Draw a hollow circle in SVG - svg

Question

I'm not sure how to approach drawing a hollow circle in SVG.
I would like a ring shape filled with a colour and then have a black outline.
The way I thought about doing it was have 2 circles, one with a smaller radius than the other. The problem is when I fill them, how do I make the smaller circle take the same fill colour as what it sits on?

Answer 1

Just use fill="none" and then only the stroke (outline) will be drawn.
<svg xmlns="http://www.w3.org/2000/svg" version="1.1">
<circle cx="100" cy="50" r="40" stroke="black" stroke-width="2" fill="none" />
</svg>
Or this if you want two colours:
<svg xmlns="http://www.w3.org/2000/svg" version="1.1">
<circle cx="100" cy="50" r="40" stroke="black" stroke-width="3" fill="none" />
<circle cx="100" cy="50" r="39" stroke="red" stroke-width="2" fill="none" />
</svg>

Answer 2

MDragon00's answer works, but the inner and outer circles are not perfectly aligned (e.g. centered).
I modified his approach a little, using 4 semi-circle arcs (2 outer and 2 inner in reversed direction) to get the alignment exactly right.
<svg width="100" height="100">
<path d="M 50 10 A 40 40 0 1 0 50 90 A 40 40 0 1 0 50 10 Z M 50 30 A 20 20 0 1 1 50 70 A 20 20 0 1 1 50 30 Z" fill="#0000dd" stroke="#00aaff" stroke-width="3" />
</svg>
<!--
Using this path definition as d:
M centerX (centerY-outerRadius)
A outerRadius outerRadius 0 1 0 centerX (centerY+outerRadius)
A outerRadius outerRadius 0 1 0 centerX (centerY-outerRadius)
Z
M centerX (centerY-innerRadius)
A innerRadius innerRadius 0 1 1 centerX (centerY+innerRadius)
A innerRadius innerRadius 0 1 1 centerX (centerY-innerRadius)
Z
-->

Answer 3

Thanks to Chasbeen, I figured out how to make a true ring/donut in SVG. Note that the outer circle actually isn't closed, which is only apparent when you use a stroke. Very useful when you have many concentric rings, especially if they're interactive (say, with CSS hover commands).
For the draw command...
M cx, cy // Move to center of ring
m 0, -outerRadius // Move to top of ring
a outerRadius, outerRadius, 0, 1, 0, 1, 0 // Draw outer arc, but don't close it
Z // default fill-rule:even-odd will help create the empty innards
m 0 outerRadius-innerRadius // Move to top point of inner radius
a innerRadius, innerRadius, 0, 1, 1, -1, 0 // Draw inner arc, but don't close it
Z // Close the inner ring. Actually will still work without, but inner ring will have one unit missing in stroke
JSFiddle - Contains several rings and CSS to simulate interactivity. Note the downside that there's a single pixel missing at the starting point (at the top), which is only there if you add a stroke on.
Edit:
Found this SO answer (and better yet, this answer) which describes how to get the empty innards in general

Answer 4

You can do this as per the SVG spec by using a path with two components and fill-rule="evenodd". The two components are semi-circular arcs which join to form a circle (in the "d" attribute below, they each end with a 'z'). The area inside the inner circle does not count as part of the shape, hence interactivity is good.
To decode the below a little, the "340 260" is the top middle of the outer circle, the "290 290" is the radius of the outer circle (twice), the "340 840" is the bottom middle of the outer circle, the "340 492" is the top middle of the inner circle, the "58 58" is the radius of the inner circle (twice) and the "340 608" is the bottom middle of the inner circle.
<svg viewBox="0 0 1000 1000" xmlns="http://www.w3.org/2000/svg">
<path fill-rule="evenodd" d="M340 260A290 290 0 0 1 340 840A290 290 0 0 1 340 260zM340 492A58 58 0 0 1 340 608A58 58 0 0 1 340 492z" stroke-width="4" stroke="rgb(0,0,0)" fill="rgb(0,0,255)">
<title>This will only display on the donut</title>
</path>
</svg>

Answer 5

This is the classic donut shape
I'm not sure if you are trying to achieve this with standard SVG or JavaScript that produces SVG
The objective can be achieved by including a relative "moveto" command in a single path definition
And click "donut holes" on the right side of the interactive examples.
At the very least you can see the path definition that made the red donut.

Answer 6

Here's a routine to create a bezier arc which is as close as makes no odds to a circle. You need four of them in a path for a complete circle.
BezierCurve BezierArc(double ox, double oy, double r, double thetaa, double thetab)
{
double theta;
double cpx[4];
double cpy[4];
int i;
int sign = 1;
while (thetaa > thetab)
thetab += 2 * Pi;
theta = thetab - thetaa;
if (theta > Pi)
{
theta = 2 * Pi - theta;
sign = -1;
}
cpx[0] = 1;
cpy[0] = 0;
cpx[1] = 1;
cpy[1] = 4.0 / 3.0 * tan(theta / 4);
cpx[2] = cos(theta) + cpy[1] * sin(theta);
cpy[2] = sin(theta) - cpy[1] * cos(theta);
cpx[3] = cos(theta);
cpy[3] = sin(theta);
cpy[1] *= sign;
cpy[2] *= sign;
cpy[3] *= sign;
for (i = 0; i < 4; i++)
{
double xp = cpx[i] * cos(thetaa) + cpy[i] * -sin(thetaa);
double yp = cpx[i] * sin(thetaa) + cpy[i] * cos(thetaa);
cpx[i] = xp;
cpy[i] = yp;
cpx[i] *= r;
cpy[i] *= r;
cpx[i] += ox;
cpy[i] += oy;
}
return BezierCurve({cpx[0], cpy[0]},{cpx[1], cpy[1]}, {cpx[2], cpy[2]}, {cpx[3], cpy[3]});
}