I have to find a directory "Dir1" excluding "Dir2" and "Dir3", using command find
$ find . -name Dir1 -type d \( -name Dir2 -o -name Dir3 \) \
-prune -o -print
dosen't work
Move -prune to the beginning:
find . \( -name Dir2 -o -name Dir3 \) -prune -o -name Dir1 -type d
Related
I have a folder structure like below. I am deleting all files inside /data/mydata/ which are older than 2 hrs using the command below, but I want to exclude the metadata folder. How can I do it?
Command:
/usr/bin/find /data/mydata -mindepth 1 -type d -empty -delete -o -cmin +120 -type f -delete
Directory structure:
/data/mydata/
--test1
--f2.txt
--foo
--metadata
--test1.json
--test2
--metadata
--foo(under metadata)
--test2.json
--f2.txt
To exclude a particular path, you can do:
/usr/bin/find /data/mydata -path /data/mydata/test2/metadata -prune \
-o -mindepth 1 \( \( -type d -empty \) -o \( -cmin +120 -type f \) \) -delete
To exclude all instances of directories named metadata, you probably want:
/usr/bin/find /data/mydata -name metadata -prune \
-o -mindepth 1 \( \( -type d -empty \) -o \
\( -cmin +120 -type f \) \) -delete
How to remove all files without the .txt and .exe extensions recursively in the current working directory? I need a one-liner.
I tried:
find . ! -name "*.txt" "*.exe" -exec rm -r {} \
find -type f -regextype posix-extended -iregex '.*\.(txt|exe)$'
Try this.
find . -type f ! -name "*.exe" ! -name "*.txt" -exec rm {} \;
The above command will remove all the files other than the .exe and .txt extension files in the current directory and sub directory recursively.
If you have GNU find with the -delete action:
find . -type f ! \( -name '*.txt' -o -name '*.exe' \) -delete
And if not:
find . -type f ! \( -name '*.txt' -o -name '*.exe' \) -exec rm -f {} +
using -exec ... {} + to execute rm as few times as possible, with the arguments chained.
Try the following:
rm -f $(find . -type f ! \( -name "*.txt" -o -name "*.exe" \))
This will first recursively find all files that do not end with .txt or .exe extensions, and then delete all of these files.
I'm trying to do a find and replace function, finding files which match a criteria then find/replace text within them.
Find statement (works find and returns list of files):
find / -type f -name "*.properties" -o -name "*.xml" -not \( -path '/tmp/*' -o -path '/var/tmp/*' \)
Sed find/replace:
sed -i 's/find/replace/g' {} \;
Putting together:
find / -type f -name "*.properties" -o -name "*.xml" -not \( -path '/tmp/*' -o -path '/var/tmp/*' \) -exec sed -i 's/10\.32\.19\.156/10.32.19.165/g' {} \;
However this does not seem to work. Removing some 'find' parameters causes it to work, for example this works:
find / -type f -name "*.properties" -exec sed -i 's/10\.32\.19\.156/10.32.19.165/g' {} \;
How can I get sed to work with the extended 'find' parameters?
Currently these two 'find' statements return exactly the same result in a test folder with only 2 files:
find /var/tmp/ipreplace/ -type f -name "*.properties"
find /var/tmp/ipreplace/ -type f -name "*.properties" -o -name "*.xml" -not \( -path '/tmp/*' -o -path '/var/tmp/*' \)
I guess the use of -path parameter in your find command is wrong.
Try the following:
find / -not \( -path '/tmp' -prune \) -not \( -path '/var/tmp' -prune \) -type f -name "*.properties" -o -name "*.xml" -exec sed -i 's/10\.32\.19\.156/10.32.19.165/g' {} \;
Look at this post for reference
I have a source directory with several files. Some of them are symlinks to other files.
I created a cscope.files file. But when I execute cscope. It complains for the files that are symlinks:
cscope: cannot find file /home/bla/source/file.cc
I think it's not very good, but maybe the correct way to go is to change the "find" script, to just write the destination of the symlink instead?
Currently I'm using:
# Write only the files which are NOT symlinks
find `pwd` \( \( -iname "*.c" -o -iname "*.cc" -o -iname "*.h" \) -and \( -not -type l \) \) -print > cscope.files
# Add the target of the symlink for all files matching the right extension, and are symlinks
find `pwd` \( \( -iname "*.c" -o -iname "*.cc" -o -iname "*.h" \) -and -type l \) -printf "%l\n" >> cscope.files
But this seems like a terrible solution. Still looking for a better one
I think you can use the command to find all real paths in a folder that you searched
find -L [your searched folder] -name [your searched pattern] -exec realpath {} \; >> cscope.files
For example, if I would like to add developed folder and linux kernel header to cscope.files, I will the these commands:
find -L `pwd` -iname "*.c" -o -iname "*.h" > cscope.files
find -L /usr/src/linux-headers-3.19.0-15-generic/ -iname '*.h' -exec realpath {} \; >> cscope.files
I hope the answer can help you.
For example if you want to give / as your path for cscope, and want cscope to search files with extensions .c/.h/.x/.s/.S you can give the find command as:
find / -type f -name "*.[chxsS]" -print -exec readlink -f {} \;> cscope.files
This will include regular files, including targets of symbolic links.
I just do the following to avoid symbolic links, as well get the absolute path in the cscope.files. With absolute path you can search from any directory in your sandbox when cscope is integrated with the vim editor
find /"path-to-your-sandbox" -path .git -prune -o -name "*.[ch]" -exec readlink -f {} \; > cscope.files
Note: if you omit -print from the find it does not put the symbolic link path in your cscope.files only the resolved path.
Better in a bash script:
#!/bin/bash
#
# find_cscope_files.sh
extension_list=(c cpp cxx cc h hpp hxx hh)
for x in "${extension_list[#]}"; do
find . -name "*.$x" -print -exec readlink -f {} \;
done
For reference for others I'm currently using.
find "$(pwd)" \( -name "*.[chCS]" -o -name "*.[ch][ci]" -o -name "*.[ch]pp" -o -name "*.[ch]++" -o -name "*.[ch]xx" ) -not \( -ipath "*unittest*" -or -ipath "*regress*" \) \( \( -type l -xtype f -exec readlink -f {} \; \) -o \( -type f -print \) \) >cscope.files
cscope -q -R -b -i cscope.files
In the following command i want to search only only the directories which are non hidden how can i do this using the following command .Iwant to ignore hidden directories while searching the log file
find /home/tom/project/ -name '.log.txt'
ls /home/tom/project/
dir1
dir2
.backup
.snapshot/
.ignore/
Try
find /home/tom/project -type d -name '.*' -prune -o -name .log.txt -print
This will find all files but ignore those that start with a dot so hidden files.
find /home/tom/project/ -type f \( -iname ".log.txt" ! -iname ".*" \)
EDIT:
If the above those not work, this should do the trick. It has a better regex.
find /home/tom/project/ \( ! -regex '.*/\..*' \) -type f -name ".log.txt"
EDIT2:
The following will exclude hidden folders but will search for the hidden files that have the requested pattern:
find /home/tom/project/ \( ! -regex '.*/\..*/..*' \) -type f -name ".log.txt"
EDIT3:
The grep solution :) if this doesn't work i'm lost :)
find /home/tom/project/ \( ! -regex '.*/\..*/..*' \) -exec grep -l ".log.txt" {} \;
EDIT4:
Have you tried the simple solutions?
find /home/tom/project/ -type f -name ".log.txt"
OR
find /home/tom/project/ -type f -name "*" -exec grep -l ".log.txt" {} \;