Is there any program/app that draws and save avl tree charts ? To pdf format preferably
did you see AVL tree Applet
it is a ready tree. you can insert as many as you want then print page or save as PDF.
Best regard.
Related
I'm trying to render a tree that is very broad... and it renders, as expected, in a long, skinny horizontal image.
Problem is that I need a graph suitable for a document. I would very much like to take and move the nodes that are rendered horizontally and "drag" them down so that the graph is more vertical... with the edges curving to accommodate this. Are there any clever ways to accomplish this? GraphViz settings? Third party tools that let me manipulate and fine tune the output? I work mostly in the Python ecosystem, but open to others. Also open to the use of tools like Visio and other pro drawing tools. Thanks!
Edit
After implementing the answer below by #sroush, and then tweaking a little further with Photoshop, got some nice results.
Tweaking the above in Photosop. Had to add the two curved edges after the secondary node by hand, but it's worth it. Much more presentable.
I assume you are using dot, and your graph "naturally" has only a few ranks (rows).
There are a few tweaks that will help a bit (reducing node horizontal footprints):
node [shape=rect] // snugger fit into rectangles
insert newlines into node labels e.g. xxx [label="Controller Board\n#19_8"])
Also try the unflatten program (https://www.graphviz.org/pdf/unflatten.1.pdf). It will increase the apparent number of ranks (rows).
See related question here with command line examples:
Distribute nodes on the same rank of a wide graph to different lines
You can use the minlen property to limit the minimum level span of some edges.This avoids the result becoming very long in the horizontal position.
For example:
digraph {
a->b
a->c
a->d
a->e
}
This will output the following image:
But when minlen is used, the picture will become longer vertically but shortened horizontally:
digraph {
a->b
a->c
a->d[minlen=2]
a->e[minlen=3]
}
I read a couple of posts on position nodes in force layout but didn't find an answer to what I was looking for.
I have an object with nodes and links.
I' trying to create a graph which would show all the nodes top to bottom.
I was looking at the example code from here:
https://github.com/danielstern/force-graph-example
Here's a screenshot of the result:
I'm trying to find a way to position each node so the nodes without parents would be on the top and the ones connecting to them would be under them and so forth.
Here's an image to illustrate it:
Right now, all the nodes are scattered randomly.
I wanted to if I need to actually calculate the position of each node in a vertical view or is there a smarter/built-in way to achieve it.
I looked at this example which looked promising:
How to organise node positions in D3 Force layout
But in my case I don't have a way to differentiate between nodes levels so I don't think the yPostion would help.
I was also looking at thes post:
d3.js - How can I expand force directed graph horizontally?
According to #Lars Kotthoff:
"The point of the force layout is to automatically lay out a graph like this so that you don't have to specify the positions of the nodes yourself".
Since my graph is not really a tree, I don't think the tree view would match.
What would be my best approach to position the nodes?
Or perhaps there's a better library to achieve what I need?
I found this package:
d3-dag
It basically supports what I need:
"Often data sets are hierarchical, but are not in a tree structure..."
Here's an exmaple:
exmaple
I want to create a search tree with files on a computer and search the tree to see if the tree contains specific files. Then I thought, why not use one tree for images and one for videos, for example. That would make the search for an image or video faster, since the number of comparisons should reduce. But then I thought, couldnt I break it down even further, and use one tree for each set of images that begins with a specific letter and then map that search tree to the specific letter using a hashmap. Then the number of comparisons would be even smaller.
I tried searching for using multiple binary search trees to search for an item, but I couldn't find anything. Is there a downside to using multiple binary search trees? Have I misunderstood something?
and use one tree for each set of images that begins with a specific letter
This is effectively adding a 26-ry (or more, for capital letters, digits, etc.) tree node below your other trees. So you can do that... but then why not make the entire tree the same way? With a slight generalization, you can get a trie.
I want to programatically create time lines similar to this:
source
Each event will be at a vertical position determined by its datetime, but it can have arbitrary-length text, and must be positioned vertically so that it doesn't overlap with another event box.
How can I programatically detect overlap of SVG elements so that I can move them up or down as needed? A solution in any programming language or using any library is fine, but ideally I'd like to build this time line without involving a browser; I want this to be a command-line utility.
(I think this is possible because GraphViz Dot can output undirected graphs as SVG and keeps the nodes from overlapping - see the Wikipedia article.)
I'm trying to develop a view of a hierarchical tree in which the weight of each node is the actual number of children it has. A leaf node has weight 1.
I want to arrange these items in a way they can be browsed going deeper into the tree by showing the root categories (with no parent) at the beginning. Clicking on a node makes the view repaint iself to show just children of that node.
The tricky part is that the size in pixel of a node should be proportional to its weight compared to adjacents nodes. According to wikipedia this is called treemapping and what I need is a tiling algorithm, I was trying to figure out by myself but it seems more complex that I expected..
To give you an example there is a program for Mac Os X called GrandPerspective that shows folder sizes of your HD:
(source: arstechnica.com)
I want to arrange nodes in a way like this! (of course size is proportional to folder size)
Any suggestions?
Thanks
The data structure used in the file system example you show is most likely a KD tree. I'm not exactly sure how well the problem you want to solve maps to the file system example but this is how I would go along solving the file system case myself:
You start with a rectangle representing the root of the hard disk.
You take all files and directories in the directory and give them a size.
For files the size is the size of the file
For directories, the size is the the complete size of all files it contains (including all its subfolders, and their subfolders and so on).
Now you try to cut this list into two as equally sized lists as possible. Now you cut the input rectangle into two rectangles that has the same size proportions as the two lists you cut the input files into. You should make the cut along the axis that is shorter of the input rectangles size to make sure you always have as quadratic as possible rectangles. Now you run the algorithm recursively on the two lists with their corresponding rectangle.
The base cases would be:
There is only a single file in the list. You then fill the rectangle with the color of the file type.
There is a single directory in the list. For this case you run the algorithm recursively on the contents in the directory inside the rectangle.
Choosing how to split the lists into two as equally sized parts as possible may not be trivial (is it a knapsack?). A decent heuristic approach would probably be to sort the list in descending order and take the elements out of the list and put it in the currently smallest of the two resulting lists.
EDIT: The splitting problem is called partition and is a special case of knapsack. It's covered in this thread here on SO.
That's a squarified treemap. You can read the paper explaining this technique.