I have a string (eg. 'STA') and I want to make a cell array that will be a concatenation of my sting with a numbers from 1 to X.
I want the code to do something like the fore loop here below:
for i = 1:Num
a = [{a} {strcat('STA',num2str(i))}]
end
I want the end results to be in the form of {<1xNum cell>}
a = 'STA1' 'STA2' 'STA3' ...
(I want to set this to a uitable in the ColumnFormat array)
ColumnFormat = {{a},... % 1
'numeric',... % 2
'numeric'}; % 3
I'm not sure about starting with STA1, but this should get you a list that starts with STA (from which I guess you could remove the first entry).
N = 5;
[X{1:N+1}] = deal('STA');
a = genvarname(X);
a = a(2:end);
You can do it with combination of NUM2STR (converts numbers to strings), CELLSTR (converts strings to cell array), STRTRIM (removes extra spaces)and STRCAT (combines with another string) functions.
You need (:) to make sure the numeric vector is column.
x = 1:Num;
a = strcat( 'STA', strtrim( cellstr( num2str(x(:)) ) ) );
As an alternative for matrix with more dimensions I have this helper function:
function c = num2cellstr(xx, varargin)
%Converts matrix of numeric data to cell array of strings
c = cellfun(#(x) num2str(x,varargin{:}), num2cell(xx), 'UniformOutput', false);
Try this:
N = 10;
a = cell(1,N);
for i = 1:N
a(i) = {['STA',num2str(i)]};
end
Related
I have two string arrays and I want to find where each string from the first array is in the second array, so i tried this:
for i = 1:length(array1);
cmp(i) = strfind(array2,array1(i,:));
end
This doesn't seem to work and I get an error: "must be one row".
Just for the sake of completeness, an array of strings is nothing but a char matrix. This can be quite restrictive because all of your strings must have the same number of elements. And that's what #neerad29 solution is all about.
However, instead of an array of strings you might want to consider a cell array of strings, in which every string can be arbitrarily long. I will report the very same #neerad29 solution, but with cell arrays. The code will also look a little bit smarter:
a = {'abcd'; 'efgh'; 'ijkl'};
b = {'efgh'; 'abcd'; 'ijkl'};
pos=[];
for i=1:size(a,1)
AreStringFound=cellfun(#(x) strcmp(x,a(i,:)),b);
pos=[pos find(AreStringFound)];
end
But some additional words might be needed:
pos will contain the indices, 2 1 3 in our case, just like #neerad29 's solution
cellfun() is a function which applies a given function, the strcmp() in our case, to every cell of a given cell array. x will be the generic cell from array b which will be compared with a(i,:)
the cellfun() returns a boolean array (AreStringFound) with true in position j if a(i,:) is found in the j-th cell of b and the find() will indeed return the value of j, our proper index. This code is more robust and works also if a given string is found in more than one position in b.
strfind won't work, because it is used to find a string within another string, not within an array of strings. So, how about this:
a = ['abcd'; 'efgh'; 'ijkl'];
b = ['efgh'; 'abcd'; 'ijkl'];
cmp = zeros(1, size(a, 1));
for i = 1:size(a, 1)
for j = 1:size(b, 1)
if strcmp(a(i, :), b(j, :))
cmp(i) = j;
break;
end
end
end
cmp =
2 1 3
I have two lists of strings as a column in a table (PM25_spr{i}.MonitorID and O3_spr{i}.MonitorID). The lists are of different lengths. I want to compare the first 11 characters of each entry and pull out the index for each list where they are the same.
Example
List 1:
'01-003-0010-44201'
'01-027-0001-44201'
'01-051-0001-44201'
'01-073-0023-44201'
'01-073-1003-44201'
'01-073-1005-44201'
'01-073-1009-44201'
'01-073-1010-44201'
'01-073-2006-44201'
'01-073-5002-44201'
'01-073-5003-44201'
'01-073-6002-44201'
List 2:
'01-073-0023-88101'
'01-073-2003-88101'
'04-013-0019-88101'
'04-013-9992-88101'
'04-013-9997-88101'
'05-119-0007-88101'
'05-119-1008-88101'
'06-019-0008-88101'
'06-029-0014-88101'
'06-037-0002-88101'
'06-037-1103-88101'
'06-037-4002-88101'
'06-059-0001-88101'
'06-065-8001-88101'
'06-067-0010-88101'
'06-073-0003-88101'
'06-073-1002-88101'
'06-073-1007-88101'
'08-001-0006-88101'
'08-031-0002-88101'
I tried intersect, which isn't the right approach for what I want to do. I'm not sure how to use ismember given that I only want to look at the first 11 characters.
