How to number lines read from a file using conduits? - haskell

I'm a Haskell beginner trying to wrap my head around the conduit library.
I've tried something like this, but it does not compile:
import Data.Conduit
import Data.Conduit.Binary as CB
import Data.ByteString.Char8 as BS
numberLine :: Monad m => Conduit BS.ByteString m BS.ByteString
numberLine = conduitState 0 push close
where
push lno input = return $ StateProducing (lno + 1) [BS.pack (show lno ++ BS.unpack input)]
close state = return state
main = do
runResourceT $ CB.sourceFile "wp.txt" $= CB.lines $= numberLine $$ CB.sinkFile "test.txt"
It seems that the state in conduitState must be of the same type as the conduit's input type. Or at least that's what I understand from the error message:
$ ghc --make exp.hs
[1 of 1] Compiling Main ( exp.hs, exp.o )
exp.hs:8:27:
Could not deduce (Num [ByteString]) arising from the literal `0'
from the context (Monad m)
bound by the type signature for
numberLine :: Monad m => Conduit ByteString m ByteString
at exp.hs:(8,1)-(11,30)
Possible fix:
add (Num [ByteString]) to the context of
the type signature for
numberLine :: Monad m => Conduit ByteString m ByteString
or add an instance declaration for (Num [ByteString])
In the first argument of `conduitState', namely `0'
In the expression: conduitState 0 push close
In an equation for `numberLine':
numberLine
= conduitState 0 push close
where
push lno input
= return
$ StateProducing (lno + 1) [pack (show lno ++ unpack input)]
close state = return state
How can this be done using conduits? I want to read lines from a file and append a line number to each line.

Yes, it can be done. I prefer to use the helper functions in Data.Conduit.List and also avoid Data.ByteString.Char8 if at all possible. I'm assuming your file is UTF-8 encoded.
import Data.Conduit
import Data.Conduit.Binary as CB
import Data.Conduit.List as Cl
import Data.Conduit.Text as Ct
import Data.Monoid ((<>))
import Data.Text as T
numberLine :: Monad m => Conduit Text m Text
numberLine = Cl.concatMapAccum step 0 where
format input lno = T.pack (show lno) <> T.pack " " <> input <> T.pack "\n"
step input lno = (lno+1, [format input lno])
main :: IO ()
main =
runResourceT
$ CB.sourceFile "wp.txt"
$$ Ct.decode Ct.utf8
=$ Ct.lines
=$ numberLine
=$ Ct.encode Ct.utf8
=$ CB.sinkFile "test.txt"

close state = return state
Herein lies the type error. Your close function should have type (state -> m [output]) (as per the docs). In your case state = Int (you may want to add type annotations to make sure it selects Int) and output = BS.ByteString, so probably just return the empty list, since at the point of closing the conduit, you haven't really saved any ByteStrings to produce or anything like that.
close _ = return []
Especially note from the docs for that argument:
The state need not be returned, since it will not be used again

An alternative solution with pipes 3.0, though it does use string instead of ByteString. The main advantage in my mind is being able to use the normal state monad methods get and put. Another benefit is that the starting line number is not hidden in the addLineNumber(numberLine) so it is easier to start at any given line number.
import System.IO
import Data.Monoid ((<>))
import Control.Proxy
import qualified Control.Proxy.Trans.State as S
addLineNumber r = forever $ do
n <- S.get
line <- request r -- request line from file
respond $ show n <> " " <> line
S.put (n + 1) -- increments line counter
main =
withFile "wp.txt" ReadMode $ \fin ->
withFile "test.txt" WriteMode $ \fout ->
runProxy $ S.execStateK 1 -- start at line number at 1
$ hGetLineS fin >-> addLineNumber >-> hPutStrLnD fout
Find out how to do more fine grained resource management at the announce blog post of pipes-safe..

