I have two folders, one called 'modified' and one called 'original'.
'modified' has no subdirectories and contains 4000 wav files each with unique names.
The 4000 files are copies of files from 'original' except this folder has many subdirectories inside which the original wav files are located.
I want to, for all the wav files in 'modified', replace their name-counterpart in 'original' wherever they may be.
For example, if one file is called 'sound1.wav' in modified, then I want to find 'sound1.wav' in some subdirectory of 'original' and replace the original there with the modified version.
I run Windows 8 so command prompt or cygwin would be best to work in.
As requested, I've written the python code that does the above. I use the 'os' and 'shutil' modules to first navigate over directories and second to overwrite files.
'C:/../modified' refers to the directory containing the files we have modified and want to use to overwrite the originals.
'C:/../originals' refers to the directory containing many sub-directories with files with the same names as in 'modified'.
The code works by listing every file in the modified directory, and for each file, we state the path for the file. Then, we look through all the sub-directories of the original directory, and where the modified and original files share the same name, we replace the original with the modified using shutil.copyfile().
Because we are working with Windows, it was necessary to change the direction of the slashes to '/'.
This is performed for every file in the modified directory.
If anyone ever has the same problem I hope this comes in handy!
import os
import shutil
for wav in os.listdir('C:/../modified'):
modified_file = 'C:/../modified/' + wav
for root, dirs, files in os.walk('C:/../original'):
for name in files:
if name == wav:
original_file = root + '/' + name
original_file = replace_file.replace('\\','/')
shutil.copyfile(modified_file, original_file)
print wav + ' overwritten'
print 'Complete'
Related
I'll start by mentioning that I've no knowledge in Python but read online that it could help me with my situation.
I'd like to do a few things using (I believe?) a Python script.
I have a bunch of .yml files that I want to transfer the contents into one main .yml file (let's call it Main.yml). However, I'd also like to be able to take the name of each individual .yml and add it before it's content into Main.yml as "##Name". If possible, the script would look like each file in a directory, instead of having to list every .yml file I want it to look for (my directory in question only contains .yml files). Not sure if I need to specify, but just in case: I want to append the contents of all files into Main.yml & keep the indentation (spacing). P.S. I'm on Windows
Example of what I want:
File: Apes.yml
Contents:
Documentation:
"Apes":
year: 2009
img: 'link'
After running the script, my Main.yml would like like:
##Apes.yml
Documentation:
"Apes":
year: 2009
img: 'link'
I'm just starting out in Python too so this was a great opportunity to see if my newly learned skills work!
I think you want to use the os.walk function to go through all of the files and folders in the directory.
This code should work - it assumes your files are stored in a folder called "Folder" which is a subfolder of where your Python script is stored
# This ensures that you have the correct library available
import os
# Open a new file to write to
output_file = open('output.txt','w+')
# This starts the 'walk' through the directory
for folder , sub_folders , files in os.walk("Folder"):
# For each file...
for f in files:
# create the current path using the folder variable plus the file variable
current_path = folder+"\\"+f
# write the filename & path to the current open file
output_file.write(current_path)
# Open the file to read the contents
current_file = open(current_path, 'r')
# read each line one at a time and then write them to your file
for line in current_file:
output_file.write(line)
# close the file
current_file.close()
#close your output file
output_file.close()
I need to write a python script to read through files in a directory, retrieve the header record (which contains date)? I need to compare the date in the header record of each file with current date and if the difference is greater than 30 days. I need to delete such files.
I managed to come up with below code but not sure how to proceed since I am new to Python.
Example:
Sample file in the directory (/tmp/ah): abcdedfgh1234.123456
Header record : FILE-edidc40: 20200602-123539 46082 /tmp/ah/srcfile
I have below code for the list of files in the current directory. I need to pass the python equivalent of below actions on unix files
head -1 file|cut -c 15-22
Output: 20200206 (to compare with current date and if older than 30) then delete file(using rm command).
import os
def files in os.listdir(path):
for files in os.listdir(path):
if os.path.isfile(os.path.join(path,file)):
yield file
for file in files(".") : # prints the list of files
As per the code below I am having issues with the zipping a directory using the python 3 shutil.make_archive function. The .testdir will be zipped but it is being zipped in /home/pi, instead of /home/pi/Backups.
zip_loc = '/home/pi/.testdir'
zip_dest = '/home/pi/Backups/'
shutil.make_archive(zip_loc, 'zip', zip_dest)
Could anyone explain what I am doing wrong?
Reading the docs here I came up with:
zip_loc = '/home/pi/.testdir'
zip_dest = '/home/pi/Backups/'
shutil.make_archive(base_dir=zip_loc, root_dir=zip_loc, format='zip', base_name=zip_dest)
From the docs:
base_name is the name of the file to create, including the path, minus any format-specific extension.
root_dir is a directory that will be the root directory of the archive; for example, we typically chdir into root_dir before creating the archive.
base_dir is the directory where we start archiving from; i.e. base_dir will be the common prefix of all files and directories in the archive.
root_dir and base_dir both default to the current directory.
Before to write the archive, move to the good directory :
old_path = os.getcwd()
os.chdir(path)
-> write the archive
After writing the archive move back to old directory :
os.chdir(old_path)
Suppose I am standing on a directory. Inside there's another directory called inside_dir containing a huge number of files. I want to create a file containing a list of all the files inside inside_dir, listed as the relative path to the files. That is, if there is a file called file1 inside inside_dir, the corresponding line in the list file should be inside_dir/file1.
Since the number of files is huge, just doing ls inside_dir/* > list.txt won't work because it will complain about having too many arguments.
find inside_dir -type f > list.txt
I am working on a search-and-destroy type program which I need it to do is search all directories with a certain file-name and append them to a list. after that delete all those files...not objects in list or the list...
import os
file_list=[]
for root, dirs, files in os.walk(path-to-dir'):
for f_name in files:
if f_name.startswith("file-name"):
file_list.append(f_name)
I could write up to appending part of the code but I don't know next...
Some help please
To remove a file from your computer, use os.remove(). It takes full path to the file as it's parameter, so instead of calling os.remove("infectedFile.dll") you would call os.remove("C:/program files/avira/infectedFile.dll")
So your file_list should contain full paths to the files, and then just call:
for file in file_list:
os.remove(file)
Modify your file_list.append(f_name). The f_name is only a bare name. You need to add the path to the file name in the time of processing, because you do not know where the file was found in the directory hierarchy:
file_list.append(os.path.join(root, f_name))
The root variable contains the path during walking.
To make check whether your code works, just print the content of the list:
print('\n'.join(file_list))
Or you can do it in the loop to get ready for the later part:
for fname in file_list:
print(fname)
Then you just add the os.remove(fname) to remove the file name:
for fname in file_list:
print('removing', fname)
os.remove(fname)