Cannot access UIBezierPath in a NSMutable array - nsmutablearray

Question

so I have a [NSMutableArray *paths] that contains UIBezierPaths that correspond to each separate path drawn on the screen. I also have another NSMutable array colors that contains the corresponding color for the path. The problem that I am having is that although the two arrays are mutating and I can see the count of both going up, the following drawRect method only seems to draw the last path in the array.
I have scoured through a lot of questions and based on what I have read so far, this very problem seems to get us newbies and mostly because of type mismatch. I even tried to Typecast the return and it was futile.
Here is my code from the drawRect
int cnt = paths.count;
if (cnt != 0)
{
for(int i = 0; i < cnt; i++)
{
NSLog(#"Drawing path:%i", i);
UIColor *color;
color = [colors objectAtIndex:i];
[color setStroke];
UIBezierPath *path = [paths objectAtIndex:i];
path.lineWidth = 2;
[path stroke];
}
}
every time I call [self setNeedsDisplay] it wipes out my entire screen.
Am I correct in assuming that I am not handling my
UIBezierPath *path = [paths objectAtIndex:i];
well?
Thank you very much and in advance.
UPDATE:
I was rummaging through some more codes and now it almost looks like there is another possibility that ARC is releasing the contents of my NSMutable array. I tried the do the following and got a compiler error.
[paths retain];

Answer 1

Besure you add your path to your path array afer each draw
- (void)drawRect:(CGRect)rect {
[brushPattern setStroke];
UIBezierPath *drawPath = [UIBezierPath bezierPath];
drawPath.lineCapStyle = kCGLineCapRound;
drawPath.miterLimit = 0;
drawPath.lineWidth = thisLineWidth;
for (UIBezierPath *path in pathArray)
[drawPath appendPath:path];
UIBezierPath *path = [self pathForCurrentLine];
if (path)
[drawPath appendPath:path];
[drawPath stroke];
}
- (UIBezierPath*)pathForCurrentLine {
UIBezierPath *path = [UIBezierPath bezierPath];
[path moveToPoint:startPoint];
[path addLineToPoint:endPoint];
return path;
}