Startup script with systemd in Linux - linux

Question

Can I do This start up service below, there are no errors showing once run, but the server script below does not run!
ln /lib/systemd/aquarium.service aquarium.service
systemctl daemon-reload
systemctl enable aquarium.service
systemctl start aquarium.service
thanks
aquarium.service:
[Unit]
Description=Start aquarium server
[Service]
WorkingDirectory=/home/root/python/code/aquarium/
ExecStart=/bin/bash server.* start
KillMode=process
[Install]
WantedBy=multi-user.target
here is the server.sh script
#!/bin/bash
PID=""
function get_pid {
PID=`pidof python ./udpthread.py`
}
function stop {
get_pid
if [ -z $PID ]; then
echo "server is not running."
exit 1
else
echo -n "Stopping server.."
kill -9 $PID
sleep 1
echo ".. Done."
fi
}
function start {
get_pid
if [ -z $PID ]; then
echo "Starting server.."
./udpthread.py &
get_pid
echo "Done. PID=$PID"
else
echo "server is already running, PID=$PID"
fi
}
function restart {
echo "Restarting server.."
get_pid
if [ -z $PID ]; then
start
else
stop
sleep 5
start
fi
}
function status {
get_pid
if [ -z $PID ]; then
echo "Server is not running."
exit 1
else
echo "Server is running, PID=$PID"
fi
}
case "$1" in
start)
start
;;
stop)
stop
;;
restart)
restart
;;
status)
status
;;
*)
echo "Usage: $0 {start|stop|restart|status}"
esac

Answer 1

Try using "Type=forking" and use complete filename.
[Unit]
Description=Start aquarium server
[Service]
WorkingDirectory=/home/root/python/code/aquarium/
Type=forking
ExecStart=/bin/bash server.sh start
KillMode=process
[Install]
WantedBy=multi-user.target
if it not work, post output of this command:
# journalctl -u aquarium.service