Consider the following table:
I have a series of blank cells with missing data. From this missing data I only have the year in the next column. I need to fill any blank cells with a standard day/month of 30/06. The year of each cell however needs to be the year in the next column. The attached file shows how my data is arranged. So at cell B 2091, the date shall be 30/06/2011 while for cell B 2098 the date shall be 30/06/2018 and at cell B 2100 the date shall be 30/06/2008.
Filter on the blank cells in column B. Then, in the topmost cell (which I'll assume to be B1 but will likely be different), enter a formula similar to the following and fill down
=DATE(C1,6,30)
where the row number in C1 is the same as your first row of data.
You can achieve this with a helper column (any blank column in the same worksheet where you need the dates). In that column enter this formula in the first cell (here in row 2) and copy down.
=IF(ISBLANK(B2),DATE(C2,6,30),B2)
Then copy the Values from the helper column to the date column and delete the helper.
Below is a small macro that is doing the same job. It needs no helper column and over-writes your existing blanks. Before you run it make sure to check the values of the 2 constants at the top and the name of the worksheet (especially the latter!) against your requirements.
Sub WriteStandardDate()
'293
Const FirstDataRow As Long = 2 'change to suit
Const DateClm As Long = 2 'change to suit
' year column must be adjacent to DateClm
Dim R As Long
Dim Arr As Variant
Dim Rng As Range
With Worksheets("Sheet1") ' change name as required
Set Rng = .Range(.Cells(FirstDataRow, DateClm), _
.Cells(.Rows.Count, DateClm).End(xlUp)) _
.Resize(, 2)
Arr = Rng.Value
For R = 1 To UBound(Arr)
If IsEmpty(Arr(R, 1)) Then
Arr(R, 1) = DateSerial(Arr(R, 2), 6, 30)
End If
Next R
Rng.Value = Arr
End With
End Sub
Update: I used the formula suggested by Variatus: =IF(ISBLANK(B2),DATE(C2,6,30),B2) and worked fine through a helper column. There was no need to copy / paste the new dates into the Dates column. I just used the helper column as the new Dates column since full dates from the original column were not changed and got inserted in the helper column thanks to the IFBLANK portion of the formula. Thanks.
I need to go through a table (X by Y) where every column (X) should have the same value (string) and would like the cell to get highlighted if is not the same value. I'm stuck in building the comparison method, because I would like it to be dynamic. I would like to first determine what is the value that is present the most in the column and determine that is what everything else needs to be compared against and highlight the cell that is not equal to this value.
Example (6x5 table) -
A 3 4 C M R
A 3 4 O M R
8 3 T O M F
8 3 4 O M G
A 3 T O Y K
In the first column, A is the most prevalent value therefore the (8s) are highlighted, second column nothing is highlighted, third both (T) are highlighted, fourth column (C), fifth column (Y) and sixth column (F),(G) and (K) are highlighted.
Thank you in advance.
I can suggest a workaround. Not sure if this is the best way though.
Step 1. Create a count if table which basically gives you the count of a value in the column. Ex: for cell F4 use formula =COUNTIF($B$4:$B$8,B4)
Step 2. Create a row with max values of each column. Ex: Cell F11 =MAX(F4:F8)
Step 3. For each cell, give a conditional formatting condition that if the value in the count table does not match the max value, color it. Ex: for cell B4, go to conditional formatting -> new rule -> use a formula and write this formula =F4<>F$11. Then copy paste the format to all other cells.
Note: this will not work when multiple values in a column have the same max count.
Here is a VBA solution, I've commented the code so you can understand
Sub HighlightNonFrequentInColumn()
Dim rng As Range
Dim col As Range
Dim cell As Range
Dim myVal As String
Dim colRng As String
Set rng = Selection '<<change range as required
For Each col In rng.Columns
'determine the most frequent value
colRng = col.Address
On Error Resume Next
myVal = Application.Evaluate("INDEX(" & colRng & ",MODE(IF(" & colRng & "<>"""",MATCH(" & colRng & "," & colRng & ",0))))")
If Application.countblanks(col) > Application.CountIf(col, myVal) Then myVal = "" '<<if blanks are most frequent
'highlight all cells not equals to most frequent value
For Each cell In col.Cells
If Not cell = myVal Then cell.Interior.Color = vbYellow '<<change colour as desired
Next
Next
End Sub
I am looking for a list of column A where there isn't a specific value in column B as well as any other value in Column B.
