I want to change all occurrences of == to ===, but issuing the command :%s/==/===/g would convert existing identity operators from === to ====. I tried using the command :%s/\<==\>/===/g, but no pattern matches are found.
The informal definition of the pattern given in the question could be
read as “two equal signs in a row neither preceded with nor followed
by an equal sign”.
A natural way to transform this verbal description to a concise Vim
regular expression is to use the \#<! and \#! zero-width assertions
(see :help /multi for an overview). The former allows to leave out
the occurrences starting with a certain pattern (see :help /\#<!).
The latter makes it possible to ignore the occurrences ending with an
ineligible pattern (see :help /\#!).
:%s/=\#<!===\#!/&=/g
As far as I can guess from the history of your questions and answers
on StackOverflow, the substitution is probably to be performed in
JavaScript or PHP source code. Since both languages have the !==
inequality operator as well as the === equality one, == in the
former is also the subject of replacement as you describe it in the
question. If this behavior is undesirable, modify the substitution
command above, as follows:
:%s/[!=]\#<!===\#!/&=/g
kind of ugly, but :%s/\([^=]\)==\([^=]\)/\1===\2/g
EDIT
Turned out that ib. has far better solution so look at his answer. That takes care of the cases of !== etc. So ignore this one and look at his.
Consider adding the c flag on the sed command: %s/==/===/gc
This will allow you to choose every time with y or n. Of course if there are a lot then this might not be the best plan.
Related
The exact problem: I have a source in C++ and I need to replace a symbol name to some other name. However, I need that this replace the symbol only, not accidentally the same looking word in comments or text in "".
The source information what particular language section it is, is enough defined in the syntax highlighting rules. I know they can fail sometimes, but let's state this isn't a problem. I need some way to walk through all found occurrences of the phrase, then check in which section it is found, and if it's text or comment, this phrase should be skipped. Otherwise the replacement should be done either immediately, or by asking first, depending on well known c flag.
What I imagine would be at least theoretically possible is:
Having a kinda "callback" when doing substitution (called for each phrase found, and requesting the answer whether to substitute or not), or extract the list of positions where the phrase has been found, then iterate through all of them
Extract the name of the current "hi-linked" syntax highlighting rule, which is used to color the text at given position
Is it at all possible within the current features of vim?
Yes, with a :help sub-replace-expression, you can evaluate arbitrary expressions in the replacement part of :substitute. Vim's synID() and synstack() functions allow you to get the current syntax element.
Luc Hermitte has an implementation that omits replacement inside strings, here. You can easily adapt this to your use case.
With the help of my ingo-library plugin, you can define a short predicate function, e.g. matching comments and constants (strings, numbers, etc.):
function! CommentOrConstant()
return ingo#syntaxitem#IsOnSyntax(getpos('.'), '^\%(Comment\|Constant\)$')
endfunction
My PatternsOnText plugin now provides a :SubstituteIf command that works like :substitute, but also takes a predicate expression. With that, it's very easy to do a replacement anywhere except in comments or constants:
:%SubstituteIf/pattern/replacement/g !CommentOrConstant()
Most substitution commands in vim perform an action on a full line or a set of lines, but I would like to only do this on part of a line (either from the cursor to end of the line or between set marks).
example
this_is_a_sentence_that_has_underscores = this_is_a_sentence_that_should_not_have_underscores
into
this_is_a_sentence_that_has_underscores = this is a sentence that should not have underscores
This task is very easy to do for the whole line :s/_/ /g, but seems to be much more difficult to only perform the replacement for anything after the =.
Can :substitution perform an action on half of a line?
Two solutions I can think of.
Option one, use the before/after column match atoms \%>123c and \%<456c.
In your example, the following command substitutes underscores only in the second word, between columns 42 and 94:
:s/\%>42c_\%<94c/ /g
Option two, use the Visual area match atom \%V.
In your example, Visual-select the second long word, leave Visual mode, then execute the following substitution:
:s/\%V_/ /g
These regular expression atoms are documented at :h /\%c and :h /\%V respectively.
Look-around
There is a big clue your post already:
only perform the replacement for anything after the =.
This often means using a positive look-behind, \#<=.
:%s/\(=.*\)\#<=_/ /g
This means match all _ that are after the following pattern =.*. Since all look-arounds (look-aheads and look-behinds) are zero width they do not take up space in the match and the replacement is simple.
Note: This is equivalent to (?<=...) in perl speak. See :h perl-patterns.
What about \zs?
\zs will set the start of a match at a certain point. On the face this sounds exactly what is needed. However \zs will not work correctly as it matches the pattern before the \zs first then the following pattern. This means there will only be one match. Look-behinds on the other hand match the part after \#<= then "look behind" to make sure the match is valid which makes it great for multiple replacement scenario.
It should be noted that if you can use \zs not only is it easy to type but it is also more efficient.
Note: \zs is like \K in perl speak.
More ways?!?
As #glts mentioned you can use other zero-width atoms to basically "anchor" your pattern. A list of a few common ways:
\%>a - after the 'a mark
\%V - match inside the visual area
\%>42c - match after column 42
The possible downside of using one of these methods they need you to set marks or count columns. There is nothing wrong with this but it means the substitution will maybe affected by side-effects so repeating the substitution may not work correctly.
