Let's say I have a collection of books that contains multiple documents that looks like this:
{
"author":"Gud Author",
"title":"Gud Book"
}
{
"author":"Lazy Writer",
"title":"Lesson about lazyness"
}
{
"author":"Mysterious Enigma",
"title":"Ways of the unknown"
}
In the request I'm getting one query parameter (string) called "filter". I want to use this parameter to get only the books whose author or title matches at least a part of the filter string.
This is my code so far:
bookRouter.get("/books", (req,res) => {
const {filter} = req.query
let query = {}
if (filter) query.$or = [{author: {$regex: filter}}, {title: {$regex: filter}}]
Book.find(query)
.then((books) => res.json(books))
.catch((err) => res.json(err))
})
If the filter parameter is shorter than the values in my db everything works ok.
"" as filter would return everything,
"Gud" would only return the first object
"Mysterious" would only return the third object"
However when my query is " Mysterious Enigma Ways" I'm getting back an empty array. Also a combination of both title and author that is only a partial match with both db values like "Mysterious Ways" won't work.
How do i modify my query to also return documents that only match with a part of the query string?
I've tried turning the string into an array (separating words) using .join(" ") to compare matches to the single elements of the array but I couldn't figure out how to combine the operators for this query.
PS: Yes I will convert both query string and values to lowercase for case-insensitive comparison. Just wanted to keep this short.
Instead of $regex, try using plain Javascript regex, by splitting the input words and checking if any of the words are present using $in,
let splitWords = filter.split(" ");
let regexWords = splitWords.map(e =>{return new RegExp(e,i)}
if (filter) query.$or = [{author: {$in: regexWords}}, {title: {{$in: regexWords}}]
I have documents in a MongoDB as below -
[
{
"_id": "17tegruebfjt73efdci342132",
"name": "Test User1",
"obj": "health=8,type=warrior",
},
{
"_id": "wefewfefh32j3h42kvci342132",
"name": "Test User2",
"obj": "health=6,type=magician",
}
.
.
]
I want to run a query say health>6 and it should return the "Test User1" entry. The obj key is indexed as a text field so I can do {$text:{$search:"health=8"}} to get an exact match but I am trying to incorporate mathematical operators into the search.
I am aware of the $gt and $lt operators, however, it cannot be used in this case as health is not a key of the document. The easiest way out is to make health a key of the document for sure, but I cannot change the document structure due to certain constraints.
Is there anyway this can be achieved? I am aware that mongo supports running javascript code, not sure if that can help in this case.
I don't think it's possible in $text search index, but you can transform your object conditions to an array of objects using an aggregation query,
$split to split obj by "," and it will return an array
$map to iterate loop of the above split result array
$split to split current condition by "=" and it will return an array
$let to declare the variable cond to store the result of the above split result
$first to return the first element from the above split result in k as a key of condition
$last to return the last element from the above split result in v as a value of the condition
now we have ready an array of objects of string conditions:
"objTransform": [
{ "k": "health", "v": "9" },
{ "k": "type", "v": "warrior" }
]
$match condition for key and value to match in the same object using $elemMatch
$unset to remove transform array objTransform, because it's not needed
db.collection.aggregate([
{
$addFields: {
objTransform: {
$map: {
input: { $split: ["$obj", ","] },
in: {
$let: {
vars: {
cond: { $split: ["$$this", "="] }
},
in: {
k: { $first: "$$cond" },
v: { $last: "$$cond" }
}
}
}
}
}
}
},
{
$match: {
objTransform: {
$elemMatch: {
k: "health",
v: { $gt: "8" }
}
}
}
},
{ $unset: "objTransform" }
])
Playground
The second upgraded version of the above aggregation query to do less operation in condition transformation if it's possible to manage in your client-side,
$split to split obj by "," and it will return an array
$map to iterate loop of the above split result array
$split to split current condition by "=" and it will return an array
now we have ready a nested array of string conditions:
"objTransform": [
["type", "warrior"],
["health", "9"]
]
$match condition for key and value to match in the array element using $elemMatch, "0" to match the first position of the array and "1" to match the second position of the array
$unset to remove transform array objTransform, because it's not needed
db.collection.aggregate([
{
$addFields: {
objTransform: {
$map: {
input: { $split: ["$obj", ","] },
in: { $split: ["$$this", "="] }
}
}
}
},
{
$match: {
objTransform: {
$elemMatch: {
"0": "health",
"1": { $gt: "8" }
}
}
}
},
{ $unset: "objTransform" }
])
Playground
Using JavaScript is one way of doing what you want. Below is a find that uses the index on obj by finding documents that have health= text followed by an integer (if you want, you can anchor that with ^ in the regex).
