i have following code:
while(lock)
;
lock = 1;
// critical section
lock = 0;
As reading or changing lock value is in itself a multi-instruction
read lock
change value
write it
If it happens like:
1) One thread reads the lock and stops there
2) Another thread reads it and sees it is free; lock it and do something untill half
3) First thread wakes up and goes into CS
SO how would locking would be implmented in system ?
Placing variables over top of another variables is not right : it would be like Guarding the guard ?
Stopping other processors threads is also not right ?
It is 100% platform specific. Generally, the CPU provides some form of atomic operation such as exchange or compare and swap. A typical lock might work like this:
1) Create: Store 0 (unlocked) in the variable.
2) Lock: Atomically attempt to switch the value of the variable from 0 (unlocked) to 1 (locked). If we failed (because it wasn't unlocked to begin with), let the CPU rest a bit, and then retry. Use a memory barrier to ensure no future memory operations sneak behind this one.
3) Unlock: Use a memory barrier to ensure previous memory operations don't sneak past this one. Atomically write 0 (unlocked) to the variable.
Note that you really don't need to understand this unless you want to design your own synchronization primitives. And if you want to do that, you need to understand an awful lot more. It's certainly a good idea for every programmer to have a general idea of what he's making the hardware do. But this is an area filled with seriously heavy wizardry. There are so many, many ways this can go horribly wrong. So just use the locking primitives provided by the geniuses who made your platform, compiler, and threading library. Here be dragons.
For example, SMP Pentium Pro systems have an erratum that requires special handling in the unlock operation. A naive implementation of the lock algorithm will cause the branch prediction logic to expect the operation to keep spinning, incurring a massive performance penalty at the worst possible time -- when you first acquire the lock. A naive implementation of the lock algorithm may cause two cores each waiting for the same lock to saturate the bus, slowing the CPU that needs to get work done in order to release the lock to a crawl. These all require heavy wizardry and deep understanding of the hardware to deal with.
In a course I studied at Uni, a possible firmware solution for implementing locks was presented in the form of the "atomicity bit" associated to a memory operation initiated by a processor.
Basically, when locking, you'll notice that you have a sequence of operations that need to be executed atomically: test the value of the flag and, if not set, set it to locked, otherwise try again. This sequence can be made atomic by associating a bit with each memory request send by the CPU. The first N-1 operations will have the bit set, while the last one will have it unset, to mark the end of the atomic sequence.
When the memory module (there can be several modules) where the flag data is stored receives the request for the first operation in the sequence (whose bit is set), it will serve it and not take requests from any other CPU until the CPU that initiated the atomic sequence sends a request with an unset atomicity bit (since these transactions are usually short, a coarse-grain approach like this is acceptable). Note that this is usually made easier by the assembler providing specialized instructions of type "compare-and-set", that do exactly what I mentioned before.
Related
In a multi-threading environment, isn’t it that every operation on the RAM must be synchronized?
Let’s say, I have a variable, which is a pointer to another memory address:
foo 12345678
Now, if one thread sets that variable to another memory address (let’s say 89ABCDEF), meanwhile the first thread reads the variable, couldn’t it be that the first thread reads totally trash from the variable if access wouldn’t be synchronized (on some system level)?
foo 12345678 (before)
89ABCDEF (new data)
••••• (writing thread progress)
89ABC678 (memory content)
Since I never saw those things happen I assume that there is some system level synchronization when writing variables. I assume, that this is why it is called an ‘atomic’ operation. As I found here, this problem is actually a topic and not totally fictious from me.
On the other hand, I read everywhere that synchronizing has a significant impact on performance. (Aside from threads that must wait bc. they cannot enter the lock; I mean just the action of locking and unlocking.) Like here:
synchronized adds a significant overhead to the methods […]. These operations are quite expensive […] it has an extreme impact on the program performance. […] the expensive synchronized operations that cause the code to be so terribly slow.
How does this go together? Why is locking for changing a variable unnoticeable fast, but locking for anything else so expensive? Or, is it equally expensive, and there should be a big warning sign when using—let’s say—long and double because they always implicitly require synchronization?