Related

Filtering ANSI escape sequences from a ByteString with Conduit

I'm trying to make a Conduit that filters ANSI escape codes from ByteStrings. I've come up with a function that converts the ByteString into a stream of Word8's, does the filtering, and converts back into a stream of ByteStream at the end.
It seems to work fine when I use it in GHCi:
> runConduit $ yield "hello\27[23;1m world" .| ansiFilter .| printC
"hello world"
When I use it in my application, conduits that contain ansiFilter don't seem to pass anything through. Here is the full source:
{-# LANGUAGE OverloadedStrings #-}
module Main where
import Conduit
import Control.Concurrent.Async
import Control.Concurrent.STM
import Data.ByteString (ByteString)
import qualified Data.ByteString as BS
import Data.Conduit.TQueue
import Data.Word8 (Word8)
import qualified Data.Word8 as Word8
main :: IO ()
main = do
queue <- atomically $ newTBQueue 25
let qSource = sourceTBQueue queue
atomically $ writeTBQueue queue ("hello" :: ByteString)
race_
(putInputIntoQueue queue)
(doConversionAndPrint qSource)
putInputIntoQueue q =
runConduit
$ stdinC
.| iterMC (atomically . writeTBQueue q)
.| sinkNull
doConversionAndPrint src =
runConduit
$ src
.| ansiFilter
.| stdoutC
ansiFilter :: MonadIO m => ConduitM ByteString ByteString m ()
ansiFilter = toWord8 .| ansiFilter' .| toByteString
where
ansiFilter' = awaitForever $ \first -> do
msecond <- peekC
case (first, msecond) of
(0x1b, Just 0x5b) -> do
dropWhileC (not . Word8.isLetter)
dropC 1
_ -> yield first
toWord8 = concatC
toByteString :: Monad m => ConduitM Word8 ByteString m ()
toByteString =
(mapC BS.singleton .| foldC) >>= yield
This program is supposed to echo back the filtered contents of stdin, but nothing gets echoed back.
However, if I comment out the ansiFilter in doConversionAndPrint, echoing does work which makes me thing the ansiFilter function is wrong.
Any help would be greatly appreciated!
I reimplemented ansiFilter in terms of the higher level chunked data functions in conduit-combinator, like takeWhileCE. This seems to work, and should be more efficient by letting more of the data remain in an efficient memory representation:
ansiFilter :: MonadIO m => ConduitM ByteString ByteString m ()
ansiFilter = loop
where
loop = do
takeWhileCE (/= 0x1b)
mfirst <- headCE
case mfirst of
Nothing -> return ()
Just first -> assert (first == 0x1b) $ do
msecond <- peekCE
case msecond of
Just 0x5b -> do
dropWhileCE (not . Word8.isLetter)
dropCE 1
_ -> yield $ BS.singleton first
loop
Went with a slightly different approach and am having more luck leaving the ByteStrings alone. I think this gives up some of the streaming stuff, but is acceptable for my use-case.
ansiFilter :: Monad m => Conduit ByteString m ByteString
ansiFilter = mapC (go "")
where
csi = "\27["
go acc "" = acc
go acc remaining = go (acc <> filtered) (stripCode unfiltered)
where
(filtered, unfiltered) = BS.breakSubstring csi remaining
stripCode bs = BS.drop 1 (BS.dropWhile (not . Word8.isLetter) bs)