For more help see:
:h /\#<=
:h /zero-width
:h perl-patterns
:h /\zs
When i need to replace a string with a new string in vim.
First i would use search-mode to check that the search pattern is correct.
/search pattern
Then use the 's' command to do substitution.
:%s/search pattern/new string/
The search pattern need to type twice. If it is too complex, it would be boring.
Is there a method to avoid this?
You can simply omit the pattern in the substitution command, e.g.
:%s//new string/
This is documented in :help last-pattern (emphasis mine):
The last used pattern and offset are remembered. They can be used to
repeat the search, possibly in another direction or with another
count. Note that two patterns are remembered: One for 'normal' search
commands and one for the substitute command ":s". Each time an empty
pattern is given, the previously used pattern is used.
Also (in addition to Marco Baldelli's correct answer), the last search pattern is stored in the special register /. You can insert this in the command-line via Ctrl + R, followed by /. (This also works in insert mode, and also with other registers.) It's helpful when you want to tweak your search pattern before substituting.
I have several functions that start with get_ in my code:
get_num(...) , get_str(...)
I want to change them to get_*_struct(...).
Can I somehow match the get_* regex and then replace according to the pattern so that:
get_num(...) becomes get_num_struct(...),
get_str(...) becomes get_str_struct(...)
Can you also explain some logic behind it, because the theoretical regex aren't like the ones used in UNIX (or vi, are they different?) and I'm always struggling to figure them out.
This has to be done in the vi editor as this is main work tool.
Thanks!
To transform get_num(...) to get_num_struct(...), you need to capture the correct text in the input. And, you can't put the parentheses in the regular expression because you may need to match pointers to functions too, as in &get_distance, and uses in comments. However, and this depends partially on the fact that you are using vim and partially on how you need to keep the entire input together, I have checked that this works:
%s/get_\w\+/&_struct/g
On every line, find every expression starting with get_ and continuing with at least one letter, number, or underscore, and replace it with the entire matched string followed by _struct.
Darn it; I shouldn't answer these things on spec. Note that other regex engines might use \& instead of &. This depends on having magic set, which is default in vim.
For an alternate way to do it:
%s/get_\(\w*\)(/get_\1_struct(/g
What this does:
\w matches to any "word character"; \w* matches 0 or more word characters.
\(...\) tells vim to remember whatever matches .... So, \(w*\) means "match any number of word characters, and remember what you matched. You can then access it in the replacement with \1 (or \2 for the second, etc.)
So, the overall pattern get_\(\w*\)( looks for get_, followed by any number of word chars, followed by (.
The replacement then just does exactly what you want.
(Sorry if that was too verbose - not sure how comfortable you are with vim regex.)
This question was helpful for getting a count of a certain pattern in Vim, but it would be useful to me to store the count and sum the results so I can echo a concise summary.
I'm teaching a class on basic HTML to some high schoolers, and I'm using this script to be quickly check numbers of required elements throughout all their pages without leaving Vim. It works fine, but when students have more than 10 .html files it gets cumbersome to add up the various sections by hand.
Something like:
img_sum = :bufdo %s/<img>//gen
would be nice. I think I'll write a ruby script to check the pages more thoroughly and check for structure, but for now I'm curious about how to do this in Vim.
The problem can be solved by a counter separate from the one built-in into the
:substitute command: Use Vim-script variable to hold the number of pattern
matches. A convenient way to register every match and modify a particular
variable accordingly, is to take advantage of the substitute with an
expression feature of the :substitute command (see :help sub-replace-\=).
The idea is to use a substitution that evaluates an expression increasing
a counter on every occurrence, and does not change the text it is operating
on.
The first part of the technique cannot be implemented straightforwardly
because it is forbidden to use Ex commands in expressions (including \=
substitute expressions), and therefore it is not possible to use the :let
command to modify a variable. Answering the question "gVim find/replace
with counter", I have proposed a simple trick to overcome that limitation,
which is based on using a single-item list (or dictionary containing a single
key-value pair). Since the map() function transforms a list or a dictionary
in place, that only item could be changed in a constrained expression context.
To do that, one should call the map() function passing an expression
evaluating to the new value along with the list containing the current value.
The second half of the technique is how to avoid changing text when using
a substitution command. In order to achieve that, one can make the pattern
have zero-width by prepending \ze or by appending \zs atoms to it (see
:help /\zs, :help /\ze). In such a way, the modified pattern captures
a string of zero width just before or after the occurrence of the initial
pattern. So, if the replacement text is also empty, substitution does not
cause any change in the contents of a buffer. To make the substitute
expression evaluate to an empty string, one can just extract an empty
substring or sublist from the resulting value of that expression.
The two ideas are put into action in the following command.
:let n=[0] | bufdo %s/pattern\zs/\=map(n,'v:val+1')[1:]/ge
I think that answer above is hard to understand and more pretty way to use external command grep like this:
:let found=0
:bufdo let found=found+(system('grep "<p>" '.expand('%:p') . '| wc -l'))
:echo found