Concerning your first point, when a processor writes some data to memory, this data is always properly written and cannot be "trashed" by other writes by threads processes, OS, etc. It is not a matter of synchronization, just required to insure proper hardware behaviour.
Synchronization is a software concept that requires hardware support. Assume that you just want to acquire a lock. It is supposed to be free when at 0 et locked when at 1.
The basic method to do that is
got_the_lock=0
while(!got_the_lock)
fetch lock value from memory
set lock value in memory to 1
got_the_lock = (fetched value from memory == 0)
done
print "I got the lock!!"
The problem is that if other threads do the same thing at the same time and read lock value before it has been set to 1, several threads may think they got the lock.
To avoid that, one need atomic memory access. An atomic access is typically a read-modify-write cycle to a data in memory that cannot interrupted and that forbids access to this information until completion. So not all accesses are atomic, only specific read-modify-write operation and it is realized thanks tp specific processor support (see test-and-set or fetch-and-add instructions, for instance). Most accesses do not need it and can be a regular access. Atomic access is mostly use to synchronize threads to insure that only one thread is in a critical section.
So why are atomic access expensive ? There are several reasons.
The first one is that one must ensure a proper ordering of instructions. You probably know that instruction order may be different from instruction program order, provided the semantic of the program is respected. This is heavily exploited to improve performances : compiler reorder instructions, processor execute them out-of-order, write-back caches write data in memory in any order, and memory write buffer do the same thing. This reordering can lead to improper behavior.
1 while (x--) ; // random and silly loop
2 f(y);
3 while(test_and_set(important_lock)) ; //spinlock to get a lock
4 g(z);
Obviously instruction 1 is not constraining and 2 can be executed before (and probably 1 will be removed by an optimizing compiler). But if 4 is executed before 3, the behavior will not be as expected.
To avoid that, an atomic access flushes the instruction and memory buffer that requires tens of cycles (see memory barrier).
Without pipeline, you pay the full latency of the operation: read data from memory, modify it and write it back. This latency always happens, but for regular memory accesses you can do other work during that time that largely hides the latency.
An atomic access requires at least 100-200 cycles on modern processors and is accordingly extremely expensive.
How does this go together? Why is locking for changing a variable unnoticeable fast, but locking for anything else so expensive? Or, is it equally expensive, and there should be a big warning sign when using—let’s say—long and double because they always implicitly require synchronization?
Regular memory access are not atomic. Only specific synchronization instructions are expensive.
Synchronization always has a cost involved. And the cost increases with contention due to threads waking up, fighting for lock and only one gets it, and the rest go to sleep resulting in lot of context switches.
However, such contention can be kept at a minimum by using synchronization at a much granular level as in a CAS (compare and swap) operation by CPU, or a memory barrier to read a volatile variable. A far better option is to avoid synchronization altogether without compromising safety.
Consider the following code:
synchronized(this) {
// a DB call
}
This block of code will take several seconds to execute as it is doing a IO and therefore run high chance of creating a contention among other threads wanting to execute the same block. The time duration is enough to build up a massive queue of waiting threads in a busy system.
This is the reason the non-blocking algorithms like Treiber Stack Michael Scott exist. They do a their tasks (which we'd otherwise do using a much larger synchronized block) with the minimum amount of synchronization.
isn’t it that every operation on the RAM must be synchronized?
No. Most of the "operations on RAM" will target memory locations that are only used by one thread. For example, in most programming languages, None of a thread's function arguments or local variables will be shared with other threads; and often, a thread will use heap objects that it does not share with any other thread.
You need synchronization when two or more threads communicate with one another through shared variables. There are two parts to it:
mutual exclusion
You may need to prevent "race conditions." If some thread T updates a data structure, it may have to put the structure into a temporary, invalid state before the update is complete. You can use mutual exclusion (i.e., mutexes/semaphores/locks/critical sections) to ensure that no other thread U can see the data structure when it is in that temporary, invalid state.
cache consistency
On a computer with more than one CPU, each processor typically has its own memory cache. So, when two different threads running on two different processors both access the same data, they may each be looking at their own, separately cached copy. Thus, when thread T updates that shared data structure, it is important to ensure that all of the variables it updated make it into thread U's cache before thread U is allowed to see any of them.