I tried strncmp, but Inputs must be the same size or either one can be a scalar.
chars2compare = length('18-097-0083');
strncmp(O3_spr{i}.MonitorID, PM25_spr{i}.MonitorID,chars2compare)
PM25_spr_MID = cell(length(years),1); % Preallocate cell array
for n = 1:length(PM25_spr{i}.MonitorID)
s = char(PM25_spr{i}.MonitorID(n)); % Convert string to char
PM25_spr_MID{i}(n) = cellstr(s(1:11)); % Pull out 1-11 characters and convert to cell
end
O3_spr_MID = cell(length(years),1); % Preallocate cell array
for n = 1:length(O3_spr{i}.MonitorID)
s = char(O3_spr{i}.MonitorID(n));
O3_spr_MID{i}(n) = cellstr(s(1:11));
end
[C, ia, ib] = intersect(O3_spr_MID{i}, PM25_spr_MID{i})
PerCap_spr_O3{i} = O3_spr{i}(ia,:);
PerCap_spr_PM25{i} = PM25_spr{i}(ib,:);
Assuming list1 and list2 to be the two input cell arrays, you can use few approaches.
I. Operate on cell arrays
With intersect -
%// Clip off after first 11 characters in each cell of the input cell arrays
list1_f11 = arrayfun(#(n) list1{n}(1:11),1:numel(list1),'uni',0)
list2_f11 = arrayfun(#(n) list2{n}(1:11),1:numel(list2),'uni',0)
%// Use intersect to find common indices in the input cell arrays
[~,idx_list1,idx_list2] = intersect(list1_f11,list2_f11)
With ismember -
%// Clip off after first 11 characters in each cell of the input cell arrays
list1_f11 = arrayfun(#(n) list1{n}(1:11),1:numel(list1),'uni',0)
list2_f11 = arrayfun(#(n) list2{n}(1:11),1:numel(list2),'uni',0)
%// Use ismember to find common indices in the input cell arrays
[LocA,LocB] = ismember(list1_f11,list2_f11);
idx_list1 = find(LocA)
idx_list2 = LocB(LocA)
II. Operate on char arrays
We can use char dierctly on the input cell arrays to get 2D char arrays as working with them could be faster than working withcells.
With intersect + 'rows' -
%// Convert to char arrays
list1c = char(list1)
list2c = char(list2)
%// Clip char arrays after first 11 columns
list1c_f11 = list1c(:,1:11)
list2c_f11 = list2c(:,1:11)
%// Use intersect with 'rows' option
[~,idx_list1,idx_list2] = intersect(list1c_f11,list2c_f11,'rows')
III. Operate on numeric arrays
We can convert the char arrays further to numeric arrays with just one column as that could lead to faster solutions.
%// Convert to char arrays
list1c = char(list1)
list2c = char(list2)
%// Clip char arrays after first 11 columns
list1c_f11 = list1c(:,1:11)
list2c_f11 = list2c(:,1:11)
%// Remove char columns of hyphens (3 and 7 for the given input)
list1c_f11(:,[3 7])=[];
list2c_f11(:,[3 7])=[];
%// Convert char arrays to numeric arrays
ncols = size(list1c_f11,2);
list1c_f11num = (list1c_f11 - '0')*(10.^(ncols-1:-1:0))'
list2c_f11num = (list2c_f11 - '0')*(10.^(ncols-1:-1:0))'
This point onwards you have three more approaches to work with that are listed next.
With ismember ( would be memory efficient, but maybe not fast across all datasizes) -
[LocA,LocB] = ismember(list1c_f11num,list2c_f11num);
idx_list1 = find(LocA)
idx_list2 = LocB(LocA)
With intersect (could be slow) -
[~,idx_list1,idx_list2] = intersect(list1c_f11num,list2c_f11num)
With bsxfun ( would be memory inefficient, but maybe fast for small to decent sized inputs) -
[idx_list1,idx_list2] = find(bsxfun(#eq,list1c_f11num,list2c_f11num'))
I have an cell array composed by several strings
names = {'2name_19surn', '3name_2surn', '1name_2surn', '10name_1surn'}
and I would like to sort them according to the prefixnumber.
I tried
[~,index] = sortrows(names.');
sorted_names = names(index);
but I get
sorted_names = {'10name_1surn', '1name_2surn', '2name_19surn', '3name_2surn'}
instead of the desired
sorted_names = {'1name_2surn', '2name_19surn', '3name_2surn','10name_1surn'}
any suggestion?
