Vlookup and get the min value (date) - excel

Question

TOP Table is Input, and bottom table is preview for required output.
For Each ID I need to find earliest datetime. I also need other information from other columns (please see image below).
My current solution is:
In Cell E2 =A2
Cell E3 drag down =IF(E2<>A3,IF(E1=A3,"",A3),"")
In Cell F2 drag down =IF(E2<>"",MIN(IF($A$2:$A$14=E2,$C$2:$C$14)),"") Ctrl+Shift+Enter

Answer 1

One more option without any intermediate calculations:
Select the whole range starting E2 and to the last row where IDs are located - for the sample given it's row 14, so select range E2:E14: =IFERROR(INDEX($A$2:$A$14,SMALL(IF(MATCH($A$2:$A$14,$A$2:$A$14,0)=ROW(INDIRECT("1:"&ROWS($A$2:$A$14))),MATCH($A$2:$A$14,$A$2:$A$14,0),""),ROW(INDIRECT("1:"&ROWS($A$2:$A$14))))),"") and press CTRL+SHIFT+ENTER instead of usual ENTER - this will define a Multicell ARRAY formula and will result in curly {} brackets around it (but do NOT type them manually!).
F2 (ID2): =IF(E2="","",SUMPRODUCT(--(E2=$A$2:$A$14),--(G2=$C$2:$C$14),$B$2:$B$14)) - normal formula.
G2 (Min Date): =IF(E2="","",MIN(IF(E2=$A$2:$A$14,$C$2:$C$14,2^100))) and press CTRL+SHIFT+ENTER instead of usual ENTER - this will define an ARRAY formula and will result in curly {} brackets around it (but do NOT type them manually!).
H2 (InCh): =IF(E2="","",INDEX($D$2:$D$14,SUMPRODUCT(--(E2=$A$2:$A$14),--(F2=$B$2:$B$14),--(G2=$C$2:$C$14),ROW(INDIRECT("1:"&ROWS($D$2:$D$14)))))) - normal formula.
Remarks:
To make the solution more compact and easy to read, define named range for ID column, and then reference other data columns using OFFSET.
ID2 values may not be unique - as they are on the sample for IDs 1...3.
Resulting set for Min Date should be formatted the same way as source Date row.
The key formula of the solution - is multicell monster which returns unique IDs without empty rows - as OP requested)
Sample file: https://www.dropbox.com/s/d2098updfh8djnf/MinDateIDs.xlsx

Answer 2

This is quite a challenge... I think I have found an approach that works. For the sake of clarity, I used a few helper columns. Also, I did not use any named ranges but stuck with the column-row indications. You might want to change that.
It looks like this:
and zooming in to the relevant columns:
Column F contains an array formula to filter out duplicates. An approach is explained here. The formula I used in F2 is
=INDEX($A$2:$A$14, MATCH(MIN(IF(COUNTIF($F$1:F1,$A$2:$A$14)=0, 1, MAX((COUNTIF($A$2:$A$14, "<"&$A$2:$A$14)+1)*2))*(COUNTIF($A$2:$A$14, "<"&$A$2:$A$14)+1)), COUNTIF($A$2:$A$14, "<"&$A$2:$A$14)+1, 0))
Use Ctrl-Shift-Enter to confirm as array formula. Drag this down or copy into column F. Then columns G and H contain the starting and ending indices of the duplicate ID values. This answer helped, please upvote it :-). The two formulas used are:
=MATCH(2,1/FREQUENCY($F2,$A$2:$A$14))
in G2, and
=FREQUENCY($A$2:$A$14,$F2)
in H2. Again, drag them down to get the full column filled. Next, column I is for clarification only -- and for sanity checking. It contains the desired minimum date from each sub-array. Column J substitutes that formula into a MATCH to find the actual index of the desired date.
=MIN(OFFSET($C$2:$C$14,$G2-1,0,1+$H2-$G2,1))
in I2 and
=$G2-1+MATCH(2,1/FREQUENCY(MIN(OFFSET($C$2:$C$14,$G2-1,0,1+$H2-$G2,1)), OFFSET($C$2:$C$14,$G2-1,0,1+$H2-$G2,1))
in J2. Finally, columns L, M and N index into the original set of data via
=INDEX(B$2:B$14,$J2)
in L2, which you can drag horizontally and then vertically.
When you are done, you can hide the helper columns, or fold everything into big formulas. Good luck with that... There might be an easier way to achieve this, but I did not find it.

Answer 3

If you want the value from column D in G then assuming that column C values are unique you could just use a VLOOKUP, i.e. in G2 copied down
=VLOOKUP(F2,C$2:D$14,2,0)

Answer 4

Per your picture, they're all in the same sheet. Just sort by ID, then Date (ascending). As you work your way down the ID column, each time the ID changes, you know you've found the row with the minimum Date for that specific ID. Create an extra column to signify where ID changes occur, and filter for those rows (hide the column if you so desire).
And... voila.

Answer 5

Know this link is old, but there is a much shorter and easier way!
How about using a pivot table using the Minimum as field setting and then do a =GETPIVOTDATA() to get the information back!
Seems a lot simpler as these formulas!

Answer 6

Actually, I just realized I've been overthinking this...Excel keeps the top item and removes all that follow when removing duplicates.
So if you are going to create an extra working table anyway, why not just copy the range/columns you want to keep, then use the basic sort.
Sort first by ID, then by the column you want as the second filter. Be sure the sorts are in the order you want (e.g. newest to oldest, oldest to newest, A to Z, Largest to smallest, etc).
Once the data is sorted, remove duplicates based on ID. You are left with all of your columns of data, filtered by newest/oldest/largest/smallest per individual.
This worked for my table with 30,000+ records, filtered down to 1500 unique individuals with most recent (plus associated amount), and with a second filter, the largest (plus associated date) for each person.