Evening everyone hope on of you gurus can help. I am trying to find the answer to this issue I need to read the data out of the string below by searching the tags. i.e IZTAG UKPART etc however the code I am using is no good as it only stores the 1st part of it for example UKPART = 12999 and misses out the -0112. Is there a better way to search strings ?
UPDATE SO FAR.
#include <stdio.h>
#include <string.h>
#include <windows.h>
int main ()
{
// in my application this comes from the handle and readfile
char buffer[255]="TEST999.UKPART=12999-0112...ISUE-125" ;
//
int i;
int codes[256];
char *pos = buffer;
size_t current = 0;
//
char buffer2[255];
if ((pos=strstr(pos, "UKPART")) != NULL) {
strcpy (buffer2, pos); // buffer2 <= "UKPART=12999-0112...ISUE-125"
}
printf("%s\n", buffer2);
system("pause");
return 0;
}
NOW WORKS BUT RETURN WHOLE STRING AS OUTPUT I NEED TO JUST RETURN UKPART FOR EXAMPLE THANKS SO FAR :-)
strstr() is absolutely the right way to search for the substring. Cool :)
It sounds like you want something different from "sscanf()" to copy the substring.
Q: Why not just use "strcpy ()" instead?
EXAMPLE:
char buffer[255]="IZTAG-12345...UKPART=12999-0112...ISUE-125" ;
char buffer2[255];
if ((pos=strstr(pos, "UKPART")) != NULL) {
strcpy (buffer2, pos); // buffer2 <= "UKPART=12999-0112...ISUE-125"
Related
I'm currently doing the CS50 Harvard Course and I'm stuck in problem set 2.
I made this program that takes a name and prints the initials, it takes the name in the command line. How can I use get_string() instead of argv, and argc wich is very unorthodox and sloppy, so I can prompt the user to give me her/his name. Thank you.
#include <cs50.h>
#include <ctype.h>
#include <stdio.h>
#include <string.h>
int main(int argc, string argv[])
{
//How do I use Get_string() so I don't have to use argv and argc??
//iterate over strings on the vector (words)
for (int i = 0; i < argc; i++)
{
//prints the 0 character of each string, use "toupper" to convert into capital letters
printf("%c", toupper(argv[i][0]));
}
printf("\n");
}
use Array,
let's say for 10 names
string name[10];
for (int i = 0; i < 10; i++)
{
name[i] = get_string("Enter your name: /n");
}
On week 2 of CS50 and I've hit a wall. My code is supposed to prompt a user for plaintext and then print a simple cypher on the next line. Problem is, my code keeps printing the exact input for the user rather than scrambling. My code is below.
Note: the error in my code is likely down in the for loop, inside the respective printf functions.
#include <stdio.h>
#include <cs50.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
int main (int argc, string argv[]){
if (argc != 2){
printf("You must enter two arguments, the second being a single digit integer!\n");
return 1;
}
int key = atoi(argv[1]);
printf("What do you want to encrpyt?");
string s = get_string();
for(int i=0; i < strlen(s); i++){
if (isupper(s[i])==true){
printf("%c",((s[i] + key)));
}
if (islower(s[i])==true){
printf("%c",s[i] + key);
}
else {
printf("%c",s[i]);
}
}
}
Fixed it. The if statement syntax was wrong, so the program was skipping over the cypher text. I need to delete the "==true" out of the if statement.
When I try to read a line from standard input and split it into words, after removing the /n character, I get a core dumped error. Could anyone explain me the reason? What is the correct way to do this?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define LINE_LEN 50
#define MAX_PARTS 50
int main ()
{
char* token;
char *str;
char* arr[MAX_PARTS];
int i,j;
printf("Write a line: \n $:");
fgets(str, LINE_LEN, stdin);
str = strncpy(str, str, strlen(str)-1);
fflush(stdin);
i=0;
token = strtok(str, " ");
while( token != NULL )
{
arr[i] = token;
printf("%s",arr[i]);
i++;
token = strtok(NULL," ");
}
return 0;
}
You are printing the NULL pointer on your last pass through the while() loop. You probably need to reverse the printf() and strtok() calls like this:
while( token != NULL )
{
arr[i] = token;
printf("%s",arr[i]); # Must come first to avoid printing a NULL on final loop
i++;
token = strtok(NULL," ");
}
You are reading into unallocated memory.
char *str;
This declares a pointer str, which is pointing nowhere. (In fact, it points to a random location, but "nowhere" stops the guys who try to second-guess undefined behaviour.)
fgets(str, LINE_LEN, stdin);
This writes to the location str is pointing at, which is nowhere (see above). This is undefined behaviour. If your program happens to survive this (instead of SEGFAULTing right there), you cannot rely on it behaving in any sane manner from this point on.
While we're at it:
fflush(stdin);
Note that the C standard does not define the behaviour of fflush() when called on input streams, i.e. while this is well-defined under Linux (which does define this behaviour), this is a non-standard, non-portable construct that could well crash on other platforms.
I have the following code:
sHexPic = string_to_hex(sPic);
sHexPic.insert(sHexPic.begin() + 2,' ');
sHexPic.insert(2," ");
I would like to know how I can put this into a counted loop and add a space after every 2nd character. So far all this does is make this string "35498700" into "35 498700", which in the end I want the final result to be something like "35 49 87 00".
I assume you would have to get the length of the string and the amount of characters in it.
I am trying to achieve this in c++/cli.
Thanks.
Here's how it would be done in C++, using a string :) (I'm using C libraries cuz I'm more familiar with C)
#include <stdio.h>
#include <string>
using namespace std;
int main()
(
string X;
int i;
int y;
X = 35498700;
y= X.size();
for(i=2;i<y;i+=2)
{
X.insert(i," ");
y=x.size(); //To update size of x
i++; //To skip the inserted space
}
printf("%s",X);
return 0;
}
Have fun :)
That would "probably" work. If it didn't then please mention so :)
Do you know if exist one program or method to see (secuences of)bytes from a text,html file?
Not to see characters, rather see the complete sequence of bytes.
recommendations?
yes, it is called hex editor... Hundreds of those exist out there.
Here are some: http://en.wikipedia.org/wiki/Comparison_of_hex_editors
A common hex editor allows you to view any file's byte sequence.
If you just want to see the existing bytes (without changing them) you can use a hex-dump program, which is much smaller and simpler than a hex editor. For example, here's one I wrote several years ago:
/* public domain by Jerry Coffin
*/
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) {
unsigned long offset = 0;
FILE *input;
int bytes, i, j;
unsigned char buffer[16];
char outbuffer[60];
if ( argc < 2 ) {
fprintf(stderr, "\nUsage: dump filename [filename...]");
return EXIT_FAILURE;
}
for (j=1;j<argc; ++j) {
if ( NULL ==(input=fopen(argv[j], "rb")))
continue;
printf("\n%s:\n", argv[j]);
while (0 < (bytes=fread(buffer, 1, 16, input))) {
sprintf(outbuffer, "%8.8lx: ", offset+=16);
for (i=0;i<bytes;i++) {
sprintf(outbuffer+10+3*i, "%2.2X ",buffer[i]);
if (!isprint(buffer[i]))
buffer[i] = '.';
}
printf("%-60s %*.*s\n", outbuffer, bytes, bytes, buffer);
}
fclose(input);
}
return 0;
}