Automatically Show (Un-hide) Columns in Excel - excel

Is there a method whereby columns in Excel (2003, 2007 and/or 2010) can be automatically shown (un-hidden) when the column to the left contains data?
Something like this:
IF column to the left contains data
THEN show column
+-----+-----+
| C | C | //If column1 contains data
| O | O | //Then reveal/show (unhide) column2
| L | L |
| U | U |
| M | M |
| N | N |
| 1 | 2 |
+-----+-----+
I'm guessing that VB code is required but am unsure as to what this would be.
Further to this, is there a way to automatically show the column going by the date (first day of each month)? This is a little more complicated. For example:
FOR all dates
IF system date = year(month.day1) //If it is the first day of a new month
THEN show column(month) //Then show the corresponding column for that month
ENDIF
ENDFOR
i.e. IF system date = 01/09/2012
THEN show column(September)
Is this possible?
Thank you.

Correct, you need VBA to achieve that. Use the Worksheet_Change event which fires whenever something changes. Then, use one of the various methods to determine if a column is not empty (http://ewbi.blogs.com/develops/2006/03/determine_if_a_.html, or just google). Alternatively, if this is to slow because if fires almost all the time, you could use the Worksheet_Activate() event (an overview of all Excel events can be found here).
If your column 7 contains data, you can unhide column 8 using MyWorksheet.Columns("8:8").Hidden = False.
Your second problem can be solved in a similar way. In the Worksheet_Activate(), check if today is the first day in a month using Day(Date) = 1 (I guess it needs to take into account that the user may not be using Excel this day, so the code should be a little more complex) and show that column using MyWorksheet.Columns("12:12").Hidden = False (or whichever it is) for December 1st.
All this code assumes that the columns are already there, just hidden.

Related

Alternate row colour by data in fields in a spreadsheet

Good Afternoon all,
I've had a search but can't find the answer - please direct me if there is one!
I'm looking to make my spreadsheet have better readability to the user. It requires a lot of manual work outside of the sheet, so the less time strain the spreadsheet is, the better.
I know to to use =mod() in Conditional Formatting but this isn't what I'm looking for
I also know about opening the filter drop down, and clicking one cell, pressing down twice and pressing space bar (rinse and repeat) - but I'm not going to do this over 1000 rows...
Is there a way to alternate the colours from a filtered name in excel?
For example:
+---------------+---------------+--------------+
| Site Code | Site Name | Changed Date |
+---------------+---------------+--------------+
| 000020 | Bobs site | 28/11/18 | <-- colour 1
| 000020 | Bobs site | 26/11/18 | <-- colour 1
| 059201 | Julian's | date | <-- colour 2
| 059201 | Julian's | date | <-- colour 2
| 002237 | etc. 1 | date | <-- colour 1
| 523878 | etc. 2 | date | <-- colour 2
| 523878 | etc. 3 | date | <-- colour 2
+---------------+---------------+--------------+
So rather than by line number, it would be by the name "bobs site" would be one colour, the next in the list would be another colour etc
I would love for this to apply to site code and site name, so when filtering by either, the rows are highlighted correctly.
I can't do this in the =mod() kind of way, as some sites have just one entry, most have 2 and a few can have up to 10
EDIT: Proof of the answer working for future references
Doable with a helper column and Conditional Formatting with COUNTIF and MOD.
In the helper column:
=OR(A2<>A1,B2<>B1)
which returns TRUE or FALSE if the site code or site name has changed (or not) compared to the previous row.
Then 2 conditional formatting rules:
=MOD(COUNTIF($D$2:$D2,TRUE),2)=0
=MOD(COUNTIF($D$2:$D2,TRUE),2)=1
The mixed reference ($D$2:$D2) in the COUNTIF will allow for each separate section to be coloured alternately as the instances of TRUE are successively added up.
One solution; get all uniq values in a seperate column, copy column you want to refer to, paste to new column, remove duplicates.
Then select area with data and start refering those values you want to have that color i conditional formatting.
Edit
With more options use "AND" or "OR"