It would totally defeat the purpose of the separate caches if every write by one processor invalidated every other processor's cache, so there typically are special hardware instructions to do that only when it's needed, and typical mutex/lock implementations execute those instructions on entering or leaving a protected block of code.
Hi I am writing kernel code which intends to do process scheduling and multi-threaded execution. I've studied about locking mechanisms and their functionality. Is there a thumb rule regarding what sort of data structure in critical section should be protected by locking (mutex/semaphores/spinlocks)?
I know that where ever there is chance of concurrency in part of code, we require lock. But how do we decide, what if we miss and test cases don't catch them. Earlier I wrote code for system calls and file systems where I never cared about taking locks.
Is there a thumb rule regarding what sort of data structure in critical section should be protected by locking?
Any object (global variable, field of the structure object, etc.), accessed concurrently when one access is write access requires some locking discipline for access.
But how do we decide, what if we miss and test cases don't catch them?
Good practice is appropriate comment for every declaration of variable, structure, or structure field, which requires locking discipline for access. Anyone, who uses this variable, reads this comment and writes corresponded code for access. Kernel core and modules tend to follow this strategy.
As for testing, common testing rarely reveals concurrency issues because of their low probability. When testing kernel modules, I would advice to use Kernel Strider, which attempts to prove correctness of concurrent memory accesses or RaceHound, which increases probability of concurrent issues and checks them.
It is always safe to grab a lock for the duration of any code that accesses any shared data, but this is slow since it means only one thread at a time can run significant chunks of code.
Depending on the data in question though, there may be shortcuts that are safe and fast. If it is a simple integer ( and by integer I mean the native word size of the CPU, i.e. not a 64 bit on a 32 bit cpu ), then you may not need to do any locking: if one thread tries to write to the integer, and the other reads it at the same time, the reader will either get the old value, or the new value, never a mix of the two. If the reader doesn't care that he got the old value, then there is no need for a lock.
If however, you are updating two integers together, and it would be bad for the reader to get the new value for one and the old value for the other, then you need a lock. Another example is if the thread is incrementing the integer. That normally involves a read, add, and write. If one reads the old value, then the other manages to read, add, and write the new value, then the first thread adds and writes the new value, both believe they have incremented the variable, but instead of being incremented twice, it was only incremented once. This needs either a lock, or the use of an atomic increment primitive to ensure that the read/modify/write cycle can not be interrupted. There are also atomic test-and-set primitives so you can read a value, do some math on it, then try to write it back, but the write only succeeds if it still holds the original value. That is, if another thread changed it since the time you read it, the test-and-set will fail, then you can discard your new value and start over with a read of the value the other thread set and try to test-and-set it again.
Pointers are really just integers, so if you set up a data structure then store a pointer to it where another thread can find it, you don't need a lock as long as you set up the structure fully before you store its address in the pointer. Another thread reading the pointer ( it will need to make sure to read the pointer only once, i.e. by storing it in a local variable then using only that to refer to the structure from then on ) will either see the new structure, or the old one, but never an intermediate state. If most threads only read the structure via the pointer, and any that want to write do so either with a lock, or an atomic test-and-set of the pointer, this is sufficient. Any time you want to modify any member of the structure though, you have to copy it to a new one, change the new one, then update the pointer. This is essentially how the kernel's RCU ( read, copy, update ) mechanism works.
Ideally, you must enumerate all the resources available in your system , the related threads and communication, sharing mechanism during design. Determination of the following for every resource and maintaining a proper check list whenever change is made can be of great help :
The duration for which the resource will be busy (Utilization of resource) & type of lock
Amount of tasks queued upon that particular resource (Load) & priority
Type of communication, sharing mechanism related to resource
Error conditions related to resource
If possible, it is better to have a flow diagram depicting the resources, utilization, locks, load, communication/sharing mechanism and errors.
This process can help you in determining the missing scenarios/unknowns, critical sections and also in identification of bottlenecks.
On top of the above process, you may also need certain tools that can help you in testing / further analysis to rule out hidden problems if any :
Helgrind - a Valgrind tool for detecting synchronisation errors.
This can help in identifying data races/synchronization issues due
to improper locking, the lock ordering that can cause deadlocks and
also improper POSIX thread API usage that can have later impacts.