It then uses a JavaScript function to parse out the actual integer after substringing your way past the health= part, doing a parseInt to get the int, and then the comparison operator/value you mentioned in the question.
db.collection.find({
// use the index on obj to potentially speed up the query
"obj":/health=\d+/,
// now apply a function to narrow down and do the math
$where: function() {
var i = this.obj.indexOf("health=") + 7;
var s = this.obj.substring(i);
var m = s.match(/\d+/);
if (m)
return parseInt(m[0]) > 6;
return false;
}
})
You can of course tweak it to your heart's content to use other operators.
NOTE: I'm using the JavaScript regex capability, which may not be supported by MongoDB. I used Mongo-Shell r4.2.6 where it is supported. If that's the case, in the JavaScript, you will have to extract the integer out a different way.
I provided a Mongo Playground to try it out in if you want to tweak it, but you'll get
Invalid query:
Line 3: Javascript regex are not supported. Use "$regex" instead
until you change it to account for the regex issue noted above. Still, if you're using the latest and greatest, this shouldn't be a limitation.
Performance
Disclaimer: This analysis is not rigorous.
I ran two queries against a small collection (a bigger one could possibly have resulted in different results) with Explain Plan in MongoDB Compass. The first query is the one above; the second is the same query, but with the obj filter removed.
and
As you can see the plans are different. The number of documents examined is fewer for the first query, and the first query uses the index.
The execution times are meaningless because the collection is small. The results do seem to square with the documentation, but the documentation seems a little at odds with itself. Here are two excerpts
Use the $where operator to pass either a string containing a JavaScript expression or a full JavaScript function to the query system. The $where provides greater flexibility, but requires that the database processes the JavaScript expression or function for each document in the collection.
and
Using normal non-$where query statements provides the following performance advantages:
MongoDB will evaluate non-$where components of query before $where statements. If the non-$where statements match no documents, MongoDB will not perform any query evaluation using $where.
The non-$where query statements may use an index.
I'm not totally sure what to make of this, TBH. As a general solution it might be useful because it seems you could generate queries that can handle all of your operators.
From the docs:
You can also chain multiple where() methods to create more specific queries (logical AND).
How can I perform an OR query?
Example:
Give me all documents where the field status is open OR upcoming
Give me all documents where the field status == open OR createdAt <= <somedatetime>
OR isn't supported as it's hard for the server to scale it (requires keeping state to dedup). The work around is to issue 2 queries, one for each condition, and dedup on the client.
Edit (Nov 2019):
Cloud Firestore now supports IN queries which are a limited type of OR query.
For the example above you could do:
// Get all documents in 'foo' where status is open or upcmoming
db.collection('foo').where('status','in',['open','upcoming']).get()
However it's still not possible to do a general OR condition involving multiple fields.
With the recent addition of IN queries, Firestore supports "up to 10 equality clauses on the same field with a logical OR"
A possible solution to (1) would be:
documents.where('status', 'in', ['open', 'upcoming']);
See Firebase Guides: Query Operators | in and array-contains-any
suggest to give value for status as well.
ex.
{ name: "a", statusValue = 10, status = 'open' }
{ name: "b", statusValue = 20, status = 'upcoming'}
{ name: "c", statusValue = 30, status = 'close'}
you can query by ref.where('statusValue', '<=', 20) then both 'a' and 'b' will found.
this can save your query cost and performance.
btw, it is not fix all case.
I would have no "status" field, but status related fields, updating them to true or false based on request, like
{ name: "a", status_open: true, status_upcoming: false, status_closed: false}
However, check Firebase Cloud Functions. You could have a function listening status changes, updating status related properties like
{ name: "a", status: "open", status_open: true, status_upcoming: false, status_closed: false}
one or the other, your query could be just
...where('status_open','==',true)...
Hope it helps.
This doesn't solve all cases, but for "enum" fields, you can emulate an "OR" query by making a separate boolean field for each enum-value, then adding a where("enum_<value>", "==", false) for every value that isn't part of the "OR" clause you want.
For example, consider your first desired query:
Give me all documents where the field status is open OR upcoming
You can accomplish this by splitting the status: string field into multiple boolean fields, one for each enum-value:
status_open: bool
status_upcoming: bool
status_suspended: bool
status_closed: bool
To perform your "where status is open or upcoming" query, you then do this:
where("status_suspended", "==", false).where("status_closed", "==", false)
How does this work? Well, because it's an enum, you know one of the values must have true assigned. So if you can determine that all of the other values don't match for a given entry, then by deduction it must match one of the values you originally were looking for.
