I need to create a Class Diagram with some Model Packages. I have to use Visual Paradigm as modeling editor. The target I'm looking for is a diagram like this one:
My problem is the following: how to create a Class like the classes in this picture?
I'm trying with the default Class command:
but it's not what I'm looking for. The class name must be centered and without the separation line. How can I do this?
I have also tried with Rectangles and Text Boxes overlapped, but in this case I'm not able to draw associations between the classes.
Thanks in advance.
The solution is very simple: you have to hide all the class attributes and methods (thank you, clapas!)
Related
I am using Sparx Enterprise Architect and am somehow confused that I did not find any hint on the internet regarding the following question: How can I show the programming language of a component in the component diagram?
It is clear to me that I could use custom stereotypes but this is not a good idea as it prevents me from using "real" stereotypes later on.
The reason is simply that you can not show it using EA's GUI. You would need to stereotype the element and come up with a shape script to display the language with a
print("#language#");
somewhere.
To assign a shape script to a stereotype there are two ways, the quick and dirty and the difficult one. Here's the q&d one:
Under Configure/UML Types you can add a new 'wild' stereotype. That is one with no profile. EA will show that as <none> when applied. Think of a fitting name and choose Edit with the shape script:
Here can enter the new shape script (since this depends very much here's a simple one):
shape main {
Rectangle(0, 0, 100, 100);
println("#name#");
println("#language#");
}
Save the edit and close the dialog. Once you assign the stereotype to an element it will render like this:
I know this is not pretty and you need to dig into shape scripts to make it useful, but that can't be avoided.
So the difficult, but better and preferred, way is to create your own profile containing the stereotype along with the shape script. The above would just be a way of testing it but finally you would need to create your profile and put it in a MDG. Since this is a quite complex task it won't go here into this answer (no, I'm not Fermat, but you need quite some effort to get that far).
There is no standardized way to show the programming language of a component in UML. There are several ways you can do it, for example:
Stereotype. This will not prevent you from adding other stereotypes in the future. Multiple stereotypes are shown comma separated: «stereotype1, stereotype2»
Generalization. You can define a component called 'JavaComponent' and let all Java components inherit from this base component.
Note. You can attach a note to the component specifying the language.
I have a Text class. Objects of this class will have many versions. So there will be history of text changes.
How to indicate this on class diagram properly?
I need to show when it was changed and by who? Create class for text change? It is littlebit strange. Generalization?
Thanks for answer.
How's this diagram below? (I'm sorry if I am misunderstanding your description.)
Also, the Memento design pattern may help you.
So that I can connect them in my package diagram. I'm using eclipse as IDE by the way.
The package diagram does not have all elements of the class diagram. So, you'll have to include some class diagram elements into your toolbox or palette or what you have as a source of elements. It is allowed by the UML standard.
Or make it as a class or object diagram. There you have all class diagram elements and packages, too.
Either way you'll get something as:
I have a file very big file .umlclass. It has a lot of classes, Enumerationtypes, relations.... I want to organize it in the class diagram Editor, but it is impossible because I don't know where the things are.
In the Project Explorer of Eclipse I can see the tree and in the view properties I can see the properties of each one, but I can't see it in the class diagram Editor.
Is there any kind of select or find each resource in the diagram Editor? I'm using the UML2Tools plugin.
Thanks in advance.
Ramón.
Actually the UML2Tools don't have a full fledged editor. Consider using another editor for your Eclipse UML2 Model.
Omondo EclipseUML can read all UML2Tools model.
You just need to to create an empty class diagram and drag and drop one classifier inside the diagram. The project will immediately import all models and then allow you to navigate graphically in the model using the class diagram as a viewer of your model.
It is really good because your diagrams are not anymore the model itself as it is for many tools but only a viewer of your model.
Really cool feature :-)
I'm Using Papyrus UML and I have to use in my diagram, a class which is defined in another .uml file. HowI can do it?
Thank you
You need to create a shortcut but for me this is not usable because I prefer to mix usecase and class diagram elements inside the same model and sometimes even the same diagram.
You can do it with RSA IBM or Omondo EclipseUML.
I do not know particularly about Papyrus, but in UML in general, you should have a Model-element at the top-level, and in there, you create a PackageImport. Now you should be able to set the ``Imported Package'' reference---but the other UML must be loaded from the workspace first:
This is where things become interesting! in the plain Eclipse UML editor, you have to load the resource first using the 'UML Editor' menu or the ``Additional Resources'' sub-tree in the model-outline. I guess Papyrus offers at least the same way through the outline.