How to find words consist of the once used letters of the keyword in Lua? [duplicate] - string

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How can I find the words consist of the letters inside the keyword in Lua?
I am trying to find words consist of letters inside the keyword. However, the letters shouldn't be used again once it's detected that it's inside the word.
i keep the words in the dictionary.
For example I have the keyword: "asdasdas"
My code says hi in these conditions
consistLetters("asdasdas","asdas")
consistLetters("asdasdas","sad")
consistLetters("asdasdas","sss")
However it also says hi when i consume all of the "s" in the keyword which is not what i want:
consistLetters("asdasdas","ssss")
How to stop this? Thank you.
EDIT: I solved my problem and shared it as an answer. I hope it'll be helpful.

Answer 1

Here is my code:
function consistLetters(keyword,word)
keywordletters={ }
wordletters= { }
local found=false
findLetters(keyword,keywordletters)
findLetters(word,wordletters)
for i=1, #wordletters,1 do
for j=1, #keywordletters,1 do
if(keywordletters[j]~="") then
if(wordletters[i]==keywordletters[j]) then
keywordletters[j]=""
found=true;
break
end
end
end
if found~=true then
return false
end
found=false;
end
end