Example:
COLUMN A COLUMN B
LEFT ALPHA
LEFT BETA
LEFT CHARLIE
RIGHT BETA
RIGHT CHARLIE
UP ALPHA
UP CHARLIE
DOWN ALPHA
I want to know all Column A where there is an Alpha and at least one other value for Column A.
Left has an Alpha and another value that is not Alpha so it would be included.
Right doesn't have an Alpha so excluded.
Up has an Alpha and another value that is not Alpha so it would be included.
Down has Alpha but no other values and is excluded.
This can populate a list on another worksheet that would be best. I think I have to go the VBA route but I am unsure where to start.
This uses COUNTIFS. Adjust sheet names to your set up if necessary. I should add that you will need a header row for your data (for AF) so insert a row if necessary.
Sub x()
Dim r As Range, wf As WorksheetFunction, r1 As Range
Set wf = WorksheetFunction
Set r1 = Sheet1.Range("A1").CurrentRegion
r1.Columns(1).AdvancedFilter xlFilterCopy, , Sheet2.Range("A1"), unique:=True
With Sheet2
For Each r In .Range("A2", .Range("A" & Rows.Count).End(xlUp))
If wf.CountIfs(r1.Columns(1), r, r1.Columns(2), "ALPHA") > 0 And _
wf.CountIfs(r1.Columns(1), r, r1.Columns(2), "<>ALPHA") > 0 Then
r.Offset(, 1) = "Yes"
Else
r.Offset(, 1) = "No"
End If
Next r
End With
End Sub
Data and result:
Formula in result A1:
=IFERROR(INDEX(Data!A$1:A$8,SMALL(IF(
MATCH(Data!A$1:A$8,Data!A$1:A$8,0)=ROW(Data!A$1:A$8),ROW(Data!A$1:A$8)),ROW())),"")
This is the same as the remove duplicated offered by excel, a formula version. Please press Ctrl + Shift + Enter to complete the formula.
Formula in result B1:
=AND(SUMPRODUCT(--(Data!A$1:A$8&Data!B$1:B$8=A1&"ALPHA"))>0,
COUNTIF(Data!A$1:A$8,A1)>1)
Just some simple criteria judgments. We build a list of combination of column A and column B. That is LEFTALPHA, LEFTBETA, LEFTCHARLIE, RIGHTBETA.... so that we can search for LEFTALPHA is exist or not. And the second criteria is find out the target is single or multiple.
I am trying to set conditional formatting in 18 cells in third column ("C"). I have merged each 6 cells in first column ("A"), and unmerged (normal) cells in second column ("B"). I am trying to check for each next cell in row of column "C" if there is a "yes" in first row of column "A" or whether there is a "no" in "A" column and "pass" in "B" column. The trick is, I want to check only first row of "A" column, seventh, thirteenth and nineteenth (so with the step = 6) and check every row in "B" column. I try something like this:
Sub try()
Dim i As Integer
Dim j As Integer
i = 1
For j = 1 To 12
With Range("C1:C18")
.FormatConditions.Delete
.FormatConditions.Add Type:=xlExpression, Formula1:="=OR(Cells(i, 1) = ""Yes""; AND(Cells(i, 1) = ""No""; Cells(j, 2) = ""Pass""))"
End With
If j Mod 6 = 0 Then
i = i + 6
Next j
End Sub
But it does not work like that, I saw examples with specific Cells like "A1" or "A3" but I want a number to increase with every loop (so I tried it with Cells(row,column)).
You can do it in one statement on the whole range by using relative addresses, so what applies to C1 relatively to A1 and B1 will follow automatically in the subsequent rows of the range.
