How to use the case statement to call functions? - linux

Question

Hi I have used this code to find the .java file from the given path and generate the list of the .java files from the path to output file,and count total number of tabs and spaces in each java file.now i need to write the two while loops in function and call that function in case statement, how to do this?
Code:
#!/bin/sh
#
output=/home/user/Desktop/file-list.txt
path=/home/user/Desktop
find $path -type f -name \*.java > $output
echo "Generating files list..."
echo "Done"
while IFS= read file
do
if [ -f "$file" ]; then
spaces=$(tr -cd '\s' < "$file" | wc -c);
echo "$spaces spaces in file $file" >> "/home/user/Desktop/space-count.txt"
fi
done < "$output"
echo "Space Count Done!"
while IFS= read file
do
if [ -f "$file" ]; then
tabs=$(tr -cd '\t' < "$file" | wc -c);
echo "$tabs tabs in file $file" >> "/home/user/Desktop/tab-count.txt"
fi
done < "$output"
echo "Tab Count Done!"

Answer 1

Here is an example of case, but the name of the character could be passed to the function
thereby eliminating the need to case the char.
function count_char
{
flist=$1
ch=$2
case $ch in
" ") chName=space;;
"\t") chName=tab;;
esac
while IFS= read file
do
if [ -f "$file" ]; then
tot=$(tr -cd $ch < "$file" | wc -c);
echo "$tot $chName in file $file" >> "/home/user/Desktop/tab-count.txt"
fi
done < "$flist"
}
# setup code, find command here
# ....
count_char $output " "
count_char $output "\t"