Conditional Formatting using dates and weekends

I have data in a spreadsheet like this
Name | 9/1/2016 | 9/2/2016 | .... | 6/8/2017
Abe | | | |
Jonas | | | |
I want to highlight every column where the date is either a weekend or a user defined date (for instance, a holiday....does excel already know federal holidays?).
The conditional format I have is:
Applies to
=$b$2:$KI$62
Format values where the following formula is true
#1 =WEEKDAY($B$1:$KI$1,1)=1
#2 =WEEKDAY($B$1:$KI$1,1)=7
Yet nothing shows up. At the best I've been able to only make the bottom row show up through playing with the function. Why?
With Name in A1, select B2 to the extents of your data and use the following to create a conditional formatting rule.
=WORKDAY(B$1-1, 1, $L$2:$L$4)<>B$1

Return values, based on value of an intersection of a row and column

I want to return a label(s) based on an intersection of a Row and Column equal to "Yes".
| Location |
ID | Tool | Wall | Bin | Toolbox | Count
---+--------+------+-----+---------+-------
1. | Axe | YES | | | 1
2. | Hammer | | | YES | 5
3. | Pliers | | | YES | 2
4. | Nails | | YES | | 500
5. | Hoe | YES | | | 2
6. | Screws | | YES | | 200
7. | Saw | YES | | | 3
What's in Toolbox? (Results wanted)
Axe,Wall, 1
Hammer, Toolbox, 5
Pliers,Toolbox, 2
Nails,Bin, 500
Hoe, Wall, 2
Screws, Bin, 200
Saw, Wall, 3
I also want to be able add Tools and Locations?
Without using VBA, this is going to be a bit of a pain, but workable if you don't mind helper columns. I don't advise trying to do this in a single Array Formula, because text strings are hard to work with in Array formulas. That is - if you have an array of numbers, you can turn that into a single result a lot of ways (MIN, MAX, AVERAGE, SUM, etc.). However with an array of strings, it's harder to work with. Particularly, there's no easy way to concatenate an array of strings.
So instead, use a helper column. Assume column A = toolname, column B = a check for being on the wall, column C = a check for being in the bin, column D for being in the toolbox, and column E for the number available.
FORMATTING SIDE NOTE
First, I will say that I recommend you use TRUE/FALSE instead of "yes"/"no". This is because it is easier to use TRUE / FALSE within Excel formulas. For example, if you want to add A1 + A2 when A3 = "yes", you can do so like this:
=IF(A3="yes",A1+A2)
But if you want to check whether A3 = TRUE, this is simplified:
=IF(A3,A1+A2)
Here, we didn't need to hardcode "yes", because A3 itself will either be TRUE or FALSE. Also consider if you want to make a cell "yes" if A3 > 5, and otherwise be "no". You could do it like this:
=IF(A3>5,"yes","no)
Or, if you used TRUE/FALSE, you could simply use:
=A3>5
However, I'll assume that you keep the formatting you currently have (I would also recommend you just have a single cell that says either "toolbox"/"bin" etc., instead of 4 columns where 1 says "yes", but we'll also assume that this needs to be this way).
BACK TO YOUR QUESTION
Put this in column F, in F2 for the first cell:
=Concatenate(A2," ",INDEX($B$1:$D$1,MATCH("yes",B2:D2,0))," ",E2)
Concatenate combines strings of text into a new single text string. You could also use &; like: A2 & " " etc., but with this many terms, this is likely easier to read. Index looks at your header row 1, and returns the item from the first column which matches "yes" in the current row.
Then put the following in F3 and drag down:
=Concatenate(F2," ", A2," ",INDEX($B$1:$D$1,MATCH("yes",B2:D2,0))," ",E2)
This puts a space in between the line above and the current line. If instead you want to make each row appear after a line-break, use this:
=Concatenate(F2,CHAR(10), A2," ",INDEX($B$1:$D$1,MATCH("yes",B2:D2,0))," ",E2)

