Add Permission to Object - object

I have a System called 'A' that holds the objects of itself into data structure by name. Basically System 'A' has a function called getObject(obj_name). This function creates an object with the given name, obj_name, if it's not already exists and then return it otherwise it just return the object.
Now, Program 1 uses System 'A' and creates an object called "Program1_Object" using above function (getObject)
Program 2 calls getObject with "Program1_Object" as its argument.
The problem in here is getObject returns Program 1 object to Program 2. I want to add permission to that object that if object is not meant for the caller program returns an error or create a new one for the caller program.
What is a trick behind it?
Thanks

A could be a simple wrapper for a hash table. Permissions could be implemented with an additional parameter to getObject stating the permissions of the calling code.

Related

GetObject Fails while CreateObject Works [duplicate]

This question already has answers here:
How to use GetObject in VBScript
(2 answers)
Closed 3 years ago.
I recently got a small CG software package from my friend his father wrote about 30 years ago. It has a window where one can create and render some solid primitives. Interestingly, it has a VBA interface and I can in Excel (let’s call it TheSoftware) use Set app = CreateObject(“TheSoftware.Application”) to create such application (after setting app.Visible to True one can get the window on the screen)! However, the GetObject(, “TheSoftware.Application”) returns the “ActiveX component can’t create object” error. More surprisingly to me, the GetObject(“”, “TheSoftware.Application”) successfully creates the application! I have its source code in C++ about 900 KB that I can share, but just to be quick, has anyone had this issue before, or have a clue what may be the issue? I am no expert in C++, and the author passed away 4 years ago. I have seen the “opposite” problem of failing to create an object but OK when getting it, but not this one. Any idea is welcome, thanks!
GetObject(FName) opens a file or connects to a file if it already opened (and if class is specified use that class to open it) OR GetObject(,"Appname") connects to a running instance of an application. You are creating a blank file.
Visual Basic Scripting Edition
GetObject Function
See Also CreateObject Function
Requirements
Version 5
Returns a reference to an Automation object from a file.
GetObject([pathname] [, class])
Arguments
pathname
Optional; String. Full path and name of the file containing the object to retrieve.
If pathname is omitted, class is required.
class
Optional; String. Class of the object.
The class argument uses the syntax appname.objectype and has these
parts:
Use the GetObject function to access an Automation object from a file
and assign the object to an object variable. Use the Set statement to
assign the object returned by GetObject to the object variable. For
example:
Dim CADObject
Set CADObject = GetObject("C:\CAD\SCHEMA.CAD")
When this code is executed, the application associated with the
specified pathname is started and the object in the specified file is
activated. If pathname is a zero-length string (""), GetObject
returns a new object instance of the specified type. If the pathname
argument is omitted, GetObject returns a currently active object of
the specified type. If no object of the specified type exists, an
error occurs.
Some applications allow you to activate part of a file. Add an
exclamation point (!) to the end of the file name and follow it with a
string that identifies the part of the file you want to activate. For
information on how to create this string, see the documentation for
the application that created the object.
For example, in a drawing application you might have multiple layers
to a drawing stored in a file. You could use the following code to
activate a layer within a drawing called SCHEMA.CAD:
Set LayerObject = GetObject("C:\CAD\SCHEMA.CAD!Layer3")
If you don't specify the object's class, Automation determines the application to start and the object to activate, based on the file
name you provide. Some files, however, may support more than one class
of object. For example, a drawing might support three different types
of objects: an Application object, a Drawing object, and a Toolbar
object, all of which are part of the same file. To specify which
object in a file you want to activate, use the optional class
argument. For example:
Dim MyObject
Set MyObject = GetObject("C:\DRAWINGS\SAMPLE.DRW", "FIGMENT.DRAWING")
In the preceding example, FIGMENT is the name of a drawing application
and DRAWING is one of the object types it supports. Once an object is
activated, you reference it in code using the object variable you
defined. In the preceding example, you access properties and methods
of the new object using the object variable MyObject. For example:
MyObject.Line 9, 90
MyObject.InsertText 9, 100, "Hello, world."
MyObject.SaveAs "C:\DRAWINGS\SAMPLE.DRW"
Note Use the GetObject function when there is a current instance
of the object or if you want to create the object with a file already
loaded. If there is no current instance, and you don't want the
object started with a file loaded, use the CreateObject function.
If an object has registered itself as a single-instance object, only
one instance of the object is created, no matter how many times
CreateObject is executed. With a single-instance object, GetObject
always returns the same instance when called with the zero-length
string ("") syntax, and it causes an error if the pathname argument is
omitted.
Requirements Version 5
See Also CreateObject Function
© 2001 Microsoft Corporation. All rights reserved.
Build: Topic Version 5.6.9309.1546
Also these are the COM API calls that each form makes. From the Automation part of the COM docs.
CreateObject (“ProgID”)
CLSIDFromProgID
CoCreateInstance
QueryInterface to get IDispatch interface.
GetObject (“filename”, “ProgID”)
CLSIDFromProgID
CoCreateInstance
QueryInterface for IPersistFile interface.
Load on IPersistFile interface.
QueryInterface to get IDispatch interface.
GetObject (“filename”)
CreateBindCtx creates the bind context for the subsequent functions.
MkParseDisplayName returns a moniker handle for BindMoniker.
BindMoniker returns a pointer to the IDispatch interface.
Release on moniker handle.
Release on context.
GetObject (“ProgID”)
CLSIDFromProgID
GetActiveObject on class ID.
QueryInterface to get IDispatch interface.
Dim x As New interface
Find CLSID for interface.
CoCreateInstance
QueryInterface

