Save HTML Source Code to File - python-3.x

Question

How can I copy the source code of a website into a text file in Python 3?
EDIT:
To clarify my issue, here's what I have:
import urllib.request
def extractHTML(url):
f = open('temphtml.txt', 'w')
page = urllib.request.urlopen(url)
pagetext = page.read()
f.write(pagetext)
f.close()
extractHTML('http:www.google.com')
I get the following error for the f.write() function:
builtins.TypeError: must be str, not bytes

Answer 1

import urllib.request
site = urllib.request.urlopen('http://somesite.com')
data = site.read()
file = open("file.txt","wb") #open file in binary mode
file.writelines(data)
file.close()
Untested but should work.
EDIT: Updated for python3

Answer 2

Try this.
import urllib.request
def extractHTML(url):
urllib.request.urlretrieve(url, 'temphtml.txt')
It is easier, but if you still want to do it that way. This is the solution:
import urllib.request
def extractHTML(url):
f = open('temphtml.txt', 'w')
page = urllib.request.urlopen(url)
pagetext = str(page.read())
f.write(pagetext)
f.close()
extractHTML('https://www.google.com')
Your script gave an error saying it must be a string. Just convert bytes to a string with str().
Next I got an error saying no host was given. Google is a secured site so https: not http: and most importantly you forgot to include // at the end of https:.

Answer 3

probably you wanted to create something like that:
import urllib.request
class ExtractHtml():
def Page(self):
print("enter the web page name starting with 'http://': ")
url=input()
site=urllib.request.urlopen(url)
data=site.read()
file =open("D://python_projects/output.txt", "wb")
file.write(data)
file.close()
w=ExtractHtml()
w.Page()