i am reading data from an excel sheet which has decimals.
i want to obtain the result without decimals.
I'm using cell.getNumericCellValue () which gives decimal - is there a function which removes decimals.
how about just casting the value to int?
(int)cell.getNumericCellValue()
Related
I have the following 4 rows and I wish to find the decimal length (aka scale) of that decimal value. Do note that I'm importing all of the decimal data in Excel whose cell is formatted in a "Text" format (hence the trailing zeros even after the decimal values). And I do not want to convert it into decimal. I just need to find the scale of that decimal number.
Decimal Number
Scale (Formula?)
106.520000
2
0.080100
4
15.000010
5
265.000000
0
Been struggling for a very long time now. I'd appreciate any lead on this.
This is what I have tried,
• Formula used in cell B2
=LEN(MID(NUMBERVALUE(A2),FIND(".",A2)+1,255))
You could try:
Formula in B2:
=MAX(LEN(-A2)-LEN(INT(A2))-2,0)
Note: I use a decimal comma but it shouldnt matter for you.
I am attempting to do some calculations in Excel on numbers that include long decimals.
However, Excel doesn't seem to let me populate the cells with the numbers I would like to use.
Example:
If I enter 600000.00000000030000000000 into a standard cell on a new
spreadsheet, it gets converted to 600000. This makes sense as the
cell format is set to General.
If I set the cell format to Number and set the decimals
places to 20, I would expect to be able to enter the number properly.
Instead, the 600000.00000000030000000000 gets converted to 600000.00000000000000000000.
Does anyone know why this would happen?
Excel only stores 15 significant figures for numbers. Any figures beyond that automatically get rounded, regardless of number format.
Setting the cell to Text format first will store the number as a string with as many digits as you want, but Excel can't perform any calculations on it.
However, VBA can do calculations with Decimal type variables which can store up to 29 significant figures.
If you first store the values as text in Excel (setting the cell number format to Text before entering the values), you can create a User Defined Function in VBA to read the string values, convert them to Decimal values, perform your calculations and then return a string with the full precision calculated.
For example:
Function PrecisionSum(ra As Range) As String
'Declare variables holding high precision Decimal values as Variants
Dim decSum As Variant
'This loop will sum values from all cells in input range
For Each raCell In ra
'Read values from input cells, converting the strings to Decimals using CDec function
decSum = decSum + CDec(raCell.Value)
Next raCell
'Return calculated result as a String
PrecisionSum = Format(decSum, "0.00000000000000000000")
End Function
You'll need to write functions to do the operations that you desire.
Note that you'll still be limited by the accuracy of any functions you use in VBA. For example, the SQR function to return the square root of a number only returns a number with Double precision regardless of the precision of the input.
This has to do with the number precision Excel can handle. I noticed that I can show the .00000000030000000000 portion just fine if you remove the integer part. Maybe you could have a separate column for your integer, do your calculations on the decimal part and afterwards add the integer part again.
You can check the wiki regarding this issue - by adding the 600,000, you are essentially adding 6e5+3e-8, which Excel has to work with cummulative bit depth.
Numeric precision in Microsoft Excel
You could try to use exponential (Scientific) notation?
I need to count the numbers of decimals places of a number.
The A1 cell value is:
123456.78.
The formula in B1 is:
=LEN(MOD(A1,1))
The results of MOD(A1,1) is:
0.78
I expected the LEN to be 4 (LEN(0.78)=4).
The Excel formula calculates 17 because the forumula returns:
0.779999999998836
Should I try a different approach? For example looking for the separator char?
=LEN(A1)-FIND(".",A1)
Try this:
=LEN(RIGHT(A1;LEN(A1)-FIND(",";A1)))
A better formula managing a non decimal entry and different decimal separators:
=IF(ISNUMBER(FIND(".";A1));LEN(A1)-FIND(".";A1);IF(ISNUMBER(FIND(",";A1));LEN(A1)-FIND(",";A1)))
I see that the Len function is causing the math function to return the incorrect value for some reason (Len(Mod(123456.78, 1)) is returning 17 not 4, whereas Len(Mod(6.78,1) correctly returns 4).
You can add the TEXT function to your formula to change it to text, with a format of "General" to preserve the decimal precision, before calculating the length: LEN(TEXT(MOD(A1,1), "General")).
For those wanting to use this to calculate the number of decimal places without the leading "0.", simply subtract 2 from the result.
I have an excel formula that is producing a lot of decimal places and I cannot reduce them using the format cell -> numbers -> decimal places options. Here is the formula.
Cell named V01_MIN
V01_MIN =MIN(6:6)
Has a value of 2
Cell named V01_MAX
V01_MAX =MAX(6:6)
Has a value of 1800
Cell named V01_A
V01_A =1-V01_MIN*V01_B
Has a value of 0.889877642
Cell named V01_B
V01_B =99/(V01_MAX-V01_MIN)
Has a value of 0.055061179
X6=723
X7=V01_A+V01_B*X6 (value of 40.69911012)
X8=1
X9=X7*X8 (value of 40.69911012)
X10=1
X11=X9*X10 (value of 40.69911012)
X13==CONCATENATE(X12,", ",X11)
The final results of X13 are:
V01, 1162, 40.6991101223582
I want them to be:
V01, 1162, 40.7
I'm trying to figure out how to make this happen. I've already tried changing the cell formatting on all of these cells (including the final cell) to one decimal palce and that didn't work.
Cell formatting and the actual number in the cell are two different things.
The cell formatting merely changes how the number is shown to you in the cell.
The actual number in the cell will still keep all precision of the number.
If you wish to have the last number rounded, consider this:
X13=CONCATENATE(X12,", ",ROUND(X11,1))
This will round the result in X11 to 1 decimal place before concatenating.
By concatenating you are changing your data to text instead of a number and the number formats won't effect it. Generally you have two options
Either round within you concatenate function
X13==CONCATENATE(X12,", ",roound(X11,1))
or change it back to a number (easiest way is multiply by 1): Note this won't work in your case since you are joining text strings and variables but is useful to be aware of.
X13==CONCATENATE(X12,", ",X11)*1
and then you can format based on decimal places.
I have a excel sheet with cell value 0.010, 0.020 etc., I want to get the values 3 digits after the decimal ie., "010" "020" etc., If I use the Right function Right(cell,3) it returns me ".01" ".02". The reason is the Right function ignores the "0" at the end of decimal point. Is there any other function that accomplish this.
You probably first need to convert the numeric value to a string:
=RIGHT(TEXT(CELL,"0.000"),3)