The only trick is to retrieve the value in column A, since this value is only available in cells A1, A7, etc. This is achieved by the expression OFFSET(A1,-MOD(ROW(C1)-1,6),0).
Sub doIt()
With Sheet1.Range("C1:C30").FormatConditions
.Delete
.Add(xlExpression, , _
"=OR(OFFSET(A1,-MOD(ROW(C1)-1,6),0)=""yes"",AND(OFFSET(A1,-MOD(ROW(A1)-1,6),0)=""no"",B1=""pass""))") _
.Interior.ColorIndex = 6
End With
End Sub
You can also do it from the GUI using the same formula; select cell C1 then select the whole range C1:C30, and click
Conditional Fomatting -> New rule -> Use a formula... and enter the same formula.
BTW, the expression can be further simplified if you dont care to check for "no", meaning if column A is assured to be either "yes" or "no".
I've got a formula that's been puzzling me for a while - I feel I'm close but the solution is evading me so I'm turning to you wizards. This questions is similar to Excel VLOOKUP and SEARCH combination.
Problem:
I want to look up a value which is a pair of codes separated by a dash, ex.
01-05
A1-B2
AB-90
, within columns A and B and return a result from C.
The issue is that I'm searching in two columns, which may include multiple codes separated by commas:
Col A Col B Col C
01 05, B2 Result1
A1 B2 Result2
AB, AC 90, 91, 92 Result3
I was thinking that a =if(isnumber(search( function would be the key but I can't figure how to have it check the entire column and once found, check the column next to it for the 2nd part of the code.
Ideally, the formula would perform as such, where in the above example, if I were to run this formula on the criteria 01-05 it would return Result1.
Appreciated!
the "formula" approach is, to my knowledge, quite verbose and cumbersome as follows:
=IF(
ISNA(
IFERROR(MATCH(LEFT(D1,SEARCH("-",D1)-1),Codes!$A$1:$A$100,0),
IFERROR(MATCH("*"&LEFT(D1,SEARCH("-",D1)-1)&",*",Codes!$A$1:$A$100,0),
MATCH("*,"&LEFT(D1,SEARCH("-",D1)-1)&"*",Codes!$A$1:$A$100,0)))
*
IFERROR(MATCH(RIGHT(D1,LEN(D1)-SEARCH("-",D1)),Codes!$B$1:$B$100,0),
IFERROR(MATCH("*"&RIGHT(D1,LEN(D1)-SEARCH("-",D1))&",*",Codes!$B$1:$B$100,0),
MATCH("*,"&RIGHT(D1,LEN(D1)-SEARCH("-",D1))&"*",Codes!$B$1:$B$100,0)))
),
"Not Found",
IF(IFERROR(MATCH(LEFT(D1,SEARCH("-",D1)-1),Codes!$A$1:$A$100,0),
IFERROR(MATCH("*"&LEFT(D1,SEARCH("-",D1)-1)&",*",Codes!$A$1:$A$100,0),
MATCH("*,"&LEFT(D1,SEARCH("-",D1)-1)&"*",Codes!$A$1:$A$100,0)))
<>
IFERROR(MATCH(RIGHT(D1,LEN(D1)-SEARCH("-",D1)),Codes!$B$1:$B$100,0),
IFERROR(MATCH("*"&RIGHT(D1,LEN(D1)-SEARCH("-",D1))&",*",Codes!$B$1:$B$100,0),
MATCH("*,"&RIGHT(D1,LEN(D1)-SEARCH("-",D1))&"*",Codes!$B$1:$B$100,0))),
"Different rows",
INDEX(Codes!C:C,IFERROR(MATCH(RIGHT(D1,LEN(D1)-SEARCH("-",D1)),Codes!$B$1:$B$100,0),
IFERROR(MATCH("*"&RIGHT(D1,LEN(D1)-SEARCH("-",D1))&",*",Codes!$B$1:$B$100,0),
MATCH("*,"&RIGHT(D1,LEN(D1)-SEARCH("-",D1))&"*",Codes!$B$1:$B$100,0))))
)
)
where I used a (hopefully) more readable format and assumed:
"Codes" as the sheet name whose columns "A" ("first" code), "B" ("second" code) and "C" ("Results") are placed
codes pairs are to be placed in column "D" of any sheet
formula is to be placed in column "E" adjacent to above mentioned column "D" cells
you may want to consider a "VBA" approach like the following
