i=0
while read line
do
echo "i is --- $i"
#echo $line "\n"
if (( $i > 0 ))
then
$Eda_package=$(echo $line | awk '{print $1}')
$well_bias=$(echo $line | awk '{print $2}')
$biasmap=$(echo $line | awk '{print $3}')
$unified=$(echo $line | awk '{print $4}')
echo "eda pack --$Eda_package wellbias is --$well_bias biasmap is --$biasmap unified- -- $unified"
fi
i=$((i+1))
done < config.list
In the above bash program I get an error:
./script.sh: line 9: =EDA_7p0: command not found
How do I fix this?
Lines of the form:
$xyzzy=plugh
will have xyzzy substituted before they're executed so that they look like:
=plugh
assuming they're not yet set. If they are set, you'll probably get different behaviour but still almost certainly not what you want.
You should change your lines from (for one example):
$Eda_package=$(echo $line | awk '{print $1}')
to:
Eda_package=$(echo $line | awk '{print $1}')
The $ is not part of the variable name, it's an indication that the following word is a variable that should be substituted.
Let var1=1 and var2=2 now if you simply write $var2=$var1 then it will give you error that 2=1 command not found
When you initialize any variable you have to do it without $ with variable name on left side
Related
I'm monitoring from an actively written to file:
My current solution is:
ws_trans=0
sc_trans=0
tail -F /var/log/file.log | \
while read LINE
echo $LINE | grep -q -e "enterpriseID:"
if [ $? = 0 ]
then
((ws_trans++))
fi
echo $LINE | grep -q -e "sc_ID:"
if [ $? = 0 ]
then
((sc_trans++))
fi
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
However when attempting to do this with AWK I don't get the output - the $ws_trans and $sc_trans remains 0
ws_trans=0
sc_trans=0
tail -F /var/log/file.log | \
while read LINE
echo $LINE | awk '/enterpriseID:/ {++ws_trans} END {print | ws_trans}'
echo $LINE | awk '/sc_ID:/ {++sc_trans} END {print | sc_trans}'
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
Attempting to do this to reduce load. I understand that AWK doesn't deal with bash variables, and it can get quite confusing, but the only reference I found is a non tail application of AWK.
How can I assign the AWK Variable to the bash ws_trans and sc_trans? Is there a better solution? (There are other search terms being monitored.)
You need to pass the variables using the option -v, for example:
$ var=0
$ printf %d\\n {1..10} | awk -v awk_var=${var} '{++awk_var} {print awk_var}'
To set the variable "back" you could use declare, for example:
$ declare $(printf %d\\n {1..10} | awk -v awk_var=${var} '{++awk_var} END {print "var=" awk_var}')
$ echo $var
$ 10
Your script could be rewritten like this:
ws_trans=0
sc_trans=0
tail -F /var/log/system.log |
while read LINE
do
declare $(echo $LINE | awk -v ws=${ws_trans} '/enterpriseID:/ {++ws} END {print "ws_trans="ws}')
declare $(echo $LINE | awk -v sc=${sc_trans} '/sc_ID:/ {++sc} END {print "sc_trans="sc}')
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
I am facing some issue when I am reading the 3rd word(a hex string) of each line in a text file and compare it with a hex number. Can some one please help me on it.
#!/bin/bash
A=$1
cat $A | while read a; do
a1=$(echo \""$a"\" | awk '{ print $3 }')
#echo $a > cut -d " " -f 3
echo $a1
(("$a1" == 0x10F7))
echo $?
done
But when I use below, the comparison happens correctly,
a1= 0xADCAFE
(( "$a1" == 0x10F7 ))
echo $?
Then why it is showing issue when I read like below,
a1=$(echo \""$a"\" | awk '{ print $3 }')
or> a1=$(echo $a | awk '{ print $3 }')
echo $a prints intended hex value, but comparison does not happen.
Regards,
Running Awk inside a while read loop is an antipattern. Just do the loop in Awk; it's good at that.
awk '$3 == 4343' "$1"
If you want to compare against a string whose value is "0x10F7" then it's
awk '$3 == "0x10F7"' "$1"
If you want to match either, case insensitively etc, a regex is a good way to do that.
awk '$3 ~ /^(0x10[Ff]7|4343)$/' "$1"
Notice how the $1 in double quotes is handled by the shell, and gets replaced by a (properly quoted!) copy of the script's first command-line argument before Awk runs, while the Awk script in single quotes has its own namespace, so $3 is an Awk variable which refers to the third field in the current input line.
Either way, avoid the useless use of cat and always always always quote variables which contain file names with double quotes.
That's literal double quotes. You seem to have tried both a dangerous bare $a and a doubly double-quoted "\"$a\"" where the simple "$a" would be what you actually want.