Refer : http://valgrind.org/docs/manual/hg-manual.html
Locksmith - For determining common lock errors that may arise during
runtime or that may cause deadlocks.
ThreadSanitizer - For detecting race condtion. Shall display all accesses & locks involved for all accesses.
Sparse can help to lists the locks acquired and released by a function and also identification of issues such as mixing of pointers to user address space and pointers to kernel address space.
Lockdep - For debugging of locks
iotop - For determining the current I/O usage by processes or threads on the system by monitoring the I/O usage information output by the kernel.
LTTng - For tracing race conditions and interrupt cascades possible. (A successor to LTT - Combination of kprobes, tracepoint and perf functionalities)
Ftrace - A Linux kernel internal tracer for analysing /debugging latency and performance related issues.
lsof and fuser can be handy in determining the processes having lock and the kind of locks.
Profiling can help in determining where exactly the time is being spent by the kernel. This can be done with tools like perf, Oprofile.
The strace can intercept/record system calls that are called by a process and also the signals that are received by a process. It shall show the order of events and all the return/resumption paths of calls.
I'm learning Operating System now, and I'm quite confused with the two concepts - mutex and atomic operation. In my understanding, they are the same, but my OS instructor gave us such a question,
Suppose a multi-processor operating system kernel tracks the number of processes created by each user. This operating system kernel maintains a counter variable for each user that it increments every time it creates a new process for a user and decrements every time a process from that user terminates. Furthermore, this operating system runs on a processor that provides atomic fetch-and-increment and fetch-and-decrement instructions.
Should the operating system update the counter using the atomic increment and decrement instructions, or should it update the counter in a critical section protected by a mutex?
This question indicates that mutex and atomic operation are two things. Could anyone help me with it?
An atomic operation is one that cannot be subdivided into smaller parts. As such, it will never be halfway done, so you can guarantee that it will always be observed in a consistent state. For example, modern hardware implements atomic compare-and-swap operations.
A mutex (short for mutual exclusion) excludes other processes or threads from executing the same section of code (the critical section). Basically, it ensures that at most one thread is executing a given section of code. A mutex is also called a lock.
Underneath the hood, locks must be implemented using hardware somehow, and the implementation must make use of the atomicity guarantees of the underlying hardware.
Most nontrivial operations cannot be made atomic, so you must either use a lock to block other threads from operating while the critical section executes, or else you must carefully design a lock-free algorithm that ensures that all the critical state-changing operations can be safely implemented using atomic operations.
This is a very deep subject, and there is a large body of literature on all these topics. The Wikipedia links I've given are a good starting point, but since you're taking a class on operating systems right now, it might be best for you to ask your professor to provide good resources for learning and understanding this stuff.
If you're a total noob, my answer may be a good place to start. I've just learned how these work, and feel I'm in a good place to relay back.
Generally, both of these are means of avoiding bad things that happen when you read something that's halfway written.
Mutex
A mutex is like the key to a bathroom at a small business. Only one person ever has the key, so if some other person comes along they'll likely have to wait. Here's the rubs:
If someone walks off with the key, then the waiting person never stops waiting.
Nothing can stop some other process from making its own door to the bathroom.
In the context of code, a mutex is mostly the key part, and the person is a process.
Atomic
Atomic means something that can't be split into smaller steps. In the natural world there is no CPU clock -- so everything we do could be smaller steps -- but let's pretend...
When you're typing on your keyboard, every key you hit is an atomic action. It happens all at once, and you can not hit two keys at exactly the same time. Here's what's good about this:
No waiting: the fact that no two keys are being hit at the same time is not because one has to wait. It's because one is always done by the time the next gets there.
No collision: no matter how much you hammer away, you'll never get two characters overlaid. One always happens before the other, completely.
For a counter example, if you were trying to type two words at the same time, that would be not atomic. The letters would mix up.
In the context of code, hitting keys is the same as running a single CPU command. It doesn't matter what other commands are in queue, the one your are doing will finish in its entirety before the next happens.