Sub main()
Dim codesSht As Worksheet
Dim cell As Range, found As Range, codesRng As Range
Dim index1 As Long
Set codesSht = ThisWorkbook.Worksheets("Codes") '<== change "codes" sheet reference as per your needs
Set codesRng = codesSht.Range("A:B").SpecialCells(xlCellTypeConstants, xlTextValues)
With ThisWorkbook.Worksheets("Results") '<== change "Results" sheet reference as per your needs
For Each cell In .Range("D1:D" & .Cells(.Rows.count, "D").End(xlUp).Row).SpecialCells(xlCellTypeConstants, xlTextValues)
Set found = codesRng.Resize(, 1).Find(What:=Split(cell.Value, "-")(0), LookIn:=xlValues, LookAt:=xlPart)
If Not found Is Nothing Then
index1 = found.Row
Set found = codesRng.Offset(, 1).Resize(, 1).Find(What:=Split(cell.Value, "-")(1), LookIn:=xlValues, LookAt:=xlPart)
If Not found Is Nothing Then If found.Row = index1 Then cell.Offset(, 1).Value = codesRng(index1, 3)
End If
Next cell
End With
End Sub
If you put the code you are looking for in Column D, then your formula in Column E, the following formula will accomplish what you are looking for ...
=IF(OR(ISERROR(FIND(LEFT(D2,2),A2)),ISERROR(FIND(RIGHT(D2,2),B2)),LEN(D2)=0),"",C2)
And then fill it down.
The formula searches for the left two characters from the code in Column A. If it's not found, an error is thrown. It also looks for the right two characters from the code in Column B. If it's not found, an error is thrown. If the code you are looking for is blank, no error is thrown, so we need to check that case.
So if there is an error searching for the left part, or an error searching for the right part, or there is no code to look for, return a blank. Otherwise, return the result.
Below are some examples ...
Updated based on comments
On Sheet1, the data looks like this ...
... On Sheet2, we have results like this ...
Where Cell B2 contains this formula (filled down)
{=CONCAT(IF(ISERROR(FIND(LEFT(A2,2),Sheet1!$A$1:$A$3)),"",IF(ISERROR(FIND(RIGHT(A2,2),Sheet1!$B$1:$B$3)),"",IF(LEN(A2)<1,"",Sheet1!$C$1:$C$3))))}
Updated due to version-itis
When all else fails, go to VBA. Attached is an example Function. It gets the same results as shown above. It is invoked with formula in Column B, filled down ...
=FindResult(A2,Sheet1!$A$1:$A$3,Sheet1!$B$1:$B$3,Sheet1!$C$1:$C$3)
Code ...
Function FindResult(inString As String, LeftRange As Range, RightRange As Range, ReturnRange As Range) As String
Dim strArr() As String
Dim myCellLeft As Range, myCellRight
'initial
FindResult = ""
If LeftRange Is Nothing Then GoTo Done:
If RightRange Is Nothing Then GoTo Done:
If ReturnRange Is Nothing Then GoTo Done:
' get the two halfs
strArr = Split(inString, "-")
If UBound(strArr) < 1 Then GoTo Done:
' Search the left range for the left half, the right range for the right half
For Each myCellLeft In LeftRange
If InStr(1, myCellLeft.Value, strArr(0)) > 0 Then
For Each myCellRight In RightRange.Rows(myCellLeft.Row)
If InStr(1, myCellRight.Value, strArr(1)) > 0 Then
FindResult = ReturnRange.Rows(myCellLeft.Row)
Exit For
End If
Next myCellRight
If FindResult <> "" Then Exit For
End If
Next myCellLeft
' clean up
Done:
Erase strArr
Set myCellLeft = Nothing
Set myCellRight = Nothing
End Function