I am trying to remove words from a line if they contain a specific string. Here is an example of the text:
host-a, host-b, host-c+test, host-d, host-e+test
I want to remove anything that contains +test, to result with:
host-a, host-b, host-d
Likewise, I need to apply this on a line by line basis, not on all lines in the file. It is going to be used within a macro.
How can I do this?
Something like this, maybe?
:%s/\<[-a-z]\++test\>//gc
It will ask for each match if you want to replace it. Hint: set hlsearch will show you the matches.
If you also want to remove the comma, then:
%s/\(,\s\+\)\?\S\++test\>//gc
Related
I want to replace multiple stuffs:
My original file has:
<regSetting>
<registerAddr>0x0112</registerAddr>
<registerData>0x0A</registerData>
</regSetting>
<regSetting>
<registerAddr>0x0113</registerAddr>
<registerData>0x0A</registerData>
</regSetting>
I want to replace 3 items:
1st chunk:
<regSetting>
<registerAddr>
to get:
reg_write(
2nd chunk:
</registerAddr>
<registerData>
To get:
,
3rd chunk:
</registerData>
</regSetting>
To get:
);
To finally get:
reg_write(0x0112, 0x0A);
reg_write(0x0113, 0x0A);
THis is easily replacable in if we use notepad++. Because there we have non-regex option where search can include new lines aswell, it can find all exact matches and replace.
I have tried in Vim, but vim substitution option works line by line. and I could not find appropriate answers.
This is one such requirement, and similarly I have multiple replacements to be done.
If its possible in Vim, I want to yank the chunk, and use it in below command (substitute)
%s/ctrl+"/new_word/g
you can search and replace across multiple lines in vim, see search across multiple lines.
to accomplish your task you can use for example:
%s/^\s*<regSetting>\_s*<registerAddr>\(.*\)<\/registerAddr>\_s*<registerData>\(.*\)<\/registerData>\_s*<\/regSetting>/reg_write(\1, \2);/g
it's long, but I think easy to read. it basically matches the whole <regSetting> tag and content and captures the values, then substitutes the match using captured values.
the \_s pattern will match a whitespace (space or tab) or newline character.
I'm new into vim, I have hug text file as follow:
ZK792.6,ZK792.6(let-60),cel-miR-62(18),0.239
UTR3,IV:11688688-11688716,0.0670782
ZC449.3b,ZC449.3(ZC449.3),cel-miR-62(18),0.514
UTR3,X:5020692-5020720,0.355907
First, I would like to get delete all rows with even numbers (2,4,6...).
Second, I would like to remove (18) from entire file. as a example:
cel-miR-62(18) would be cel-miR-62.
Third: How can I get delete all parentheses including it's inside?
Would someone help me with this?
For the first one:
:g/[02468]\>/d
where :g matches all lines by the regex between the slashes and runs d (delete line) on the matching lines. The regex is quite easy to read, the only interesting symbol there is perhaps the \>, which matches end of a word.
For the second question:
:%s/\V(18)//g
where % is the specification meaning "all lines of the file", s is the substitute command, \V sets the "very nomagic" mode of regexes (not sure what your default is, you might not need this) and the final g makes vim substitute all occurrences on each line (with an empty string, the one between slashes). Make sure that :set gdefault? prints nogdefault (the default setting of gdefault), otherwise, drop the final g from the substitute command.
To remove every even line (or every other line):
:g/^/+d
To remove every instance of (18):
:%s/(18)//g
Remove all the parenthetical content:
:%s/(.\\{-})//g
Note: the pattern in third answer is a non-greedy match.
I have an XML file where I only care about the size attribute of a certain element.
First I used
global!/<proto name="geninfo"/d
to delete all lines that I don't care about. That leaves me a whole bunch of lines that look like this:
<proto name="geninfo" pos="0" showname="General information" size="174">
I want to delete everything but the value for "size."