If you can do something atomically, then you don't have to worry about collision. But not everything is feasible within these bounds. Generally, atomics are for really low level operations -- like getting and setting an primitive (int, boolean, etc). For anything that's going to run a bunch of CPU commands but wants to be atomic, there's a couple tricks:
Use a mutex. Kind of cheating, not really atomic. But some things do this and call themselves atomic.
Carefully writing code such that it never requires more than one concurrent instruction on a piece of data in a row to remain correct. This one gets a bit deeper, but sometimes it can be done.
From here there's tons of reading to get into the nitty gritty details, but this should be enough to give you a foundation understanding of the subject.
first read #Daniel answer then mine.
If your processor provides atomic instructions enough to complete your task you do not need Mutex/locks. In your case fetch-increment and fetch-decrement are supposed to be atomic so you do not need to use Mutex.
Atomic operations use low level/hardware level locks to make some operations ATOMIC: operations which are virtually performed in one go/cpu cycle. So atomic operations never place system in inconsistent state
EDIT
No Atomic and Mutex are not same thing but two opposite things used for same purpose of making sure that state of system should not become inconsistent. You use Mutex for Non-ATOMIC operations while for ATOMIC operations you do not use Mutex.
I think, no matter the whole lot of documentation available, I don't understand why one have to wait for a spin lock in a kernel context.
Why isn't there a specific queue with process requiring a lock with an atomic counter/index and , with preempt disabled, treat them as they come in this list and when the counter is down to 0 on thislist, go back to the main schedule list ?
Two situations :
system underloaded, maybe the spinlock is faster (depends on the lock concurrency at this moment);
system heavily loaded, maybe this strategy is faster (no more wait).
I may miss something very smart here, and I would like to understand it, please.
Thank you
Spinlocks are primarily for use in (or to interoperate with) contexts that cannot block / reschedule. They should only be used where the likelihood of actually waiting for them is relatively low and the lock will not be held long. For example, assume an interrupt handler (and/or other contexts as well) has created a data structure and needs to link it into a doubly-linked list. That will only take nanoseconds to complete and the likelihood of colliding with another process is low, yet it must have an atomic effect: no other cpu/thread should see the list in an intermediate (partially linked) state.
I'm reading the book Crack Code Interview recently, but there's one paragraph confusing me a lot on page 257:
A thread is a particular execution path of a process; when one thread modifies a process resource, the change is immediately visible to sibling threads.
IIRC, if one thread make a change to a variable, the change will firstly save in the CPU cache (say, L1 cache), and will not guarantee to synchronize to other threads unless the variable is declared as volatile.
Am I right?
Nope, you're wrong. But this is a very common misunderstanding.
Every modern multi-core CPU has hardware cache coherence. The L1, and similar caches, are invisible. CPU caches like the L1 cache have nothing to do with memory visibility.
Changes are visible immediately when a thread modifies a process resource. The issue is optimizations that cause process resources not to be modified in precisely the order the code specifies.
If your code has k = j; i = 4; if (j == 2) foo(); an optimizer might see that your first assignment reads the value of j. So it might not bother reading it again when you compare it to 2 since it "knows" that it can't have changed. However, another thread might have changed it. So optimizations of some kinds need to be disabled when synchronization between threads is required. That's what things like volatile do.
If compilers and CPUs made no optimizations and executed a program precisely as it was written, volatile would never be needed. Memory visibility is about optimizations in code (some done by the compiler, some by the CPU), not caches.
I think the text you are quoting is incorrect. The whole idea of the Java Memory Model is to deal with the complex optimizations by modern software & hardware, so that programmers can determine what writes are visible by the respective reads in other threads.
Unless a program in Java is properly synchronized, you can't guarantee that changes by one thread are immediately visible to other threads. Maybe the text refers to a very specific (and weak) memory model.
Usage of volatile variables is just one way to synchronize threads, and it's not suitable for all scenarios.
--Edit--
I think I understand the confusion now... I agree with David Schwartz, assuming that:
1) "modifies a process resource" means the actual change of the resource, not just the execution of a write instruction written in some high level computer language.
2) "is immediately visible to sibling threads" means that other threads are able to see it; it doesn't mean that a thread in your program will necessarily see it. You may still need to use synchronization tools in order to disable optimizations that bypass the actual access to the resource.