Convert string to class object in Python - python-3.x

Question

I have a list of strings. Each string of the list has same format. I would like to convert each string into a class object (if that is the best option), so I can do some analysis of the list of class object.
As an example,
I have the following list
ls_list = ['-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 bar1',
'-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 bar2',
'-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 foo1',
'-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 foo2']
I would like to convert each of the above string into a class that has Nine members (perm, etc).

Answer 1

You don't want to do that. Use os.listdir() and os.stat() to get the information you want.

Answer 2

You do it something like this:
import os
data = {}
for file in os.listdir('.'):
data[file] = os.stat(file)
This gives you the information for all the files in the current directory, as objects, as you requested. These can then be inspected, and you can use other functions to figure out the username of the userid you get, etc.

Answer 3

Here's one way of doing what you ask, but as others have noted, don't use this for parsing the output of ls. Also, it assumes that there are only 8 areas of whitespace in your input string separating your data. If any of the data substrings also contain whitespace, this code will fail:
class FileAttribs(object):
ORDERED_ATTRIB_NAMES = ["permissions", "links", "owner",
"groups", "size", "month", "day", "time", "name"]
def __init__(self, lsString):
for (attrib, s) in zip(self.ORDERED_ATTRIB_NAMES, lsString.split()):
setattr(self, attrib, s)
if __name__ == '__main__':
ls_list = ['-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 bar1',
'-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 bar2',
'-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 foo1',
'-rw-r--r-- 1 ahmed None 0 Apr 21 17:10 foo2']
files = []
for s in ls_list:
files.append(FileAttribs(s))
#do stuff with files, e.g.
for f in files:
print f.permissions, f.name