Adding Try and Catch to existing program - c#-4.0

Question

Good Evening all,
In a little of a pickle with a huge brain fart and could use a little help with something. So i wrote this C# console app that uses Selenium to open a web page, logs in, does some stuff, then submit a form and logs off the site. Now I have this in a for loop to do it 100 times. Now very rarely it may hiccup and throws an exception cause page didn't load fast enough or something. I thought it may be good to use a try/catch but once as the catch catches the exception, but I want it to redo that loop number that it is on and continue on. So example, say if i am on iteration 66 of 100 and it throws an exception cause page didn't load fast enough or there was an error on the page for that link, i need it to catch it, log it, then restart at number 66 again. Below is some of my original code and another section of what i have gotten it to.
using System;
using System.Collections.Generic;
using System.Text;
using OpenQA.Selenium;
using OpenQA.Selenium.Firefox;
using OpenQA.Selenium.Support.UI;
using System.Threading;
using System.IO;
namespace SeleniumTest
{
class Program
{
static void Main(string[] args)
{
for (Int64 i = 1; i < 100; i++)
{
DateTime time;
time = DateTime.Now;
StreamWriter tw = new StreamWriter(#"C:\folder\file.txt", true);
IWebDriver driver = new FirefoxDriver();
tw.WriteLine("Staring test," + time);
driver.Navigate().GoToUrl("http://site.com");
driver.FindElement(By.Name("username")).Clear();
driver.FindElement(By.Name("username")).SendKeys("username");
driver.FindElement(By.Name("password")).Clear();
driver.FindElement(By.Name("password")).SendKeys("password");
driver.FindElement(By.CssSelector("input.ui-standard-button")).Click();
driver.FindElement(By.LinkText("page")).Click();
driver.FindElement(By.LinkText("page")).Click();
Thread.Sleep(5000);
//Do awesome stuff
DateTime time1;
time1 = DateTime.Now;
driver.FindElement(By.CssSelector("div.Parameters")).Click();
driver.FindElement(By.Name("submit")).Click();
driver.FindElement(By.LinkText("Logoff")).Click();
driver.Quit();
tw.WriteLine("Stopping Test Successfully," + time1);
tw.Flush();
tw.Close();
Thread.Sleep(10000);
}
}
}
}
using System;
using System.Collections.Generic;
using System.Text;
using OpenQA.Selenium;
using OpenQA.Selenium.Firefox;
using OpenQA.Selenium.Support.UI;
using System.Threading;
using System.IO;
namespace SeleniumTest
{
class Program
{
static void Main(string[] args)
{
try
{
for (Int64 i = 1; i < 100; i++)
{
DateTime time;
time = DateTime.Now;
StreamWriter tw = new StreamWriter(#"C:\folder\file.txt", true);
IWebDriver driver = new FirefoxDriver();
tw.WriteLine("Staring test," + time);
driver.Navigate().GoToUrl("http://site.com");
driver.FindElement(By.Name("username")).Clear();
driver.FindElement(By.Name("username")).SendKeys("username");
driver.FindElement(By.Name("password")).Clear();
driver.FindElement(By.Name("password")).SendKeys("password");
driver.FindElement(By.CssSelector("input.ui-standard-button")).Click();
driver.FindElement(By.LinkText("page")).Click();
driver.FindElement(By.LinkText("page")).Click();
Thread.Sleep(5000);
//Do awesome stuff
DateTime time1;
time1 = DateTime.Now;
driver.FindElement(By.CssSelector("div.Parameters")).Click();
driver.FindElement(By.Name("submit")).Click();
driver.FindElement(By.LinkText("Logoff")).Click();
driver.Quit();
tw.WriteLine("Stopping Test Successfully," + time1);
tw.Flush();
tw.Close();
Thread.Sleep(10000);
}
}
catch(Exception e)
{
StreamWriter tw = new StreamWriter(#"C:\folder\file.txt", true);
tw.WriteLine("Problem happened. Restarting test. Exception is :" + e);
//Line of code to restart test at number 66 which I don't know
}
}
}
}
Where //Line of code to restart test at number 66 which I don't know is where my knowledge ends and hopefully is where someone else is. Any guidance you can give would be great and appreciated.

Answer 1

Decrementing the counter when an exception is encountered should do it.
for (Int64 i = 1; i < 100; i++) {
try {
//main code here
} catch (Exception ex) {
//logging here
i--;
}
}

Answer 2

I would try to figure out why it's failing, but if that's not an option I would convert it to a while loop with a try catch
int i = 100;
while(i > 0)
{
try
{
//Do your logic here
i--
}
catch
{
//Log failure
}//Don't decrement in case of failure
}

Answer 3

for (Int64 i = 1; i < 100; ++i)
{
for (;;)
{
try
{
//code here
break;
}
catch (Exception exc)
{
//log error
}
}
}