I need a script that will do the following, but have no idea how to approach the idea.
Recursively scan a directory /home/root/multicraft/servers finding all files named "server.properties"
Edit the file replacing "view-distance=(a number here)" with "view-distance=4"
How would I go about doing this?
You can use find to recursively go through directories. It can execute a command via -exec. To edit the file, you can use sed:
find /home/root/multicraft/servers \
-name server.properties \
-exec sed -i~ 's/view-distance=[0-9]\+/view-distance=4/' {} \;
try this:
find /home/root/multicraft/servers -name "server.properties"|xargs sed -ri 's/(view-distance)=[0-9]+/\1=4/'
making backup before trying it.
Related
Please help me with advice
I need to go through the files in this $tmp directory and make substitutions in the lines according to the rule described in sed
I trained on one file and this sed worked it out normally.
But when I perform a replacement in for , I get some nonsense on the output
for file in $tmp/*.txt; do
find $tmp/ -type f -name "*.txt" -exec sed -i -e 's/, /\n''/g; s/"//g; s/$/\x0A/; s/:[ ]/;/g; s/\n''/;\n''/g; s/^[ t]*//' {} \;
done
How can I fix it?
Thanks…
UP
I did it.
find - It was really unnecessary
#Rob Sweet Thanks!
You don't need the for loop AND the find command. Both essentially do the same thing, which is to iterate through all the files in /tmp that match *.txt.
When you don't need to edit files in a subdir of /tmp, than give sed all files in once.
sed -i your_command *.txt
Off topic:
I don't understand your sed command. Why two single quotes? When you want to replace a newline, consider option -z.
I am trying to find the whole source code for occurrences of, say, "MY_NAME" and want to replace it with, say, "YOUR_NAME". I already know the files and the line numbers where they occur and i want to make a patch for the same so that anyone running the patch can do the same. Can anyone please help?
You can do it by console. Just use find to locate destination files, and then you can declare what you want to replace with what sentence. In example:
find -name '*' | xargs perl -pi -e 's/MY_NAME/YOUR_NAME/g'
It might be easier to do a sed command, and then generate a patch.
sed -e '12s/MY_NAME/YOUR_NAME/g;32s/MY_NAME/YOUR_NAME/g' file > file2
This will replace MY_NAME with YOUR_NAME on lines 12 and 32, and save the output into file2.
You can also generate a sed script if there are many changes:
#!/bin/sed -f
12s/MY_NAME/YOUR_NAME/g
32s/MY_NAME/YOUR_NAME/g
Then, for applying to many files, you should use find:
find -type f '(' -iname "*.c" -or -iname "*.h" ')' -exec "./script.sed" '{}' \;
Hope this helps =)
Use the command diff to create a patch-file that can then be distributed and applied with the patch-command.
man diff Will give you a lot of information on the process.
I need to traverse a directory so starting in one directory and going deeper into difference sub directories. However I also need to be able to have access to each individual file to modify the file. Is there already a command to do this or will I have to write a script? Could someone provide some code to help me with this task? Thanks.
The find command is just the tool for that. Its -exec flag or -print0 in combination with xargs -0 allows fine-grained control over what to do with each file.
Example: Replace all foo's by bar's in all files in /tmp and subdirectories.
find /tmp -type f -exec sed -i -e 's/foo/bar/' '{}' ';'
for i in `find` ; do
if [ -d $i ] ; then do something with a directory ; fi
if [ -f $i ] ; then do something with a file etc. ; fi
done
This will return the whole tree (recursively) in the current directory in a list that the loop will go through.
This can be easily achieved by mixing find, xargs, sed (or other file modification command).
For example:
$ find /path/to/base/dir -type f -name '*.properties' | xargs sed -ie '/^#/d'
This will filter all files with file extension .properties.
The xargs command will feed the file path generated by find command into the sed command.
The sed command will delete all lines start with # in the files (feed by xargs).
Command combination in this way is very flexible.
For example, find command have different parameters so you can filter by user name, file size, file path (eg: under /test/ subfolder), file modification time.
Another dimension of flexibility is how and what to change in your file. For ex, sed command allows you to make changes on file in applying substitution (specify via regular expressions). Similarly, you can use gzip to compress the file. And so on ...
You would usually use the find command. On Linux, you have the GNU version, of course. It has many extra (and useful) options. Both will allow you to execute a command (eg a shell script) on the files as they are found.
The exact details of how to make changes to the file depend on the change you want to make to the file. That is probably best scripted, with find running the script:
POSIX or GNU:
find . -type f -exec your_script '{}' +
This will run your script once for a group of files with those names provided as arguments. If you want to do it one file at a time, replace the + with ';' (or \;).
I am assuming SearchMe is the example directory name you need to traverse completely.
I am also assuming, since it was not specified, the files you want to modify are all text file. Is this correct?
In such scenario I would suggest using the command:
find SearchMe -type f -exec vi {} \;
If you are not familiar with vi editor, just use another one (nano, emacs, kate, kwrite, gedit, etc.) and it should work as well.
Bash 4+
shopt -s globstar
for file in **
do
if [ -f "$file" ];then
# do some processing to your file here
# where the find command can't do conveniently
fi
done
There are some folder that contains space, and as a result, those folders can not be indexed using cscope.
Can i ask you for help to solve this,or any suggestion.
thanks
Julius
Thanks for your reply.
My steps to use cscope like the following
find . -name '*.scala'>cscope.files
cscope -b
at this step. i see the message indicates that can not find file:
cscope: cannot find file /work/project/copy
cscope: cannot find file of
cscope: cannot find file fp/src/main/jav....
Actually copy of fp is a folder.so i think cscope can not recognize the folder contains space.
I encountered this problem when i tried to use vim with cscope.maybe i need move this question to other tag.
You can do it simply using GNU find at least, you can use the -printf or -fprintf options for that:
find . -type f -fprintf cscope.files '"%p"\n'
pydave's answer is very slow. This way took 0.10s where pydave's answer took 14s:
find . -name "*.scala" | awk '{print "\""$0"\""}' > cscope.files
You can use find's -exec to force quotes around your output:
find . -name "*.scala" -exec echo \"{}\" \; > cscope.files
You might need to mess around with quoting/escaping if you're doing this from a script.
Double quoting the files names works in cygwin, where as escaping with backslash does not.
$ find $PWD -name "*.scala" | sed -e 's/^/"/g' -e 's/$/"/g' > cscope.files
So, How Do I find and copy all files,
*.a
that are in,
~/DIR{1,2,3,...}
to
~/tmp/foo?
Assumed you meant recursively copy everything of type .a from some source location.
Haven't verified yet, but this should do that.
find <root-of-search> -type f -name '*.a' -exec cp {} /tmp/foo \;
replace with the top of wherever you want to search from. You might have to throw quotes around *.a, and you might have to replace escape the ending semicolon by putting it in single quotes rather than back-slashing it.
In a bash shell:
cp ~/DIR*/*.a ~/tmp/foo
find ~/DIR{1,2,...} -name *.a print0 | xargs -i -0 cp '{}' ~/tmp/foo