See also
in/not-in/array-contains-in: https://firebase.google.com/docs/firestore/query-data/queries#in_and_array-contains-any
!=: https://firebase.googleblog.com/2020/09/cloud-firestore-not-equal-queries.html
I don't like everyone saying it's not possible.
it is if you create another "hacky" field in the model to build a composite...
for instance, create an array for each document that has all logical or elements
then query for .where("field", arrayContains: [...]
you can bind two Observables using the rxjs merge operator.
Here you have an example.
import { Observable } from 'rxjs/Observable';
import 'rxjs/add/observable/merge';
...
getCombinatedStatus(): Observable<any> {
return Observable.merge(this.db.collection('foo', ref => ref.where('status','==','open')).valueChanges(),
this.db.collection('foo', ref => ref.where('status','==','upcoming')).valueChanges());
}
Then you can subscribe to the new Observable updates using the above method:
getCombinatedStatus.subscribe(results => console.log(results);
I hope this can help you, greetings from Chile!!
We have the same problem just now, luckily the only possible values for ours are A,B,C,D (4) so we have to query for things like A||B, A||C, A||B||C, D, etc
As of like a few months ago firebase supports a new query array-contains so what we do is make an array and we pre-process the OR values to the array
if (a) {
array addObject:#"a"
}
if (b) {
array addObject:#"b"
}
if (a||b) {
array addObject:#"a||b"
}
etc
And we do this for all 4! values or however many combos there are.
THEN we can simply check the query [document arrayContains:#"a||c"] or whatever type of condition we need.
So if something only qualified for conditional A of our 4 conditionals (A,B,C,D) then its array would contain the following literal strings: #["A", "A||B", "A||C", "A||D", "A||B||C", "A||B||D", "A||C||D", "A||B||C||D"]
Then for any of those OR combinations we can just search array-contains on whatever we may want (e.g. "A||C")
Note: This is only a reasonable approach if you have a few number of possible values to compare OR with.
More info on Array-contains here, since it's newish to firebase docs
If you have a limited number of fields, definitely create new fields with true and false like in the example above. However, if you don't know what the fields are until runtime, you have to just combine queries.
Here is a tags OR example...
// the ids of students in class
const students = [studentID1, studentID2,...];
// get all docs where student.studentID1 = true
const results = this.afs.collection('classes',
ref => ref.where(`students.${students[0]}`, '==', true)
).valueChanges({ idField: 'id' }).pipe(
switchMap((r: any) => {
// get all docs where student.studentID2...studentIDX = true
const docs = students.slice(1).map(
(student: any) => this.afs.collection('classes',
ref => ref.where(`students.${student}`, '==', true)
).valueChanges({ idField: 'id' })
);
return combineLatest(docs).pipe(
// combine results by reducing array
map((a: any[]) => {
const g: [] = a.reduce(
(acc: any[], cur: any) => acc.concat(cur)
).concat(r);
// filter out duplicates by 'id' field
return g.filter(
(b: any, n: number, a: any[]) => a.findIndex(
(v: any) => v.id === b.id) === n
);
}),
);
})
);
Unfortunately there is no other way to combine more than 10 items (use array-contains-any if < 10 items).
There is also no other way to avoid duplicate reads, as you don't know the ID fields that will be matched by the search. Luckily, Firebase has good caching.
For those of you that like promises...
const p = await results.pipe(take(1)).toPromise();
For more info on this, see this article I wrote.
J
OR isn't supported
But if you need that you can do It in your code
Ex : if i want query products where (Size Equal Xl OR XXL : AND Gender is Male)
productsCollectionRef
//1* first get query where can firestore handle it
.whereEqualTo("gender", "Male")
.addSnapshotListener((queryDocumentSnapshots, e) -> {
if (queryDocumentSnapshots == null)
return;
List<Product> productList = new ArrayList<>();
for (DocumentSnapshot snapshot : queryDocumentSnapshots.getDocuments()) {
Product product = snapshot.toObject(Product.class);
//2* then check your query OR Condition because firestore just support AND Condition
if (product.getSize().equals("XL") || product.getSize().equals("XXL"))
productList.add(product);
}
liveData.setValue(productList);
});
For Flutter dart language use this:
db.collection("projects").where("status", whereIn: ["public", "unlisted", "secret"]);
actually I found #Dan McGrath answer working here is a rewriting of his answer:
private void query() {
FirebaseFirestore db = FirebaseFirestore.getInstance();
db.collection("STATUS")
.whereIn("status", Arrays.asList("open", "upcoming")) // you can add up to 10 different values like : Arrays.asList("open", "upcoming", "Pending", "In Progress", ...)
