tl;dr: need a way to process (with grep) an output inside subshell AND redirect all original output to the main stdout/stderr at the same time. I am looking for shell-independent (!) way.
In detail
There is a proprietary binary which I want to grep for some value
The proprietary binary from time to time might be interactive to ask for a password (depends on the internal logic)
I want to grep the output of the binary AND want being able to enter the password it that is required to proceed further
So the script which is supposed to achieve my task might look like:
#!/bin/sh
user_id=... # some calculated value
list_actions_cmd="./proprietary-binary --actions ${user_id}"
action_item=$(${list_actions_cmd} | grep '^Main:')
Here proprietary-binary might ask for a password through stdin. Since subshell inside $() catches the all output, an end-user won't understand that the list_actions_cmd waits for input. What I want is either to show all output of list_action_cmd AND grepping at the same time or at least caught the keyword that now user will be asked for a password and let him know about that.
Currently what I figured out is to tee the output and grep there:
#!/bin/sh
user_id=... # some calculated value
list_actions_cmd="./proprietary-binary --actions ${user_id}"
$list_actions_cmd 2>&1 | tee /tmp/.proprietary-binary.log
action_item=$(grep "^Main" /tmp/.proprietary-binary.log)
But I wonder is there any elegant shell-independent (not limited to bash which is quite powerful) solution without any intermediate temporary file? Thanks.
What about duplicating output to stderr if executed in a terminal:
item=$(your_command | tee /dev/stderr | grep 'regexp')
I'm using this code to write all terminal's output to the file
exec > >(tee -a "${LOG_FILE}" )
exec 2> >(tee -a "${LOG_FILE}" >&2)
How to tell it to stop? If, for example, I don't want some output to get into log..
Thank you!
It's not completely clear what your goal is here, but here is something to try.
Do you know about the script utility? You can run script myTerminalOutputFile and any commands and output after that will be captured to myTerminalOutputFile. The downside is that it captures everything. You'll see funny screen control chars like ^[[5m;27j. So do a quick test to see if that works for you.
To finish capturing output just type exit and you are returned to you parent shell cmd-line.
Warning: check man script for details about the inherent funkyness of your particular OS's version of script. Some are better than others. script -k myTerminalOutputFile may work better in this case.
IHTH
You may pipe through "sed" and then tee to log file
For some reasons not relevant to this question, I am running a Java server in a bash script not directly but via command substitution under a separate sub-shell, and in the background. The intent is for the subcommand to return the process id of the Java server as its standard output. The fragement in question is as follows:
launch_daemon()
{
/bin/bash <<EOF
$JAVA_HOME/bin/java $JAVA_OPTS -jar $JAR_FILE daemon $PWD/config/cl.yml <&- &
pid=\$!
echo \${pid} > $PID_FILE
echo \${pid}
EOF
}
daemon_pid=$(launch_daemon)
echo ${daemon_pid} > check.out
The Java daemon in question prints to standard error and quits if there is a problem in initialization, otherwise it closes standard out and standard err and continues on its way. Later in the script (not shown) I do a check to make sure the server process is running. Now on to the problem.
Whenever I check the $PID_FILE above, it contains the correct process id on one line.
But when I check the file check.out, it sometimes contains the correct id, other times it contains the process id repeated twice on the same line separated by a space charcater as in:
34056 34056
I am using the variable $daemon_pid in the script above later on in the script to check if the server is running, so if it contains the pid repeated twice this totally throws off the test and it incorrectly thinks the server is not running. Fiddling with the script on my server box running CentOS Linux by putting in more echo statements etc. seems to flip the behavior back to the correct one of $daemon_pid containing the process id just once, but if I think that has fixed it and check in this script to my source code repo and do a build and deploy again, I start seeing the same bad behavior.
For now I have fixed this by assuming that $daemon_pid could be bad and passing it through awk as follows:
mypid=$(echo ${daemon_pid} | awk '{ gsub(" +.*",""); print $0 }')
Then $mypid always contains the correct process id and things are fine, but needless to say I'd like to understand why it behaves the way it does. And before you ask, I have looked and looked but the Java server in question does NOT print its process id to its standard out before closing standard out.
Would really appreciate expert input.
Following the hint by #WilliamPursell, I tracked this down in the bash source code. I honestly don't know whether it is a bug or not; all I can say is that it seems like an unfortunate interaction with a questionable use case.
TL;DR: You can fix the problem by removing <&- from the script.
Closing stdin is at best questionable, not just for the reason mentioned by #JonathanLeffler ("Programs are entitled to have a standard input that's open.") but more importantly because stdin is being used by the bash process itself and closing it in the background causes a race condition.
In order to see what's going on, consider the following rather odd script, which might be called Duff's Bash Device, except that I'm not sure that even Duff would approve: (also, as presented, it's not that useful. But someone somewhere has used it in some hack. Or, if not, they will now that they see it.)