Azure Function ExecutionContext.InvocationId vs FunctionFilterContext.FunctionInstanceId

ExecutionContext.InvocationId vs FunctionFilterContext.FunctionInstanceId
The ExecutionContext in Azure Function has a property InvocationId. In IFunctionInvocationFilter.OnExecutedAsync(FunctionExecutedContext ...) the FunctionExecutedContext has a property FunctionInstanceId, which is defined in its base class FunctionFilterContext.
In the same call, are these two Ids the same?
Are they unique for each call, or for each function instance?
Thanks if anyone can help!
I was confused at first, but these are actually the same thing. They are both showing a unique identifier of function call, so they are the same for the same call, and different between calls.
The docs aren't great in this part, but you can compare Retrieving information about the currently running function
Provides the invocation ID, uniquely identifying the current invocation
with FunctionExceptionContext source code
The instance ID for the function invocation
I actually ran a test and both properties gave me the same Guid.

How to get the class name when running a constructor function in duktape?

I'd like to use a single duktape/C constructor function as dispatcher for these kind of calls. When the dispatcher function is called I need to know for which class this happend to call the appropriate C++ construction function.
I guess the this binding won't help since it represents the (not yet fully initialized) JS object we are creating here.
Another option would be the current function, but from the docs I can't see how to get the class name from that. What else could I use?
Could you elaborate what you mean by "class name"? Do you mean the .name property of the Ecmascript function object which is used as a the 'new' target?
If so, you can use duk_is_constructor_call() to see if the current call is a constructor call, then use duk_push_current_function() to get access to the Ecmascript constructor function object, and then read its properties using the usual property API calls. For example, if by "class name" you mean .name of the function object, you'd just read its "name" property using duk_get_prop_string().

How to get caller file name in Node.js?

I have a Node class which I import in many of my projects modules Once imported into required module I create object of it and then call related methods of that object.
My question is how do I get the object caller's file name in my class file without explicitly passing so
I don't want to use module.parent.filename as it only gives the file name of parent file and not of other files. After some R&D I came to know that there is a module called stack-trace which could provide me similar functionality. But when I tried following code into my class I got the name of file itself in which the code was written and not the name of file which was calling the object of that class
const stackTrace = require('stack-trace');
var trace = stackTrace.get()
console.log(trace[0].getFileName())
The manual states, for stackTrace.get():
Returns an array of CallSite objects, where element 0 is the current call site.
You don't want the current call site, but the previous one, so you need to use trace[1].getFileName()

Object reference exactly

Demo demo=new Demo();
Here demo is a reference variable. Are reference variables equal to object references... ?
If no then please explain the concept of object reference.
Demo represents the type of the object.
demo represents the object reference, you will be able to refer to new Demo() object and calling its methods (for example).
new Demo() represents the object itself which is situated in heap memory.
In case of java language,
When you write the statement
Demo obj = new Demo();
It means that You are declaring a variable named obj and it is of type Demo.
by writing
obj = new Demo();
You are creating a new object in the heap memory and the reference variable "obj" will refer to it so that when you want to access the object created just now, you can access it through reference variable "obj".
so when you want to call some method on Demo object, you can call it using
obj.someMethod();
A reference to an object is a way to denote that object. The address of an object, for example, is one kind of reference (probably the simplest kind). Other kinds of references can exist, too, and they are written and read using some more complicated logic. It could theoretically be a double pointer, a pseudo-address, or something else - as long as it contains enough information that (if interpreted in a specified way) can be used to denote a specific object, .
A reference variable is a variable whose value is a reference to an object. So, for example, a reference variable could be a variable whose value is the address of an object, or (as I described above) something different, but equivalent.
For comparison, the other common type of variable (called primitive type in Java, value type in C# and other names in other contexts) is the kind variable whose value is an actual object (instead of a reference).

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