Deceptively not-as-simple-as-I-thought typing - haskell

In the process of writing an interpreter in Haskell for a separate, simple programming language - I find myself butting my head against a wall as I learn typing in Haskell.
I have two custom data types
data Expr
= Var Var
| NumE Int
| NilE
| ConsE Expr Expr
| Plus Expr Expr
| Minus Expr Expr
| Times Expr Expr
| Div Expr Expr
| Equal Expr Expr
| Less Expr Expr
| Greater Expr Expr
| Not Expr
| Isnum Expr
| And Expr Expr
| Or Expr Expr
| Head Expr
| Tail Expr
| Call String
deriving (Show, Read)
data Val = Num Int | Nil | Cons Val Val
deriving (Eq, Show, Read)
and I'm starting to write the cases for interpreting these options, with the function interpret_expr
interpret_expr :: Vars -> Expr -> Val
interpret_expr vars#(Vars a b c d) (NumE integer) = integer
but this COMPLAINS that it couldn't match expected type 'Val' with actual type 'Int' in the expression 'integer'. But say I change it to something silly like
interpret_expr :: Vars -> Expr -> Val
interpret_expr vars#(Vars a b c d) (NumE 'a') = 'a'
it then complains at 'a' that it can't match expected type 'Int' with actual type 'Char'. NOW IT WANTS AN INT?????? I really don't know what to say, I really thought it would be as simple as providing NumE with a variable it could figure is an integer. What am I doing wrong?

In the first case you are returning an Int from a function you declared to return a Val. From your definition of Val it looks like you probably want to return Num integer here.
In the second case the problem is in the pattern matching. (NumE 'a') is an error because NumE is defined as NumE Int, so it must be followed by an Int, not a Char.

Related

How to create a data type containing a list

I'm trying to create a data type class that contains a list:
data Test = [Int] deriving(Show)
But Haskell can't parse the constructor. What am i doing wrong here and how can I best achieve what I'm trying to do?
An Answer
You need to include a constructor, which you haven't done.
data Test = Test [Int]
Consider reviewing Haskell's several type declarations, their use, and their syntax.
Haskell Type Declarations
data
Allows declaration of zero or more constructors each with zero or more fields.
newtype
Allows declaration of one constructor with one field. This field is strict.
type
Allows creation of a type alias which can be textually interchanged with the type to the right of the equals at any use.
constructor
Allows creation of a value of the declared type. Also allows decomposition of values to obtain the individual fields (via pattern matching)
Examples
data
data Options = OptionA Int | OptionB Integer | OptionC PuppyAges
^ ^ ^ ^ ^ ^ ^
| | Field | | | |
type Constructor | | Constructor |
Constructor Field Field
deriving (Show)
myPuppies = OptionB 1234
newtype
newtype PuppyAges = AgeList [Int] deriving (Show)
myPuppies :: PuppyAges
myPuppies = AgeList [1,2,3,4]
Because the types (PuppyAges) and the constructors (AgeList) are in different namespaces people can and often do use the same name for each, such as newtype X = X [Int].
type
type IntList = [Int]
thisIsThat :: IntList -> [Int]
thisIsThat x = x
constructors (more)
option_is_a_puppy_age :: Options -> Bool
option_is_a_puppy_age (OptionC _) = True
option_is_a_puppy_age () = False
option_has_field_of_value :: Options -> Int -> Bool
option_has_field_of_value (OptionA a) x = x == a
option_has_field_of_value (OptionB b) x = fromIntegral x == b
option_has_field_of_value (OptionC (AgeList cs)) x = x `elem` cs
increment_option_a :: Options -> Options
increment_option_a (OptionA a) = OptionA (a+1)
increment_option_a x = x

Haskell not finding "indirect" type

I'm taking a compilers class, and I decided to do it in haskell, but I'm having a hard time setting up the ast. My issue is that I have an Atom class and an Expr class and one instance of the Expr can be an Atom, but when the Expr is immediately an Atom it has an issue. Here is the example:
data Atom -- cannot be reduced farther
= Const Int -- int is value
| Var String -- string is name
deriving (Show) -- So we can print it
data Expr -- add input and the like
= Add Expr Expr -- add is two exprs
| USub Expr -- negation
| Input -- call to input
| Atomic Atom -- or an atomic
deriving (Show) -- So we can print it
data Statement
= Print Expr
| Discard Expr
| Assign String Expr
deriving (Show) -- So we can print it
main = do
let test5 = Print (Const 2)
putStrLn $ show test5
The compiler fails on the Print (Const 2) because it expected an Expr. Is there a fix to this, and is there better vocabular for expressing this problem?
Const 2 is an Atom, but Print takes an Expr as an argument. Luckily, every Atom can be made into an Expr with the Atomic constructor. So:
main = do
let test5 = Print (Atomic (Const 2))
print test5

Executing Parsed function calls in Haskell

First i want to say I'm a newbie in Haskell. Here's my problem:
For a school project I need to be able to parse and interprate and execute a fucntion call. This call needs to be able to execute a function already defined in haskell.
Parsing the call works, but i have no idea how to execute the function because the amount of arguments and type is unkown.
Here is how i represent my data
type Name = String
type Cond = Expr
data Expr
= Num Int
| Boolean Bool
| BinOp Op Expr Expr
| Var Name
deriving (Eq, Ord, Show)
data Stmnt
= Call Name [Expr]
| If Cond [Stmnt] [Stmnt]
| While Cond [Stmnt]
| VarDef Name Expr
deriving (Eq, Ord, Show)
This is a part of my interpeter. And it is with the implementation of funcall that I need help.
data Value = FineInt Int
| FineBool Bool
| FineFun ([Value] -> Value)
-- The enviroment keeps track of variables in the program
type Env = [(Name,Value)]
-- A state that takes an enviroment
type StEnv = State Env
evalstm :: Stmnt -> StEnv ()
evalstm (Call name exprs) = funcall name exprs
-- funcall name exprs = ?

Printing non string values in haskell

How can i print a value that is a non string type to console? The type is below.
data Expr = Var String | Con Bool | Uno Unop Expr | Duo Duop Expr Expr | List [Expr]
deriving Show
I have a list of the above type values and i would like to print them to screen each on a separate line( not the classic list view). Thanks
Just use print on each element of your list:
mapM' print exprs

Haskell: Data Type

I declare my data to be like this:
data Op = Plus | Minus | Mul | Div | Pow
deriving (Eq, Show)
type Name = String
data Variable a = Variable Name (Expression a)
deriving (Eq, Show)
data Declaration a = Declaration (Variable a)
deriving (Eq, Show)
{- The core symbolic manipulation type -}
data Expression a =
Number a -- Simple number, such as 5
| Expression Op (Expression a) (Expression a)
deriving (Eq, Show)
In GHCi, I want to create a instance of Declaration by typing:
Declaration Variable "var1" 2+3
but it does not work, I guess it is just a wrong syntax, but I cannot figure out how.
Also I would like to know when we need to use instance? This is the code I got from a book:
instance Num a => Num (Expression a) where
a + b = Expression Plus a b
a - b = Expression Minus a b
a * b = Expression Mul a b
negate a = Expression Mul (Number (-1)) a
abs a = error "abs is unimplemented"
signum _ = error "signum is unimplemented"
fromInteger i = Number (fromInteger i)
Declaration Variable "var1" 2+3
is equivalent to
(Declaration Variable "var1" 2) + 3
. That is, it tries to call Declaration with 3 arguments (Variable, "var1", 2), then adds the result to 3. This makes no sense.
You want
Declaration (Variable "var1" (2+3))

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