Linux select statement with extra options - linux

Question

I`m busy with writing a script that can download some files from an FTP and i want a select statement to give the directorys in the ftp sub directory. But also to give a option download all this should happen # $DNAtype at the bottum. Someone any ideas?
My code is:(sorry for the dutch comment)
#!/bin/bash/
#16-03-2012
#Sander van der Zeeuw s1040176
#Variabele om de ftp aan te kunnen roepen
var='ftp://ftp.ensembl.org/pub/release-66/fasta/'
#Hier word de lijst met beschikbare organisme binnengehaald via de functie curl.
# curl is te installeren via de terminal met het command sudo apt-get install curl
lijst=`curl $var | awk '{print $NF}'`
echo "de keuze 0 selecteert alles"
#hier wordt een directory aangemaakt om de files in weg te schrijven
mkdir -p dnaenpep
cd dnaenpep
#Hier wordt een keuze menu gecreeerd om het juiste organisme te kiezen.
select specie in $lijst
do
break
done
echo "Uw keuze is:" $specie
#Hier wordt de keuze "0" ingebouwd. Zodat alle genomen gedownload worden.
if [ "$specie" == "" ]
then
for i in $lijst
do
namen=$(curl $var$i/dna/ | awk '{print($NF)}')
for files in $namen; do curl $var$i/dna/$files -o $files
curl $var$i/pep/$files -o $files
done
done
fi
echo "de keuze 0 selecteert alles"
#Wanneer de loop niet uitgevoerd wordt, zal via nog een select statement de gekozen worden #welk DNA je van de ftp wil downloaden.
lijst2=`curl $var$specie/ | awk '{print $9}'`
echo $lijst2
select dnatype in $lijst2
do
break
done
echo "uw keuze is:" $dnatype
if [$dnatype == ""]
then
for i in $dnatype
do
wget -O DNAtype "$var$specie/dna/"
wget -O DNAtype "$var$specie/pep/"
done
fi
#Hier worden de files die in $dnatype gemaakt worden gedownload.
wget -O DNAtype "$var$specie/$dnatype/"
cat DNAtype | egrep "=" | tr '"' '\n' | sort | grep ^"ftp" |grep gz > Downlist.txt
wget -c -i Downlist.txt
exit

Answer 1

Your select statement should use an array and you can add additional items to the array or add them after the array name in the select statement.
lijst2=($(curl "$var$specie/" | awk '{print $9}')
lijst2+=("Another option" "Additional option" "Download all")
echo "${lijst2[#]}"
select dnatype in "${lijst2[#]}"
do
break
done
echo "uw keuze is: $dnatype"
or
lijst2=($(curl "$var$specie/" | awk '{print $9}')
echo "${lijst2[#]}"
select dnatype in "${lijst2[#]}" "Another option" "Additional option" "Download all"
do
break
done
echo "uw keuze is: $dnatype"
Which you choose depends on whether you want the added options in the array.
To download all, just iterate over the array (so you'll probably want to use the second version so you don't have to skip over "Download all", for example, since it's not a filename.
Additional notes:
Use $() instead of backticks for command substitution.
This statement if [$dnatype == ""] needs spaces: if [ $dnatype == "" ].
Quote all your variables when they are expanded. You have done this in some places, but not others.
Your long pipeline near the end can almost certainly be simplified. Without seeing example data I could only guess how.