Efficient streaming and manipulation of a byte stream in Haskell

While writing a deserialiser for a large (<bloblength><blob>)* encoded binary file I got stuck with the various Haskell produce-transform-consume libraries. So far I'm aware of four streaming libraries:
Data.Conduit: Widely used, has very careful resource management
Pipes: Similar to conduit (Haskell Cast #6 nicely reveals the differences between conduit and pipes)
Data.Binary.Get: Offers useful functions such as getWord32be, but the streaming example is awkward
System.IO.Streams: Seems to be the easiest one to use
Here's a stripped down example of where things go wrong when I try to do Word32 streaming with conduit. A slightly more realistic example would first read a Word32 that determines the blob length and then yield a lazy ByteString of that length (which is then deserialised further).
But here I just try to extract Word32's in streaming fashion from a binary file:
module Main where
-- build-depends: bytestring, conduit, conduit-extra, resourcet, binary
import Control.Monad.Trans.Resource (MonadResource, runResourceT)
import qualified Data.Binary.Get as G
import qualified Data.ByteString as BS
import qualified Data.ByteString.Char8 as C
import qualified Data.ByteString.Lazy as BL
import Data.Conduit
import qualified Data.Conduit.Binary as CB
import qualified Data.Conduit.List as CL
import Data.Word (Word32)
import System.Environment (getArgs)
-- gets a Word32 from a ByteString.
getWord32 :: C.ByteString -> Word32
getWord32 bs = do
G.runGet G.getWord32be $ BL.fromStrict bs
-- should read BytesString and return Word32
transform :: (Monad m, MonadResource m) => Conduit BS.ByteString m Word32
transform = do
mbs <- await
case mbs of
Just bs -> do
case C.null bs of
False -> do
yield $ getWord32 bs
leftover $ BS.drop 4 bs
transform
True -> return ()
Nothing -> return ()
main :: IO ()
main = do
filename <- fmap (!!0) getArgs -- should check length getArgs
result <- runResourceT $ (CB.sourceFile filename) $$ transform =$ CL.consume
print $ length result -- is always 8188 for files larger than 32752 bytes
The output of the program is just the number of Word32's that were read. It turns out the stream terminates after reading the first chunk (about 32KiB). For some reason mbs is never Nothing, so I must check null bs which stops the stream when the chunk is consumed. Clearly, my conduit transform is faulty. I see two routes to a solution:
The await doesn't want to go to the second chunk of the ByteStream, so is there another function that pulls the next chunk? In examples I've seen (e.g. Conduit 101) this is not how it's done
This is just the wrong way to set up transform.
How is this done properly? Is this the right way to go? (Performance does matter.)
Update: Here's a BAD way to do it using Systems.IO.Streams:
module Main where
import Data.Word (Word32)
import System.Environment (getArgs)
import System.IO (IOMode (ReadMode), openFile)
import qualified System.IO.Streams as S
import System.IO.Streams.Binary (binaryInputStream)
import System.IO.Streams.List (outputToList)
main :: IO ()
main = do
filename : _ <- getArgs
h <- openFile filename ReadMode
s <- S.handleToInputStream h
i <- binaryInputStream s :: IO (S.InputStream Word32)
r <- outputToList $ S.connect i
print $ last r
'Bad' means: Very demanding in time and space, does not handle Decode exception.
Your immediate problem is caused by how you are using leftover. That function is used to "Provide a single piece of leftover input to be consumed by the next component in the current monadic binding", and so when you give it bs before looping with transform you are effectively throwing away the rest of the bytestring (i.e. what is after bs).
A correct solution based on your code would use the incremental input interface of Data.Binary.Get to replace your yield/leftover combination with something that consumes each chunk fully. A more pragmatic approach, though, is using the binary-conduit package, which provides that in the shape of conduitGet (its source gives a good idea of what a "manual" implementation would look like):
import Data.Conduit.Serialization.Binary
-- etc.
transform :: (Monad m, MonadResource m) => Conduit BS.ByteString m Word32
transform = conduitGet G.getWord32be
One caveat is that this will throw a parse error if the total number of bytes is not a multiple of 4 (i.e. the last Word32 is incomplete). In the unlikely case of that not being what you want, a lazy way out would be simply using \bs -> C.take (4 * truncate (C.length bs / 4)) bs on the input bytestring.
With pipes (and pipes-group and pipes-bytestring) the demo problem reduces to combinators. First we resolve the incoming undifferentiated byte stream into little 4 byte chunks:
