I wrote the following line:
string QuoteTest2 = "Benjamin Netnayahu,\"BB\", said that: \"Israel will not fall\"";
This example went well, but what can I do in case I want to write a multi paragraph string including quotes?
The following example shows that puting '#' before the doesn't cut it..
string QuoteTest2 = #"Benjamin Netnayahu,\"BB\", said that: \"Israel will not fall\"";
The string ends and the second quote and the over just gives me errors, what should I do?
Use double quotes to escape ""
e.g.
string QuoteTest2 = #"Benjamin Netnayahu,""BB"", said that: ""Israel will not fall""";
Related
I am trying to replace single quote in a string with double quote using replace function with data factory expressions.
For example, replace single quote in the following string
hello'world ---> hello''world
#replace(pipeline().parameters.tst,''','''')
The above code is not working. Need help in fixing the code
You can declare a new parameter with the value ' (single quote). You can look at the following demonstration for reference.
I have taken 2 parameters, text with the value hello'world and replace_char with the value '.
I used a set variable activity to store the output of the replace() function (for demonstration) into variable named output (String). Now, I modified the value as:
#replace(pipeline().parameters.text,pipeline().parameters.replace_char,'"')
This successfully helps in replacing a single quote with double quote character.
NOTE: The \ in the output variable value indicates that the " is to be considered as a character inside the string value.
Use two single quotes to escape a ' character in string functions.
For example, expression #concat('Baba', '''s ', 'book store') will return below result.
Baba's book store
https://learn.microsoft.com/en-us/azure/data-factory/control-flow-expression-language-functions#escaping-single-quote-character
I have a string value with an apostrophe like this:
"I\\xE2\\x80\\x99m going now."
How can I get correct apostrophe value?
"I`m going now."
As you know, \xE2\x80\x99 is the a unicode character U+2019 RIGHT SINGLE QUOTATION MARK, but I have a string representation instead of byte...
Perhaps this is what you want:
utf8_apostrophe = b'\xe2\x80\x99'.decode("utf8")
str = "I"+utf8_apostrophe+"m going now"
Aside:
I ran into this when converting a single quotation mark, within a UTF-8-encoded tweet, into a normal single quote.
import re
original_tweet = 'I’m going now'
string_apostrophe = "'"
print re.sub(utf8_apostrophe, string_apostrophe, original_tweet)
which produces
I'm going now
In Azure logic Apps, how can I escape single quotes(') using a replace function?
I have a JSON payload where I have to replace a single quote(') with a double quote(").
The expression I've came up with looks like this:
replace(string(#triggerBody()),'/' ','/" ')
But my second expression to escape the single quote (') isn't working.
I resolved this by using a double single quotation, '' thanks to this link
Summary for single and doubt quotes sharing with others.
String containing single quote ', use extra single quote to escape:
''
String containing double quotes ", prefix with a forward slash to escape:
\"
Original json (posted from postman):
{
"name": "single''dds double\"te",
"email": "special signle and double quotes",
"password": "pp#pp"
}
console.log result in sql query in Nodejs environment:
INSERT INTO ztestTbl(name, email, passowrd) VALUES (N'single''dds double"te', N'special signle and double quotes', N'pp#pp')
String insert into the mssql db:
single'dds double"te
This is now you do it. You need 2 single quotes inside the single quote
#replace(string(triggerBody()),'''' ','\" ')
Try this:
#replace(string(triggerBody()),''' ','\" ')
HTH
I had problem escaping single quote in query parameter concat. I resolved it by used double quote. Thanks to tips in this post.
concat('**Text1**', ''**'**' , '**text2**',''**'**')
resulted in :
Text1'text2'
Take a note of four single quotes.
I am trying to clean text strings containing any ' or ' (which includes an ; but if i add it here you will see just ' again. Because the the ANSI is also encoded by stackoverflow. The string content contains ' and when it does there is an error.
when i insert the string to my database i get this error:
psycopg2.ProgrammingError: syntax error at or near "s"
LINE 1: ...tment and has commenced a search for mr. whitnell's
the original string looks like this:
...a search for mr. whitnell's...
To remove the ' and ' ; I use:
stripped_content = stringcontent.replace("'","")
stripped_content = stringcontent.replace("' ;","")
any advice is welcome, best regards
When you try to replace("' ;","") it literally searching for "' ;" occurrences in string. You need to convert "' ;" to its character equivalent. Try this:
s = "That's how we 'roll"
r = s.replace(chr(int('''[2:])), "")
and with this chr(int('''[2:])) you'll get ' character.
Output:
Thats how we roll
Note
If you try to run this s.replace(chr(int('''[2:])), "") without saving your result in variable then your original string would not be affected.
I'm trying to read a string in a specific format
RealSociedad
this is one example of string and what I want to extract is the name of the team.
I've tried something like this,
houseteam = sscanf(str, '%s');
but it does not work, why?
You can use regexprep like you did in your post above to do this for you. Even though your post says to use sscanf and from the comments in your post, you'd like to see this done using regexprep. You would have to do this using two nested regexprep calls, and you can retrieve the team name (i.e. RealSociedad) like so, given that str is in the format that you have provided:
str = 'RealSociedad';
houseteam = regexprep(regexprep(str, '^<a(.*)">', ''), '</a>$', '')
This looks very intimidating, but let's break this up. First, look at this statement:
regexprep(str, '^<a(.*)">', '')
How regexprep works is you specify the string you want to analyze, the pattern you are searching for, then what you want to replace this pattern with. The pattern we are looking for is:
^<a(.*)">
This says you are looking for patterns where the beginning of the string starts with a a<. After this, the (.*)"> is performing a greedy evaluation. This is saying that we want to find the longest sequence of characters until we reach the characters of ">. As such, what the regular expression will match is the following string:
<ahref="/teams/spain/real-sociedad-de-futbol/2028/">
We then replace this with a blank string. As such, the output of the first regexprep call will be this:
RealSociedad</a>
We want to get rid of the </a> string, and so we would make another regexprep call where we look for the </a> at the end of the string, then replace this with the blank string yet again. The pattern you are looking for is thus:
</a>$
The dollar sign ($) symbolizes that this pattern should appear at the end of the string. If we find such a pattern, we will replace it with the blank string. Therefore, what we get in the end is:
RealSociedad
Found a solution. So, %s stops when it finds a space.
str = regexprep(str, '<', ' <');
str = regexprep(str, '>', '> ');
houseteam = sscanf(str, '%*s %s %*s');
This will create a space between my desired string.