/bin/bash <<EOF
if (($1<8)); then head -n-$1 > /dev/null; fi
echo eight
echo seven
echo six
echo five
echo four
echo three
echo two
echo one
EOF
For this to work, bash and head both have to be prepared to share stdin, including sharing the file position. That means that bash needs to make sure that it flushes its read buffer (or not buffer), and head needs to make sure that it seeks back to the end of the part of the input which it uses.
(The hack only works because bash handles here-documents by copying them into a temporary file. If it used a pipe, it wouldn't be possible for head to seek backwards.)
Now, what would have happened if head had run in the background? The answer is, "just about anything is possible", because bash and head are racing to read from the same file descriptor. Running head in the background would be a really bad idea, even worse than the original hack which is at least predictable.
Now, let's go back to the actual program at hand, simplified to its essentials:
/bin/bash <<EOF
cmd <&- &
echo \$!
EOF
Line 2 of this program (cmd <&- &) forks off a separate process (to run in the background). In that process, it closes stdin and then invokes cmd.
Meanwhile, the foreground process continues reading commands from stdin (its stdin fd hasn't been closed, so that's fine), which causes it to execute the echo command.
Now here's the rub: bash knows that it needs to share stdin, so it can't just close stdin. It needs to make sure that stdin's file position is pointing to the right place, even though it may have actually read ahead a buffer's worth of input. So just before it closes stdin, it seeks backwards to the end of the current command line. [1]
If that seek happens before the foreground bash executes echo, then there is no problem. And if it happens after the foreground bash is done with the here-document, also no problem. But what if it happens while the echo is working? In that case, after the echo is done, bash will reread the echo command because stdin has been rewound, and the echo will be executed again.
And that's precisely what is happening in the OP. Sometimes, the background seek completes at just the wrong time, and causes echo \${pid} to be executed twice. In fact, it also causes echo \${pid} > $PID_FILE to execute twice, but that line is idempotent; had it been echo \${pid} >> $PID_FILE, the double execution would have been visible.
So the solution is simple: remove <&- from the server start-up line, and optionally replace it with </dev/null if you want to make sure the server can't read from stdin.
Notes:
Note 1: For those more familiar with bash source code and its expected behaviour than I am, I believe that the seek and close takes place at the end of case r_close_this: in function do_redirection_internal in redir.c, at approximately line 1093:
check_bash_input (redirector);
close_buffered_fd (redirector);
The first call does the lseek and the second one does the close. I saw the behaviour using strace -f and then searched the code for a plausible looking lseek, but I didn't go to the trouble of verifying in a debugger.
I have written a Fortran program (let's call it program.exe) with does some simulation for me. Via ssh I'm logging ino some far away computers to start runs there whose results I collect after a few days. To be up-to-date how the program proceeds I want to write the shell output into a text file output.txt also (since I can't be logged in the far away computers all the time). The command should be something like
nohup program.exe | tee output.txt > /dev/null &
This enables me to have a look at output.txt to see the current status even though the program hasn't ended its run yet. The above command works fine on my local machine. I tried first with the command '>' but here the problem was that nothing was written into the text file until the whole program had finish (maybe related to the pipe buffer?). So I used the workaround with 'tee'.
The problem is now that when I log into the computer via ssh (ssh -X user#machine), execute the above command and look at output.txt with the VI editor nothing appears until the program has finished. If I omit the 'nohup' and '&' I will not even get any shell output until it has finished. My thought was that it might have to do something with data being buffered by ssh but I'm rather a Linux newbie. For any ideas or workaround I would be very grateful!
I would use screen utility http://www.oreillynet.com/linux/cmd/cmd.csp?path=s/screen instead of nohup. Thus I would be able to set my program to detached state (^A^D) reconnect to the host, retrieve my screen session (screen -r)
and monitor my output as if I never logged out.
I am new to using tee command.
I am trying to run one of my program which takes long time to finish but it prints out information as it progresses. I am using 'tee' to save the output to a file as well as to see the output in the shell (bash).
But the problem is tee doesn't forward the output to shell until the end of my command.
Is there any way to do that ?
I am using Debian and bash.
This actually depends on the amount of output and the implementation of whatever command you are running. No program is obliged to print stuff straight to stdout or stderr and flush it all the time. So even though most C runtime implementation flush after a certain amount of data was written using one of the runtime routines, such as printf, this may not be true depending on the implementation.
It tee doesn't output it right away, it is likely only receiving the input at the very end of the run of your command. It might be helpful to mention which exact command it is.
The problem you are experienced is most probably related to buffering.
You may have a look at stdbuf command, which does the following:
stdbuf - Run COMMAND, with modified buffering operations for its standard streams.
If you were to post your usage I could give a better answer, but as it is
(for i in `seq 10`; do echo $i; sleep 1s; done) | tee ./tmp
Is proper usage of the tee command and seems to work. Replace the part before the pipe with your command and you should be good to go.