chunksOfStrict :: (Monad m) => Int -> Producer ByteString m r -> Producer ByteString m r
chunksOfStrict n = folds mappend mempty id . view (Bytes.chunksOf n)
then we map these to Word32s and (here) count them.
main :: IO ()
main = do
filename:_ <- getArgs
IO.withFile filename IO.ReadMode $ \h -> do
n <- P.length $ chunksOfStrict 4 (Bytes.fromHandle h) >-> P.map getWord32
print n
This will fail if we have less than 4 bytes or otherwise fail to parse but we can as well map with
getMaybeWord32 :: ByteString -> Maybe Word32
getMaybeWord32 bs = case G.runGetOrFail G.getWord32be $ BL.fromStrict bs of
Left r -> Nothing
Right (_, off, w32) -> Just w32
The following program will then print the parses for the valid 4 byte sequences
main :: IO ()
main = do
filename:_ <- getArgs
IO.withFile filename IO.ReadMode $ \h -> do
runEffect $ chunksOfStrict 4 (Bytes.fromHandle h)
>-> P.map getMaybeWord32
>-> P.concat -- here `concat` eliminates maybes
>-> P.print
There are other ways of dealing with failed parses, of course.
Here, though, is something closer to the program you asked for. It takes a four byte segment from a byte stream (Producer ByteString m r) and reads it as a Word32 if it is long enough; it then takes that many of the incoming bytes and accumulates them into a lazy bytestring, yielding it. It just repeats this until it runs out of bytes. In main below, I print each yielded lazy bytestring that is produced:
module Main (main) where
import Pipes
import qualified Pipes.Prelude as P
import Pipes.Group (folds)
import qualified Pipes.ByteString as Bytes ( splitAt, fromHandle, chunksOf )
import Control.Lens ( view ) -- or Lens.Simple (view) -- or Lens.Micro ((.^))
import qualified System.IO as IO ( IOMode(ReadMode), withFile )
import qualified Data.Binary.Get as G ( runGet, getWord32be )
import Data.ByteString ( ByteString )
import qualified Data.ByteString.Lazy.Char8 as BL
import System.Environment ( getArgs )
splitLazy :: (Monad m, Integral n) =>
n -> Producer ByteString m r -> m (BL.ByteString, Producer ByteString m r)
splitLazy n bs = do
(bss, rest) <- P.toListM' $ view (Bytes.splitAt n) bs
return (BL.fromChunks bss, rest)
measureChunks :: Monad m => Producer ByteString m r -> Producer BL.ByteString m r
measureChunks bs = do
(lbs, rest) <- lift $ splitLazy 4 bs
if BL.length lbs /= 4
then rest >-> P.drain -- in fact it will be empty
else do
let w32 = G.runGet G.getWord32be lbs
(lbs', rest') <- lift $ splitLazy w32 bs
yield lbs
measureChunks rest
main :: IO ()
main = do
filename:_ <- getArgs
IO.withFile filename IO.ReadMode $ \h -> do
runEffect $ measureChunks (Bytes.fromHandle h) >-> P.print
This is again crude in that it uses runGet not runGetOrFail, but this is easily repaired. The pipes standard procedure would be to stop the stream transformation on a failed parse and return the unparsed bytestream.
If you were anticipating that the Word32s were for large numbers, so that you did not want to accumulate the corresponding stream of bytes as a lazy bytestring, but say write them to different files without accumulating, we could change the program pretty easily to do that. This would require a sophisticated use of conduit but is the preferred approach with pipes and streaming.
Here's a relatively straightforward solution that I want to throw into the ring. It's a repeated use of splitAt wrapped into a State monad that gives an interface identical to (a subset of) Data.Binary.Get. The resulting [ByteString] is obtained in main with a whileJust over getBlob.
module Main (main) where
import Control.Monad.Loops
import Control.Monad.State
import qualified Data.Binary.Get as G (getWord32be, runGet)
import qualified Data.ByteString.Lazy as BL
import Data.Int (Int64)
import Data.Word (Word32)
import System.Environment (getArgs)
-- this is going to mimic the Data.Binary.Get.Get Monad
type Get = State BL.ByteString
getWord32be :: Get (Maybe Word32)
getWord32be = state $ \bs -> do
let (w, rest) = BL.splitAt 4 bs
case BL.length w of
4 -> (Just w', rest) where
w' = G.runGet G.getWord32be w
_ -> (Nothing, BL.empty)
getLazyByteString :: Int64 -> Get BL.ByteString
getLazyByteString n = state $ \bs -> BL.splitAt n bs
getBlob :: Get (Maybe BL.ByteString)
getBlob = do
ml <- getWord32be
case ml of
Nothing -> return Nothing
Just l -> do
blob <- getLazyByteString (fromIntegral l :: Int64)
return $ Just blob
runGet :: Get a -> BL.ByteString -> a
runGet g bs = fst $ runState g bs
main :: IO ()
main = do
fname <- head <$> getArgs
bs <- BL.readFile fname
let ls = runGet loop bs where
loop = whileJust getBlob return
print $ length ls
There's no error handling in getBlob, but it's easy to extend. Time and space complexity is quite good, as long as the resulting list is used carefully. (The python script that creates some random data for consumption by the above is here).

