/" + filename

From string fo DataSet without passing through HTML file

I have a string with length no more than 4000 chars which is a valid xml. Is there a way to pass it to Dataset without creating a temporary xml file?
At the moment I do so:
string validXml = TextBox1.Text;
string path = Directory.GetCurrentDirectory() + #"\tmp.xml";
FileInfo xmlProcess = new FileInfo(path);
using (StreamWriter sw = xmlProcess.CreateText())
{
sw.WriteLine(validXml);
}
DataSet aDataSet = new DataSet();
aDataSet.ReadXml(reader);
Is there a way to skip this creating and filling the tmp.xml?

Try this:
XmlTextReader reader = new XmlTextReader(new StringReader(validXml));
DataSet aDataSet = new DataSet();
aDataSet.ReadXml(reader);

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