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There is a function of a 2D geometrical shape and 1D interval,
f(s, i) = Py (s ⋂ i×(-∞,∞))
It calculates intersection of shape with infinite vertical rectangle (determined by given interval i = [x1, x2)) and then projects it to Y axis.
Is there a good name for this function?
GetIntersection seems like an obvious candidate...
If you don't like Blindy's answer maybe you can call it:
ProjectoToYAfterIntersectingInfiniteRectangle(x1,x2)
But I would go with just GetIntersection as Blindy said +1
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I need to solve the following problem:
Give a linear-time algorithm to determine if a text T is a cyclic rotation of another string T'. For example, arc and car are cyclic rotations of each other.
I have no idea where to start. How can I solve this problem?
As a hint: if x and y have the same length, then x is a cyclic rotation of y iff x is a substring of yy. Try proving this and using this as the basis for your algorithm.
Hope this helps!
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I have several variables with monthly stock returns like qqqret, gldret,spyret. I would like to create a stacked histogram or dotplot of them all on the same scale. any ideas how?
thanks!
ps. if i stack my vectors on top of each other and create an indicator variable for each one I could use strip plot. but i want to be able to say something like "hist qqqret gldret spyret"
dotplot supports a varlist: see the help.
stripplot (SSC) is an alternative.
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The points are in a plane，marked with two numbers indicating coordinates.give out a connect sequence.
Take the convex hull. If it is a quadrilateral, you are done. If it is a triangle, you can break any of its edges apart to include the inner point.
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I have a list of points (x/y each in one column) and need to determine the maximum distance of any combination of pairs of points.
I'm only interested in the distance not the pair of points itself.
Right now I use a rough upper boundary estimation by calculating the length of the vector
(max(x)-min(x), max(y)-min(y))
You could try using CTRL+SHIFT+ENTER:
=MAX((x-TRANSPOSE(x))^2+(y-TRANSPOSE(y))^2)^0.5
Also see: http://newtonexcelbach.wordpress.com/2010/11/27/maximum-distance-between-two-points/
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It seems I completely forgot geometry :-( It looks like a simple. I need it for my flash game.
I drawn it in Carmetal program:
I need coordinates of C(x,y). Please help me to find a solution.
You can stick with simple trig...
Here, the blue line length is (By - Ay). So the angle at B is acos((By - Ay) / AB). Subtracting that angle from the angle ABC, you find the angle at B in the larger triangle. Knowing the length BC and that angle, you can calculate the length of the brown line with
l1 = BC/sin(small_angle)
Similarly, the length of the blue and red lines together is
l2 = BC/cos(small_angle)
And C is (Bx + l1, By - l2).