Thank you all for your responses, Now my script is working fine. I was trying to match two files, below script does the purpose
#!/bin/bash
A=$1
B=$2
dos2unix -f "$A"
dos2unix -f "$B"
rm search_match.txt search_data_match.txt search_nomatch.txt search_data_nomatch.txt
while read line;do
search_word=$(echo $line | awk '{ print $1 }')
grep "$search_word" $B >> temp_file.txt
while read var;do
file1_hex=$(echo $line | awk '{ print $2 }')
file2_hex=$(echo $var | awk '{ print $3 }')
(("$file1_hex" == "$file2_hex"))
zero=$(echo $?)
if [ "$zero" -eq 0 ] ; then
echo $line >> search_match.txt
echo $var >> search_data_match.txt
else
echo $line >> search_nomatch.txt
echo $var >> search_data_nomatch.txt
fi
done < "temp_file.txt"
rm temp_file.txt
done < "$A"
I can not use unix $variable in Fiexd search of awk command.
Please see below my commands.
a="NEW_TABLES NEW_INSERT"
b="NEW"
echo $a | awk -v myvar=$b -F'$0~myvar' '{print $2}'
is not returning any output
but if manually enter the $b value there , its working as below
echo $a | awk -v -F'NEW' '{print $2}'
outputs:
TABLES NEW_INSERT
This should make it:
$ a="NEW_TABLES NEW_INSERT"
$ echo $a | awk -F"NEW_" '{print $2}'
TABLES
$ b="NEW_"
$ echo $a | awk -F"$b" '{print $2}'
TABLES
Your quotings are all messed up and you can use your variable to split the line using split function:
a="NEW_TABLES NEW_INSERT"
b="NEW"
echo $a | awk -v myvar="$b" '{split($0,ary,myvar);print ary[2]}'
Outputs:
_TABLES
So I've been working on an assignment pertaining to awk. Everything is pretty much done, except when I throw commands into a bash script (run eleven of them all automagically) I don't get any output. Am I missing some sort of syntax that awk needs to work in a script? Thanks!
I'll just give you the first four to give you an idea:
#!/bin/sh
##VARIABLES
W=/usr/share/dict/words
C=cars_file
P=/etc/passwd
##PROBLEM EXAMPLE
#display problem number
#display command
#run command
#echo whitespace
##PROBLEMS
echo ">PROBLEM 01"
echo "awk '/zzan/ {print}' $W | head" #contains 'zzan'
awk '/zzan/ {print}' $W | head #pipe to head
echo
echo ">PROBLEM 02"
echo "awk '/^[aeiou].*[ou]rch$/ {print}' $W | head" #start w/lowercase vowel
echo awk '/^[aeiou].*[ou]rch$/ {print}' $W | head #end in orch/urch
echo #pipe to head
echo ">PROBLEM 03"
echo "awk '/chevy/ {print}' $C" #display all records
echo awk '/chevy/ {print}' $C #of all chevys
echo
echo ">PROBLEM 04"
echo "awk '$1 ~ /o/ {print}' $C" #display all records
echo awk '$1 ~ /o/ {print}' $C #contains 'o' in column 1
echo
`
The first awk entry should work fine (assuming your awk script does what you want. The other three have an erroneous leading echo and as such are just echoing the command instead of running it.
how to retrive every portion separately from following file name? DSA4020_frontcover_20346501_2011-05.doc
I want to retrieve informations as below;
name = DSA4020
type = frontcover
id = 20346501
date = 2011-05
is it possible to do with sed??
Yes, you can:
pax$ echo 'DSA4020_frontcover_20346501_2011-05.doc' | sed
-e 's/^/name=/'
-e 's/_/\ntype=/'
-e 's/_/\nid=/'
-e 's/_/\ndate=/'
-e 's/\..*//'
name=DSA4020
type=frontcover
id=20346501
date=2011-05
That's all on one line, I've just split it for readability.
You could also do it with awk if you wish:
pax$ echo 'DSA4020_frontcover_20346501_2011-05.doc'
| awk -F_ '{print "name="$1"\ntype="$2"\nid="$3"\ndate="substr($4,1,7)}'
name=DSA4020
type=frontcover
id=20346501
date=2011-05
awk may be a better choice
# f=DSA4020_frontcover_20346501_2011-05.doc
# name=$(echo $f | awk -F_ '{print $1}')
# echo $name
DSA4020
# type=$(echo $f | awk -F_ '{print $2}')
# echo $type
frontcover
In pure bash
FILE="DSA4020_frontcover_20346501_2011-05.doc"
eval $(echo $FILE |(IFS="_";read a b c d; echo "name=$a;type=$b;id=$c;date=${d%.doc}"))
echo Name:$name Type:$type ID:$id DATE:$date