My shell script find all files 90 days older
find /var/www/html/zip/data/*/*/*/*/* -type f -mtime +90
that returns the output like
/var/www/html/zip/data/2011/jan/11/333333/Photos/a.jpeg
/var/www/html/zip/data/2011/jan/11/333333/Photos/b.jpeg
/var/www/html/zip/data/2011/jan/11/333333/Photos/c.jpeg
/var/www/html/zip/data/2011/feb/11/333333/Photos/a.jpeg
/var/www/html/zip/data/2011/feb/11/333333/Photos/b.jpeg
What would i need to do to just fetch unique folder path from the above output using the same Find command so the output should be
/var/www/html/zip/data/2011/jan/11/333333/Photos
/var/www/html/zip/data/2011/feb/11/333333/Photos
So i believe there would need to append something in the above Find command but don't know what
Note: I would like to save the unique path in a variable
Try
find /var/www/html/zip/data/*/*/*/*/* -type f -mtime +90 -printf "%h\n" | sort | uniq
I am not sure if find can do this directly, but you could always use sed to post-process the results:
find /var/www/html/zip/data/*/*/*/*/* -type f -mtime +90 | sed 's|/[^/]*$||'
Piping the results further through uniq should remove duplicates (you might need to first do sort, but I doubt it).
You can find the solution this way
find /var/www/html/zip/data -type d -mtime +90 | uniq
The idea behind this is, whenever a file inside a folder is updated or modified, folder is also marked as modified. So in this case you will get all the folders which were not updated in last 90 days...
Adding to jonathanasdf's answer,
You could may be add a for loop,
$i=1;
for uniq_dir in `find /var/www/html/zip/data/*/*/*/*/* -type f -mtime +90 -printf "%h\n" | sort | uniq`;
do
a[$i]=$uniq_dir;
let "i = $i + 1";
done;
Related
So far I have this:
find -name ".txt"
I'm not quite sure how to use wc to find out the exact number of files. When using the command above, all the .txt files show up, but I need the exact number of files with the .txt extension. Please don't suggest using other commands as I'd like to specifically use find and wc. Thanks
Try:
find . -name '*.txt' | wc -l
The -l option to wc tells it to return just the number of lines.
Improvement (requires GNU find)
The above will give the wrong number if any .txt file name contains a newline character. This will work correctly with any file names:
find . -iname '*.txt' -printf '1\n' | wc -l
-printf '1\n tells find to print just the line 1 for each file name found. This avoids problems with file names having difficult characters.
Example
Let's create two .txt files, one with a newline in its name:
$ touch dir1/dir2/a.txt $'dir1/dir2/b\nc.txt'
Now, let's find the find command:
$ find . -name '*.txt'
./dir1/dir2/b?c.txt
./dir1/dir2/a.txt
To count the files:
$ find . -name '*.txt' | wc -l
3
As you can see, the answer is off by one. The improved version, however, works correctly:
$ find . -iname '*.txt' -printf '1\n' | wc -l
2
find -type f -name "*.h" -mtime +10 -print | wc -l
This worked out.
I have a find string that finds all the instances of a particular filename in a path, like so:
find /opt/logs* -type f -name "deploy.log" -exec ls {} \;
I need to return the result with 'FINENAME=' prepended on each line. Having a hard time figuring the best way.
find /opt/logs* -type f -name deploy.log | sed 's/^/FILENAME=/'
Note that if you have a directory named /opt/logs (and you're not trying to look in /opt/logs-foo/ and /opt/logs-date, or the like) you can drop the * and write find /opt/logs -type ...
Use the -printf option:
find /opt/logs* -type f -name "deploy.log" -printf='FILENAME=%p\n'
%p will get expanded to the file's name.
okay maybe this sounds simple, but it has been a bit challenging to me
I have a directory called backups and it has (backup files + other files)
backups files:
../backups/backup-2013_03_03.zip
../backups/backup-2013_03_05.zip
../backups/backup-2013_01_01.zip
../backups/backup-2013_08_16.zip
../backups/backup-2013_02_28.zip
../backups/backup-2013_01_21.zip
../backups/backup-2013_03_29.zip
../backups/backup-2013_04_05.zip
I'm trying to delete backup files older than 90 days.
find /var/tmp/stuff -mtime +90 -print | xargs /bin/rm
seems to work, but I'm not able to limit the search to backup files only. "files which starts with backup*"
I have tried adding "-iname backup" option to find command argument, thinking it would do the trick but it doesn't seems to work.
Any ideas?
Thank you
You can pipe through grep before calling rm. Something like:
find /var/tmp/stuff -mtime +90 -print | grep 'backup-' | xargs /bin/rm
while the find utility has all kinds of options to single handedly do this, including the deleting as noted in other answers, I can never remember any but the most basic options.
find "stuff" | grep "some_other_stuff" | xargs "do_stuff"
seems much easier to remember for me.
The parameter to iname matches against the full filename, so you need a trailing wildcard:
find /var/tmp/stuff -mtime +90 -iname "backup*" -print | xargs /bin/rm
You could also use find's -exec argument, but personally I find the syntax quite arcane. I prefer xargs.
find /var/tmp/stuff -mtime +90 -iname "backup*" -exec /bin/rm '{}'
Or, as damienfrancois points out, GNU find can take a -delete argument. This is the best solution because a) it is shorter and b) it is more efficient because the deletion happens within the find process. exec and xargs will both spawn one new process per file to delete. Source: GNU manual However, as wildplasser points out, it could also be dangerous - -delete will remove directories by default. To only delete files, use -type f.
find /var/tmp/stuff -type f -mtime +90 -iname "backup*" -delete
You could use -exec option of find along with -iname. Since you want to delete only files, you would need to specify -type f
find /var/tmp/stuff -type f -iname 'backup*' -mtime +90 -exec rm {} +
If you prefer xargs like me
find /var/tmp/stuff -type f -iname 'backup*' -mtime +90 -print0 | xargs -0 rm
Note : It's recommended to use find -print0 with xargs -0 to avoid weird file name caveats
I'm trying to find out the total size of all files owned by a given user.
I've tried this:
find $myfolder -user $myuser -type f -exec du -ch {} +
But this gives me an error:
missing argument to exec
and I don't know how to fix it. Can somebody can help me with this?
You just need to terminate the -exec. If you want the totals for each directory
possibly -type d is required.
find $myfolder -user $myuser -type d -exec du -ch {} \;
Use:
find $myfolder -user gisi -type f -print0 | xargs -0 du -sh
where user gisi is my cat ;)
Note the option -s for summarize
Further note that I'm using find ... -print0 which on the one hand separates filenames by 0 bytes, which are one of the few characters which are not allowed in filenames, and on the other hand xargs -0 which uses the 0 byte as the delimiter. This makes sure that even exotic filenames won't be a problem.
some version of find command does not like "+" for termination of find command
use "\;" instead of "+"
Using Linux. What I need to do is determine the number of files in a directory(recursively) that are older than DATE and echo that number.
I have:
find /u1/database/prod/arch -type f -mtime +10 -exec ls -laR | wc -l \;
That lists the files fine.
And then I have:
ls -laR | wc -l
Which lets me count the files recursively.
But I can't seem to put them together. I think I need a script to do this but don't know how to do that.
Would love some help
find /u1/database/prod/arch -type f -mtime +10 | wc -l
works here.
You dont need the exec. use -print (or nothing) and find will print a line per file (and handle the recursion)
find /u1/database/prod/arch -type f -mtime +10 -print | wc -l