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Simple question:
Is it currently possible to invoke LibreOffice from a command line to open a *.xlsx and convert/save it as a *.csv?
Alternatively, if this is not possible what is the current best method for doing this via command line (needs to be invokable via script)?
Thanks,
Here is the command:
localc --headless --convert-to csv:"Text - txt - csv (StarCalc)" *.xlsx
The above will save all converted files in current directory(directory from where you'll run the command). All converted files will have their filename extensions changed to csv.
Alternative, method is the use of unoconv which i've not used.
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Write a program to open the file and delete a specific line from a text file. The line number of the line to be replaced is asked as input. A new file is opened in write mode named output.txt. The input file name should be input.txt and output file name should be output.txt.
someone please help me through it
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i have URL https://my.waves.com/:r:/documents%20-/csv%20upload that loaded the screen then show edc_data.csv
above file edc_data.csv file move unix Location(/equ/str/loaded)
can you please how to write shellscripts
Assuming your URL https://my.waves.com/:r:/documents%20-/csv%20upload is correct and links to a CSV file, you can use this script:
#!/bin/sh
curl -L 'https://my.waves.com/:r:/documents%20-/csv%20upload' > /equ/str/loaded/edc_data.csv
exit 0
This will download the file edc_data.csv and put it directly in /equ/str/loaded/.
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I have big markdown file. Is there any way to change /foo in my url by /bla. That is, I want to replace
[text](/foo/some-long-url/a.html)
for
[text](/bla/some-long-url/a.html)
(all ocurrences).
I know I could compile markdown file to html and use html parsers (like BeautifulSoup) to do that. But I want to do that, on the source file.
Prefered python or shell solutions.
I mean you can always replace "/foo" to "/bla" directly in the source using sed?
sed 's/\/foo/\/bla/' source.md >> destination.md
If it catches anything unwanted, you can just tweak the regular expression a bit to be more specific.
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I have log file for checking transactions, and I have error lines, so I need those error lines to be exported to a .csv file? is there any code using linux bash shell script can do this?
suppose your error lines consists ERROR.
then
grep "ERROR" errorfile.txt | tr -s '[:blank:]' ',' >> errorfile.csv
csv conversion is based on blank spaces to each cell.you can replace blank filter with anything
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I don't have .bashrc file, I want to create one but how? And what does a basic .bashrc file contains? I am on Linux Mint 12
I want to have a .bashrc file, because i have created a folder for virtualenv and I want to load virtualenvwrapper
Why do you want one if you don't know what to put in there? You only need a .bashrc (or .profile or .bash_profile) if you actually have something you want to execute in every shell (or login shell).
But you can basically put any bash commands in those files.
A .bashrc file contains whatever default settings you want to use when you are using bash. If you don't have any particular preferences then leave it blank for now.
Typical contents of a .bashrc file includes aliases of commands you find yourself using a lot.