Convert column pattern - linux

Question

I have this kind of file:
1 0 1
2 0 3
2 1 2
3 0 3
4 0 1
4 1 1
4 2 1
4 3 1
5 0 1
8 0 1
10 0 1
11 0 1
The RS separator is an empty line by default.
If there was a double blank line, we have to substitute on of them by a pattern $1 0 0, where $1 means the increased "number" before the $1 0 * record.
If the separator is empty line + 1 empty line we have to increase the $1 by 1.
If the separator is empty line + 2 empty line we have to increase the $1 by 2.
...
and I need to get this output:
1 0 1
2 0 3
2 1 2
3 0 3
4 0 1
4 1 1
4 2 1
4 3 1
5 0 1
6 0 0
7 0 0
8 0 1
9 0 0
10 0 1
11 0 1
Thanks in advance!

Answer 1

awk 'NF{f=0;n=$1;print;next}f{print ++n " 0 0"}{print;f=1}' ./infile
Output
$ awk 'NF{f=0;n=$1;print;next}f{print ++n " 0 0"}{print;f=1}' ./infile
1 0 1
2 0 3
2 1 2
3 0 3
4 0 1
4 1 1
4 2 1
4 3 1
5 0 1
6 0 0
7 0 0
8 0 1
9 0 0
10 0 1
11 0 1
Explanation
NF{f=0;n=$1;print;next}: if the current line has data, unset flag f, save the number in the first field to n, print the line and skip the rest of the script
{print;f=1}: We only reach this action if the current line is blank. If so, print the line and set the flag f
f{print ++n " 0 0"}: We only execute this action if the flag f is set which only happens if the previous line was blank. If we enter this action, print the missing fields with an incremented n

Answer 2

You can try something like this. The benefit of this way is that your input file need not have an empty line for the missing numbers.
awk -v RS="" -v ORS="\n\n" -v OFS="\n" '
BEGIN{getline; col=$1;line=$0;print line}
$1==col{print $0;next }
($1==col+1){print $0;col=$1;next}
{x=$1;y=$0; col++; while (col < x) {print col" 0 0";col++};print y;next}' file
Input File:
[jaypal:~/Temp] cat file
1 0 1
2 0 3
2 1 2
3 0 3
4 0 1
4 1 1
4 2 1
4 3 1
5 0 1
8 0 1
10 0 1
11 0 1
Script Output:
[jaypal:~/Temp] awk -v RS="" -v ORS="\n\n" -v OFS="\n" '
BEGIN{getline; col=$1;line=$0;print line}
$1==col{print $0;next }
($1==col+1){print $0;col=$1;next}
{x=$1;y=$0; col++; while (col < x) {print col" 0 0";col++};print y;next}' file
1 0 1
2 0 3
2 1 2
3 0 3
4 0 1
4 1 1
4 2 1
4 3 1
5 0 1
6 0 0
7 0 0
8 0 1
9 0 0
10 0 1
11 0 1