How to parse a large XML file in Haskell with limited amount of resources?

I want to extract information from a large XML file (around 20G) in Haskell. Since it is a large file, I used SAX parsing functions from Hexpath.
Here is a simple code I tested:
import qualified Data.ByteString.Lazy as L
import Text.XML.Expat.SAX as Sax
parse :: FilePath -> IO ()
parse path = do
inputText <- L.readFile path
let saxEvents = Sax.parse defaultParseOptions inputText :: [SAXEvent Text Text]
let txt = foldl' processEvent "" saxEvents
putStrLn txt
After activating profiling in Cabal, it says that parse.saxEvents took 85% of allocated memory. I also used foldr and the result is the same.
If processEvent becomes complex enough, the program crashes with a stack space overflow error.
What am I doing wrong?
You don't say what processEvent is like. In principle, it ought to be unproblematic to use lazy ByteString for a strict left fold over lazily generated input, so I'm not sure what is going wrong in your case. But one ought to use streaming-appropriate types when dealing with gigantic files!
In fact, hexpat does have 'streaming' interface (just like xml-conduit). It uses the not-too-well known List library and the rather ugly List class it defines. In principle the ListT type from the List package should work well. I gave up quickly because of a lack of combinators, and wrote an appropriate instance of the ugly List class for a wrapped version of Pipes.ListT which I then used to export ordinary Pipes.Producer functions like parseProduce. The trivial manipulations needed for this are appended below as PipesSax.hs
Once we have parseProducer we can convert a ByteString or Text Producer into a Producer of SaxEvents with Text or ByteString components. Here are some simple operations. I was using a 238M "input.xml"; the programs never need more than 6 mb of memory, to judge from looking at top.
-- Sax.hs Most of the IO actions use a registerIds pipe defined at the bottom which is tailored to a giant bit of xml of which this is a valid 1000 fragment http://sprunge.us/WaQK
{-#LANGUAGE OverloadedStrings #-}
import PipesSax ( parseProducer )
import Data.ByteString ( ByteString )
import Text.XML.Expat.SAX
import Pipes -- cabal install pipes pipes-bytestring
import Pipes.ByteString (toHandle, fromHandle, stdin, stdout )
import qualified Pipes.Prelude as P
import qualified System.IO as IO
import qualified Data.ByteString.Char8 as Char8
sax :: MonadIO m => Producer ByteString m ()
-> Producer (SAXEvent ByteString ByteString) m ()
sax = parseProducer defaultParseOptions
-- stream xml from stdin, yielding hexpat tagstream to stdout;
main0 :: IO ()
main0 = runEffect $ sax stdin >-> P.print
-- stream the extracted 'IDs' from stdin to stdout
main1 :: IO ()
main1 = runEffect $ sax stdin >-> registryIds >-> stdout
-- write all IDs to a file
main2 =
IO.withFile "input.xml" IO.ReadMode $ \inp ->
IO.withFile "output.txt" IO.WriteMode $ \out ->
runEffect $ sax (fromHandle inp) >-> registryIds >-> toHandle out
-- folds:
-- print number of IDs
main3 = IO.withFile "input.xml" IO.ReadMode $ \inp ->
do n <- P.length $ sax (fromHandle inp) >-> registryIds
print n
-- sum the meaningful part of the IDs - a dumb fold for illustration
main4 = IO.withFile "input.xml" IO.ReadMode $ \inp ->
do let pipeline = sax (fromHandle inp) >-> registryIds >-> P.map readIntId
n <- P.fold (+) 0 id pipeline
print n
where
readIntId :: ByteString -> Integer
readIntId = maybe 0 (fromIntegral.fst) . Char8.readInt . Char8.drop 2
-- my xml has tags with attributes that appear via hexpat thus:
-- StartElement "FacilitySite" [("registryId","110007915364")]
-- and the like. This is just an arbitrary demo stream manipulation.
registryIds :: Monad m => Pipe (SAXEvent ByteString ByteString) ByteString m ()
registryIds = do
e <- await -- we look for a 'SAXEvent'
case e of -- if it matches, we yield, else we go to the next event
StartElement "FacilitySite" [("registryId",a)] -> do yield a
yield "\n"
registryIds
_ -> registryIds
-- 'library': PipesSax.hs
This just newtypes Pipes.ListT to get the appropriate instances. We don't export anything to do with List or ListT but just use the standard Pipes.Producer concept.
{-#LANGUAGE TypeFamilies, GeneralizedNewtypeDeriving #-}
module PipesSax (parseProducerLocations, parseProducer) where
import Data.ByteString (ByteString)
import Text.XML.Expat.SAX
import Data.List.Class
import Control.Monad
import Control.Applicative
import Pipes
import qualified Pipes.Internal as I
parseProducer
:: (Monad m, GenericXMLString tag, GenericXMLString text)
=> ParseOptions tag text
-> Producer ByteString m ()
-> Producer (SAXEvent tag text) m ()
parseProducer opt = enumerate . enumerate_
. parseG opt
. Select_ . Select
parseProducerLocations
:: (Monad m, GenericXMLString tag, GenericXMLString text)
=> ParseOptions tag text
-> Producer ByteString m ()
-> Producer (SAXEvent tag text, XMLParseLocation) m ()
parseProducerLocations opt =
enumerate . enumerate_ . parseLocationsG opt . Select_ . Select
newtype ListT_ m a = Select_ { enumerate_ :: ListT m a }
deriving (Functor, Monad, MonadPlus, MonadIO
, Applicative, Alternative, Monoid, MonadTrans)
instance Monad m => List (ListT_ m) where
type ItemM (ListT_ m) = m
joinL = Select_ . Select . I.M . liftM (enumerate . enumerate_)
runList = liftM emend . next . enumerate . enumerate_
where
emend (Right (a,q)) = Cons a (Select_ (Select q))
emend _ = Nil

