I am using menu using dijit.menu and Its work with right click and left click.
How I open the menu on mouse over and close on onmouseout?
dijitActionMenu = new dijit.Menu({
targetNodeIds:[actionMenuId],
leftClickToOpen:"true"
});
Have you tried something like
// Create a new Tooltip
var tip = new dijit.Tooltip({
// Label - the HTML or text to be placed within the Tooltip
label: '<div class="myTipType">This is the content of my Tooltip!</div>',
// Delay before showing the Tooltip (in milliseconds)
showDelay: 250,
// The nodes to attach the Tooltip to
// Can be an array of strings or domNodes
connectId: ["myElement1","myElement2"]
});
More details are here dialogs_tooltips.Even dijit.Menu have onMouseOver even.
onMouseOver Event
I am able to get the dijit/Menu onmouseover.
Create an element which will invoke onmouseover event.
Element
show() will call custom widget which will create menu for you.
E.g.,
show = function() {
var roll = new rollover()
}
And rollover.js will be the custom widget.
From the constructor of it, you can invoke the function and create the menu.
pMenu = new Menu({ class: "rollovermenu", id: "rolloverid" });
Related
I am fighting with CKEditor in order that after CKEditor is loaded with a content and without selecting any style from toolbar, the changes (new text) made from an user, are automatically set in bold (no toolbar needed for the user).
I tried executing a command on the "click" event setting the bold style but it does not work very well
myEditor.on("instanceReady", function() {
var editable = myEditor.editable();
editable.attachListener( editable, 'click', function() {
myEditor.commands.bold.exec();
});
});
so I changed inserting element with bold style on click event
myEditor.on("instanceReady", function() {
var editable = myEditor.editable();
editable.attachListener( editable, 'click', function() {
var parent = myEditor.getSelection().getStartElement()
//simplified code without check if span already exist
myEditor.insertHtml('<span class="boldStyle">');
myEditor.insertHtml('</span>');
});
});
This works a bit better but I wonder if this approach is a good idea or how I could do better
Thanks
I developed an app using Xamarin forms that has side menu see this url.
But I couldn't use this in my current project, so I made my custom component for side menu.
How to implementing feature that hide menu when I tap range out of side menu?
It is hard to give you any help without seeing your code, but generally I tackle this issue by adding a ContentView that covers the screen when ever your menu opens. The menu would be displayed on top of the ContentView. Then you add a TapGestureRecognizer to the ContentView which closes the menu when clicked.
You could add some color to the ContentView but make it opaque so it is see-through, something like this color: #74787878
ContentView backgroundView = new ContentView {
BackgroundColor = Color.FromHex("#74787878"),
HorizontalOptions = LayoutOptions.FillAndExpand,
VerticalOptions = LayoutOptions.FillAndExpand,
Content = //Your menu
}
backgroundView.GestureRecognizers.Add(new TapGestureRecognizer {
Command = new Command(() => {
//Remove the background and hide the menu
})
});
Let's take a TODO app as example, there is a Main window - A, that will list all of the TODO items and a button 'Add Item'. So when click on the 'Add Item' , it will open up a second window - B, where there is a form for adding item. After the form is submitted, the newly added item will be append to the list in WIndow A.
So the problem here is, how can I update the Item list in WIndow A when when WIndow B form is submitted? I am using react js for the renderer. So, how can react component listen to the changes?
Ok, got the answer.
Turn out we can use webContents to send the message to the desired window. And that message can be listened in the window.
#main.js
mainWindow = new BrowserWindow({width: 800, height: 600});
mainWindow.webContents.send('addingitem','...blahblah balh ');
and in render
ipc.on("addingitem", (event, arg)=>{
//doing the update DOM here.
}
I'm using Dojo version 1.6.1. I'm building a menu that has a Dialog dijit as a popup from a PopupMenuItem. This works, however, if the menu is docked on the right-hand side of the application I need the popup to display to the left of the menu. I can't seem to get this to work. If I use another type of widget (like a ColorPalette), this works fine. With popup submenus and a popup ColorPalette, everything opens to the left if the menu is on the right-hand side of the screen, and everything opens to the right if the menu is on the left-hand side of the screen. Dojo just handles this automatically. But with any Dialog widget, even an empty one, it always pops out to the right of the PopupMenuItem regardless of where the menu is on the screen. I thought that perhaps specifying height and width of the div that is the dijit.Dialog would resolve this, but it did not.
Here's a simplified version of the code:
<div data-dojo-type="dijit.Menu" id="toolPalette" style="position:absolute; right:0; top:0; z-index: 999;">
</div>
<script>
// Grab the div for the menu, declared in the HTML above.
var toolPalette = dijit.byId("toolPalette");
// This tool button has a popup
var menuItem1 = new dijit.PopupMenuItem({
id: "menuItem1",
iconClass: "shelterIcon",
popup: new dijit.Dialog()
});
toolPalette.addChild(menuItem1);
// This tool button does not have a popup
var menuItem2 = new dijit.MenuItem({
id: "menuItem2",
iconClass: "shelterIcon"
});
toolPalette.addChild(menuItem2);
toolPalette.startup();
</script>
Any help is greatly appreciated! I've tried everything I can think of.
Way to find your current Cursor location
document.onmouseup = getXY;
var mouseX, mouseY;
function getXY(e) {
mouseX= (e || event).clientX;
mouseY= (e || event).clientY;
if (document.documentElement.scrollTop > 0) {
mouseY= mouseY+ document.documentElement.scrollTop;
}
}
Your Code here .
var myDialog = new dijit.Dialog();
var menuItem1 = new dijit.PopupMenuItem({
id: "menuItem1",
iconClass: "shelterIcon",
popup: myDialog
});
Now apply the X and Y to your Dialog.
dijit.popup.open({
x: mouseX,
y : mouseY,
popup: myDialog
});
Using YUI, I want to create a menu button, passing in the menu widget instance.
Result is what looks like a menu button, but the menu doesn't show.
test case: http://sandbox.kluger.com/menu_test.html
// key code section:
var D = YAHOO.util.Dom,
menu = new YAHOO.widget.Menu(D.generateId(), {lazyload: true});
menu.addItems(params.menu);
var t = new YAHOO.widget.Button({
type: "menu",
label: params.label,
menu: menu,
container: el
});
Do I need to render the menu before giving it to the Button?
If you want to see the params.menu, check the test case. The params.menu object is correct, it creates a menu when directly supplied to widget.Button. That's tested in the test case.
Any ideas appreciated.
Yes, you need to render. Add menu.render(document.body); after menu.addItems(params.menu); and it should work fine.