Simple approach using regular expressions:
r = regexp(names,'^\d+','match'); %// get prefixes
[~, ind] = sort(cellfun(#(c) str2num(c{1}), r)); %// convert to numbers and sort
sorted_names = names(ind); %// use index to build result
As long as speed is not a concern you can loop through all strings and save the first digets in an array. Subsequently sort the array as usual...
names = {'2name_2', '3name', '1name', '10name'}
number_in_string = zeros(1,length(names));
% Read numbers from the strings
for ii = 1:length(names)
number_in_string(ii) = sscanf(names{ii}, '%i');
end
% Sort names using number_in_string
[sorted, idx] = sort(number_in_string)
sorted_names = names(idx)
Take the file sort_nat from here
Then
names = {'2name', '3name', '1name', '10name'}
sort_nat(names)
returns
sorted_names = {'1name', '2name', '3name','10name'}
You can deal with arbitrary patterns using a regular expression:
names = {'2name', '3name', '1name', '10name'}
match = regexpi(names,'(?<number>\d+)\D+','names'); % created with regex editor on rubular.com
match = cell2mat(match); % cell array to struct array
clear numbersStr
[numbersStr{1:length(match)}] = match.number; % cell array with number strings
numbers = str2double(numbersStr); % vector of numbers
[B,I] = sort(numbers); % sorted vector of numbers (B) and the indices (I)
clear namesSorted
[namesSorted{1:length(names)}] = names{I} % cell array with sorted name strings
I've a string like this "FBECGHD" and i need to use MATLAB and generate all the required possible permutations? In there a specific MATLAB function that does this task or should I define a custom MATLAB function that perform this task?
Use the perms function. A string in matlab is a list of characters, so it will permute them:
A = 'FBECGHD';
perms(A)
You can also store the output (e.g. P = perms(A)), and, if A is an N-character string, P is a N!-by-N array, where each row corresponds to a permutation.
If you are interested in unique permutations, you can use:
unique(perms(A), 'rows')
to remove duplicates (otherwise something like 'ABB' would give 6 results, instead of the 3 that you might expect).
As Richante answered, P = perms(A) is very handy for this. You may also notice that P is of type char and it's not convenient to subset/select individual permutation. Below worked for me:
str = 'FBECGHD';
A = perms(str);
B = cellstr(reshape(A,7,[])');
C = unique(B);
It also appears that unique(A, 'rows') is not removing duplicate values:
>> A=[11, 11];
>> unique(A, 'rows')
ans =
11 11
However, unique(A) would:
>> unique(A)
ans =
11
I am not a matlab pro by any means and I didn't investigate this exhaustively but at least in some cases it appears that reshape is not what you want. Notice that below gives 999 and 191 as permutations of 199 which isn't true. The reshape function as written appears to operate "column-wise" on A:
>> str = '199';
A = perms(str);
B = cellstr(reshape(A,3,[])');
C = unique(B);
>> C
C =
'191'
'199'
'911'
'919'
'999'
Below does not produce 999 or 191:
B = {};
index = 1;
while true
try
substring = A(index,:);
B{index}=substring;
index = index + 1;
catch
break
end
end
C = unique(B)
C =
'199' '919' '991'
What is the quickest way to create an empty cell array of strings ?
cell(n,m)
creates an empty cell array of double.
How about a similar command but creating empty strings ?
Depends on what you want to achieve really. I guess the simplest method would be:
repmat({''},n,m);
Assignment to all cell elements using the colon operator will do the job:
m = 3; n = 5;
C = cell(m,n);
C(:) = {''}
The cell array created by cell(n,m) contains empty matrices, not doubles.
If you really need to pre populate your cell array with empty strings
test = cell(n,m);
test(:) = {''};
test(1,:) = {'1st row'};
test(:,1) = {'1st col'};
This is a super old post but I'd like to add an approach that might be working. I am not sure if it's working in an earlier version of MATLAB. I tried in 2018+ versions and it works.
Instead of using remat, it seems even more convenient and intuitive to start a cell string array like this:
C(1:10) = {''} % Array of empty char
And the same approach can be used to generate cell array with other data types
C(1:10) = {""} % Array of empty string
C(1:10) = {[]} % Array of empty double, same as cell(1,10)
But be careful with scalers
C(1:10) = {1} % an 1x10 cell with all values = {[1]}
C(1:10) = 1 % !!!Error
C(1:10) = '1' % !!!Error
C(1:10) = [] % an 1x0 empty cell array