.addSnapshotListener(new EventListener<QuerySnapshot>() {
#Override
public void onEvent(#Nullable QuerySnapshot queryDocumentSnapshots, #Nullable FirebaseFirestoreException e) {
for (DocumentSnapshot documentSnapshot : queryDocumentSnapshots) {
// I assume you have a model class called MyStatus
MyStatus status= documentSnapshot.toObject(MyStatus.class);
if (status!= null) {
//do somthing...!
}
}
}
});
}
I need to do a query in an Cloudant DataBase where you compare a number with decimals that is defined as a string with another number sent from the server. The problem is that a comparison of strings is made and I need it to be a numerical comparison. There is there any way to perform this search by converting the database parameter to float while doing the query? O there are another way to do this query?
This is the query in the server, value.precio is sent from the client as a string.
value.precio = value.precio.split("-");
var precio_init = value.precio[0];
var precio_final = value.precio[1];
value.precio = {
"$gte":precio_init,
"$lte":precio_final
};
And in my database this is the parameter I want to search is:
"precio": "13.39"
Thanks
I don't think you will be able to do this with Cloudant Query, but you could try Cloudant Search. Create a new search index similar to the following:
Design Doc: myDesignDoc
Index Name: byPrecio
Index:
function (doc) {
if (doc.precio) {
index("precio", parseFloat(doc.precio));
}
}
Then you can uses ranges to search. For example:
precio:[13 TO 14]
Full search on Cloudant would look like this:
https://xxx.cloudant.com/YOUR_DB/_design/myDesignDoc/_search/byPrecio?q=precio:[13%20TO%2014]&include_docs=true
Sample response:
{
"total_rows":1,
"bookmark":"g2wAAAAxxx",
"rows":[
{
"id":"74fa6ff1b6dbca8c10d677832f6a3de2",
"order":[
1.0,
0
],
"fields":{
},
"doc":{
"_id":"74fa6ff1b6dbca8c10d677832f6a3de2",
"_rev":"2-17c984e51102b719fe9f80fc5d5bc78e",
"precio":"13.39",
"otherField":"otherValue"
}
}
]
}
More info on Cloudant Search here
I have a Json like this:
"datos_personales":
{
"nombre":"Dionel",
"apellido":"Delgado",
"fechanacimiento":"1990-12-31T04:00:00.000Z",
"lugarNacimiento":"Venezuela, Maracaibo",
"edad":25,
"genero":"Masculino",
"cedula":"21076754",
"direccion":"San Carlos",
"telefonofijo":"0262-6871111",
"telefonomovil":"0262-6871111"
},
"datos_emergencia":
{
"nombre1":"Jeaynie",
"apellido1":"Valbuena",
"telefono1":"0262-6871111",
"telefono2":"0262-6871111",
"parentesco1":"Madre",
"nombre2":"Diones",
"apellido2":"Delgado",
"telefono3":"0262-6871111",
"telefono4":"0262-6871111",
"parentesco2":"Padre"
},
"datos_sociales":
{
"civil":"Soltero",
"estudios4":true,
"ocupacion":"Programador Web",
"hijos":"No"
},
"datos_medicotratante":
{
"nombre":"Naikelin",
"apellido":"Ruiz",
"telefono1":"0262-6871111",
"telefono2":"0262-6871111",
"especialidad":"Pediatría",
"sangre":"AB",
"rh":"Negativo",
"seguro":"No"
}
`
I need to query these kinds of documents with nodeJS using "cedula" to find them
{"datos_personales.cedula":21076754} << in this case
I tried using this but it doesn't fetch the document
var ced = 21076754;
db.getCollection('users').find({"datos_personales.cedula":ced});
any suggestions?
"cedula":"21076754",
Your result is a string (See the quotes).
Change your query to:
var ced = "21076754";
db.getCollection('users').find({"datos_personales.cedula":ced});
Another solution to the problem is -
find() query in MongoDB returns a cursor while findOne() query returns a JSON Object which matches the argument passed in the query. You can retrieve the desired record by using the query below -:
db.getCollection('users').findOne({"datos_personales.cedula":ced});