Haskell Conduit: having a Sink return a value based on the values from upstream

I've been trying to use the Conduit library to do some simple I/O involving files, but I'm having a hard time.
I have a text file containing nothing but a few digits such as 1234. I have a function that reads the file using readFile (no conduits), and returns Maybe Int (Nothing is returned when the file actually doesn't exist). I'm trying to write a version of this function that uses conduits, and I just can't figure it out.
Here is what I have:
import Control.Monad.Trans.Resource
import Data.Conduit
import Data.Functor
import System.Directory
import qualified Data.ByteString.Char8 as B
import qualified Data.Conduit.Binary as CB
import qualified Data.Conduit.Text as CT
import qualified Data.Text as T
myFile :: FilePath
myFile = "numberFile"
withoutConduit :: IO (Maybe Int)
withoutConduit = do
doesExist <- doesFileExist myFile
if doesExist
then Just . read <$> readFile myFile
else return Nothing
withConduit :: IO (Maybe Int)
withConduit = do
doesExist <- doesFileExist myFile
if doesExist
then runResourceT $ source $$ conduit =$ sink
else return Nothing
where
source :: Source (ResourceT IO) B.ByteString
source = CB.sourceFile myFile
conduit :: Conduit B.ByteString (ResourceT IO) T.Text
conduit = CT.decodeUtf8
sink :: Sink T.Text (ResourceT IO) (Maybe Int)
sink = awaitForever $ \txt -> let num = read . T.unpack $ txt :: Int
in -- I don't know what to do here...
Could someone please help me complete the sink function?
Thanks!
This isn't really a good example for where conduit actually provides a lot of value, at least not the way you're looking at it right now. Specifically, you're trying to use the read function, which requires that the entire value be in memory. Additionally, your current error handling behavior is a bit loose. Essentially, you're just going to get an read: no parse error if there's anything unexpected in the content.
However, there is a way we can play with this in conduit and be meaningful: by parsing the ByteString byte-by-byte ourselves and avoiding the read function. Fortunately, this pattern falls into a standard left fold, which the conduit-combinators package provides a perfect function for (element-wise left fold in a conduit, aka foldlCE):
{-# LANGUAGE OverloadedStrings #-}
import Conduit
import Data.Word8
import qualified Data.ByteString as S
sinkInt :: Monad m => Consumer S.ByteString m Int
sinkInt =
foldlCE go 0
where
go total w
| _0 <= w && w <= _9 =
total * 10 + (fromIntegral $ w - _0)
| otherwise = error $ "Invalid byte: " ++ show w
main :: IO ()
main = do
x <- yieldMany ["1234", "5678"] $$ sinkInt
print x
There are plenty of caveats that go along with this: it will simply throw an exception if there are unexpected bytes, and it doesn't handle integer overflow at all (though fixing that is just a matter of replacing Int with Integer). It's important to note that, since the in-memory string representation of a valid 32- or 64-bit int is always going to be tiny, conduit is overkill for this problem, though I hope that this code gives some guidance on how to generally write conduit code.