Excel: Create new Row for each column

I have a data set as follows:
A | B | C |...
1abc | 1def | 1ghi |...
2abc | 2def | 2ghi |...
...
This is a collection of memo notes for each account in our database. The 1 in "1abc" represents the account ID and the letters represent some text. There are a total of 177 columns and 1866 rows but not every row has values up to column 177, some may only have two columns worth of data.
I need each column to drop down to the bottom of column A so that all data only occupies Column A. For example, all the data in column B would inserted after the last value in A. Data in column C would be inserted after the last value in column A after it's been populated with the data from B and so on.
In the end, it should look something like this (from which point I can simply sort it in ascending order).
A | B | C |
1abc | | |
2abc | | |
...
1def | | |
2def | | |
...
1ghi | | |
2ghi | | |
...
Can anyone help out with this? I am assuming that I need a macro and have tried working with the solution found in this post but couldn't figure it out. Oh, and I'm using Excel 2003 if that helps.
I am not sure if this will help but, from what you have given me, it sounds like you have 3 columns of data that you would like to be put into one column. If I am correct in my thinking, you can do this a few different ways. So as to preserve the original document in its entirety while adding an extended sorting system you could: 1: Create new tab. Then highlight range a with your mouse. Using your mouse right click and select copy (try to keep in mind the value of the range, E.g. How many items have you copied. Paste it in your now tab. Do this for the remaining ranges. Or maybe use V look up. If you would like I have a schedule module I have created that has many different types of range associations. You can also split sting in excel to divide the id from the sting.
Without VBA, add a blank row at the top and a column on the left populated throughout with say x and then follow the steps detailed here. Then delete the left-hand two columns and filter the remaining one to remove any blanks.

Dynamic data in Cucumber tables

I have a Cucumber table, one of the fields is a date which I would like to have populated with todays date.
Is there a way of doing this without having to hard code todays date into the table?
Basically I would like to enter Time.now.strftime("%Y-%m-%d") into the table and not have it break.
Since the table is being processed by your step definition, you could put a special place holder in the table, such as the string "TODAYS_DATE", and then use map_column! to process the data in the column to the format you want.
For example given the following table
Given the following user records
| username | date |
| alice | 2001-01-01 |
| bob | TODAYS_DATE |
In your step definition you would have
Given /^the following user records$/ do |table|
table.map_column!('date') do |date|
if date == 'TODAYS_DATE'
date = Time.now.strftime("%Y-%m-%d")
end
date
end
table.hashes.each do |hash|
#Whatever you need to do
end
end
Note this only changes the values when you ask for the hash. table and table.raw will remain the same, but whenever you need the row hashes, they will be converted by the code within the map_column!
I know it's been ages since this question was asked but I was doing something similar with Cucumber recently so here's an alternative solution if anyone's interested...
Given the following user records
| username | date |
| bob | Time.now.strftime("%Y-%m-%d") |
And then in your step definition just eval() the date string
Given /^the following user records$/ do |table|
table.hashes.each do |hash|
date = eval(hash["date"])
end
end
Though unlike Brandon's example this wont let you put in exact dates as well without some further logic.
bodnarbm's answer is pretty good if that is what you want to do. My own suggestion would be to take a look at the timecop gem. Use it to set time to a known day then adjust your tables accordingly.
Based on fixtures files I created this code:
Feature:
Given the following "Inquirers":
| id | email | start_date |
| 1 | alberto#deco.proteste.pt | <%= Time.now %> |
Helper:
Given(/^the following "(.*?)":$/) do |model, table|
table.hashes.each do |hash|
attributes = Rack::Utils.parse_nested_query(hash.to_query)
object = model_name.classify.constantize.new
attributes.keys.each do |key|
object.send("#{key}=", ERB.new(value).result())
end
...
end
end

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