My plan was to use substitute to get rid of everything not matching 'size="[digit]"', the remove the string 'size' and the quotes but I can't figure out how to substitute the negation of a string.
Any idea how to do it, or ideas on a better way to achieve this? Basically I want to end up with a file with one number (the size) per line.
You can use matching groups:
:%s/^.*size="\([0-9]*\)".*$/\1/
This will replace lines that contain size="N" by just N and not touch other lines.
Explanation: this will look for a line that contains some random characters, then somewhere the chain size=", then digits, then ", then some more random characters, then the end of the line. Now what I did is that I wrapped the digits in (escaped) parenthesis. That creates a group. In the second part of the search-and-replace command, I essentially say "I want to replace the whole line with just the contents of that first group" (referred to as \1).
:v:size="\d\+":d|%s:.*size="\([^"]\+\)".*:\1:
The first command (until the | deletes every line which does not match the size="<SOMEDIGIT(S)>" pattern, the second (%s... removes everything before and after size attr's " (and " will also be removed).
HTH
Let's say this is my text:
this is my text this
is my text this is my text
my text is this
I would like to highlight all text except pattern and delete the highlighted text.
p.e. text: this must be the result.
text
texttext
text
I've found the code how to select all text except pattern:
\%(\%(.{-}\)\#!text\zs\)*
however I don't know how to delete all highlighted text.
This doesn't work:
:%s/\%(\%(.{-}\)\#!bell\zs\)*//
Can anyone help me?
Try this:
:%s/\(^\|\(text\)\#<=\).\{-}\($\|text\)\#=//g
Explanation:
\(^\|\(text\)\#<=\) # means start of line, or some point preceded by “text”
.\{-} # as few characters as possible
\($\|text\)\#= # without globbing characters, checking that we reached either end of line or occurrence of “text”.
Another way to do it:
Create a function that count matches of a pattern in a string (see :help match() to help you design that)
Use: :%s/.*/\=repeat('text', matchcount('text', submatch(0)))
Forgive me, because I'm not a vim expert, but wouldn't prepending the search with v find the inverse so that you could do something like this?
:v/pattern/d
I've implemented Benoit's clever regular expression as a custom :DeleteExcept command in my PatternsOnText plugin. It offers other related commands like :SubstituteExcept or :SubstituteInSearch, too.
OP's example would be
:%DeleteExcept /text/
Comparing that with #Benoit's explicit command (:%s/\(^\|\(text\)\#<=\).\{-}\($\|text\)\#=//g), it's a lot simpler.
I am currently writing a plugin in Vim that needs to highlight arbitrary lines in a file
at the same time.
My approach so far has been implementing match with the line number to highlight it, but the problem is that I would need to add | for every other line in a file and append that information and then call it every time the window gets redrawn.
There is another problem with match in my case, and that is that a line that may not have any whitespace would not look highlighted (match only highlights existing text/whitespace).
So even if I had match rewrite the window and highlighting all the lines I need, from a user's perspective this wouldn't be to useful if the highlighting doesn't show anything if there is no whitespace/text.
Can I get any suggestions in how to effectively show/display/highlight (I'm open to different implementations to solve my problem) arbitrary lines in a file at the same time regardless of amount of text or whitespace?
Edit: My main request is to be able to highlight lines by line number not by regex
matching. So any solution should need to be flexible enough to accept a Line number to match.
Edit: signs is the answer to my problem, and I found this tutorial the best way to grasp and implement what I needed: http://htmlpreview.github.io/?https://github.com/runpaint/vim-recipes/blob/master/text/07_navigation/12_bookmarking_lines_with_visible_markers.html
I would use region rather than match. Here is part of my manuscript syntax file that highlights speech:
:syntax region msSpeech start=/"/ end=/"\|\n\n/
:highlight msSpeech guifg=#000088
It starts with a double quote and ends with another double quote or the end of the paragraph. It will highlight multiple lines if need be.