Conduit - Combining multiple Sources/Producers into one

I'm reading from a file using sourceFile, but I also need to introduce randomness into the processing operation. The best approach I believe is to have a producer that is of the type
Producer m (StdGen, ByteString)
where StdGen is used to generate the random number.
I'm intending for the producer to perform the task of sourceFile, as well as producing a new seed to yield everytime it sends data downstream.
My problem is, there doesn't seem to be a source-combiner like zipSink for sinks. Reading through Conduit Overview, it seems to be suggesting that you can embed a Source inside a Conduit, but I'm failing to see how it is done in the example.
Can anyone provide an example of which you fuse two or more IO sources into one single Producer/Source?
EDIT :
An example:
{-# LANGUAGE NoImplicitPrelude #-}
{-# LANGUAGE RankNTypes #-}
{-# LANGUAGE OverloadedStrings #-}
import System.Random (StdGen(..), split, newStdGen, randomR)
import ClassyPrelude.Conduit as Prelude
import Control.Monad.Trans.Resource (runResourceT, ResourceT(..))
import qualified Data.ByteString as BS
-- generate a infinite source of random number seeds
sourceStdGen :: MonadIO m => Source m StdGen
sourceStdGen = do
g <- liftIO newStdGen
loop g
where loop gin = do
let g' = fst (split gin)
yield gin
loop g'
-- combine the sources into one
sourceInput :: (MonadResource m, MonadIO m) => FilePath -> Source m (StdGen, ByteString)
sourceInput fp = getZipSource $ (,)
<$> ZipSource sourceStdGen
<*> ZipSource (sourceFile fp)
-- a simple conduit, which generates a random number from provide StdGen
-- and append the byte value to the provided ByteString
simpleConduit :: Conduit (StdGen, ByteString) (ResourceT IO) ByteString
simpleConduit = mapC process
process :: (StdGen, ByteString) -> ByteString
process (g, bs) =
let rnd = fst $ randomR (40,50) g
in bs ++ pack [rnd]
main :: IO ()
main = do
runResourceT $ sourceInput "test.txt" $$ simpleConduit =$ sinkFile "output.txt"
So this example takes what's in the input file and write it to the output file, as well as appending a random ASCII value between 40 and 50 to the end of the file. (Don't ask me why)
You can use ZipSource for this. In your case, it might look something like:
sourceStdGens :: Source m StdGen
sourceBytes :: Source m ByteString
sourceBoth :: Source m (StdGen, ByteString)
sourceBoth = getZipSource $ (,)
<$> ZipSource sourceStdGens
<*> ZipSource sourceBytes
You can do it in the IO monad then lift the result to a Producer.
do (i, newSeed) <- next currentSeed
b <- generateByteStringFromRandomNumber i
return (b, newSeed)
That IO action can be lifted into the appropriate conduit with a simple lift:
-- assuming the above action is named x and takes the current seed as an argument
-- the corresponding producer/source is:
lift $ x currentSeed

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