I am trying to access a file on my computer using the following code:
new File('c:/test.txt').eachLine{
line->println line
}
I know the file exists, why do I see an error that the file is not found. Is this maybe an issue with my groovy install?
This has nothing to do with the code or your groovy installation.
Recheck the file extension. If you are on Windows 7, the file extensions might be hidden while viewed in the Windows Explorer.
Also, it is better to respect the case sensitivity of filenames, if in case you are working on a Linux machine (which I assume not).
Or perhaps it could also have something to do with file permissions if in case your stack trace looks like this:
java.io.FileNotFoundException: (Permission denied)
If you pass JMS params (-Xms -Xmx etc.) to the groovy command you would get that result. You can find the full explanation here.
Related
Clarification: the directory /george/ exists when I am given the task, and I do know how to read the attribute in cli showing that it is a directory. The balance of the path requested does not exist, so the only way I can tell if 'poppet' is a file or directory is by convention. This question comes from an issue I had with interpretation of this line, so am interested in knowing if there is a convention. This occurred using Ubuntu, but would be relevant in any distro, methinks.
I have started working with the libzip library today. But I do not understand the principle how libzip works.
My focus is on zipping a directory with all the files and dirs within
into a zip-file.
Therefore, I started with zip_open(), then I read the directory
contents and add all the dirs with zip_dir_add() to the archive.
After that, I closed the zip-file with zip_close(). Everything was
fine. The next step should be to add all the files to the archive with
zip_file_add(). But it doesn't work. The last step closing the file
fails.
OK, I forgot to create a zip_source to get this done. I added a
statement a line before to get this source (zip_source_file()). But
still it doesn't work.
What is wrong in my thinking? Do I have to fopen() and fclose() the file on the filesystem also?
And what is the difference between zip_source_file() and zip_source_filep()?
Do I have to fopen() and fclose() the file on the filesystem also?
No, you can just use zip_source_file().
From your comments I think you have the right general idea, but there is probably some detail that is making it fail. Make sure you perform all the error checking the documentation suggests after each libzip call so you can get more information about what is causing it to fail.
You could also compare your code with https://gist.github.com/clalancette/bb5069a09c609e2d33c9858fcc6e170e
I am new to FSL, using version 4.1.8. I am trying to run a script that reads and generates *.nii files, which format is normally supported by FSL. I am calling an FSL function, probtrackx from within Matlab. However, I get the following error message seemingly unable to generate or recognize *.nii files:
** ERROR (nifti_image_read): failed to find header file for '~/Documents/fMRI_data/../DTI/fsl_dti/masks/target_mask_001'
** ERROR: nifti_image_open(~/Documents/fMRI_data/../DTI/fsl_dti/masks/target_mask_001): bad header info
ERROR: failed to open file ~/Documents/fMRI_data/../DTI/fsl_dti/masks/target_mask_001
ERROR: Could not open image ~/Documents/fMRI_data/../DTI/fsl_dti/masks/target_mask_001
The files do exist but FSL fails to recognize them. Any help as to how to correct the issue and get FSL to work properly would be most appreciated. I suspect it's a Linux settings issue, just not sure how to fix it. A solution to a related problem in a previous posting suggested adding ls='ls --color=auto'. I've tried it to on avail.
Some FSL tools assume that the $FSLDIR unix unvironment variable is set, which might not be the case in your MATLAB environment. You can fix that with something like setenv('FSLDIR', '/usr/local/fsl') (modified of course if your FSL installation is in a different place). Some also need the regular FSL setup script to be executed as well: system('. ${FSLDIR}/etc/fslconf/fsl.sh'). See also: http://www.fmrib.ox.ac.uk/fsl/fsl/downloading.html.
Instead of the more complicated probtrackx script, another thing to try first is simply:
system('fslhd ~/Documents/fMRI_data/../DTI/fsl_dti/masks/target_mask_001')
If this fails with the same error, then you know that you entered the path to the data incorrectly. For example, do you mean to have the .. in there?
Also, in the future, the best place to get FSL support is on their mailing list at: https://www.jiscmail.ac.uk/cgi-bin/webadmin?A0=fsl
Does MATLAB have access to run other fsl commands? If you are able to run a command from the command line but not through MATLAB, the MATLAB user may not have access to run fsl or may be looking for some FSL variables.
You might have to do the equivalent of this for a linux system
The problem statement:
I have a J2ME app and i have a separate struts program running. The program automatically changes the source of the J2ME app an then builds it, pre-verify it, and then package it using command line arguments. To achieve all this i have used "Runtime.getRuntime().exec" in my program. Problem is that if i introduce a delay of one sec before the command for packaging is executed, the jar file is still formed BUT accessing the jar file using the command "DataInputStream in = new DataInputStream(new FileInputStream(f));" gives me File Not found exception. "f" is the path to the jar file and i have checked it using "f.getCanonicalPath()" that its the right path.
I don know what the problem is. Please help me. I thank you in advance.
Are you waiting for the Process spawned by Runtime.exec() to complete before accessing the jar file? You can use Process.waitFor() for instance to halt the execution of your thread.
When I launch CruiseControl.NET with a particular configuration file I receive the following error:
ThoughtWorks.CruiseControl.Core.Config.ConfigurationException: Duplicate node detected
What does this mean, and what causes it?
I think you have 2 nodes in your config where it only expected one. Is there any chance you could post the config file it is throwing the exception on here as additional information? I'm using cruisecontrol (not the .net version) currently and find it can be very picky about it's XML files (rightly so) but not tell you anything about where in the file the exceptions were thrown from.
I found that I had an incorrectly structured config file. In particular, some blocks were outside of the configuration section. The error pointed to the second of these exec sections- apparently it didn't like that there was more than one of a given section inside the project.
Thus, the error occurred due a config file like this:
<project>
<tasks>
...
</tasks>
<exec>...</exec>
<exec>...</exec>
<project>
In my case I had something like:
<task>...</task>
<sourceControls>...</sourceControls>
<task>...</task>
<publishers>...</publishers>
It didn't like the two "<task>" nodes so I fixed it by removing the first "<task>" node. I was trying to do some stuff before getting the latest from svn, and then doing the build after that in the second "<task>" node. I'll need to revisit how to do that...any suggestions?