I am trying to convert all files in a given directory with suffix ".foo" to files containing the same basename but with suffix modified to ".bar". I am able to do this with a shell script and a for loop, but I want to write a one-liner that will achieve the same goal.
Objective:
Input: *.foo
Output: *.bar
This is what I have tried:
find . -name "*.foo" | xargs -I {} mv {} `basename {} ".foo"`.bar
This is close but incorrect. Results:
Input: *.foo
Output: *.foo.bar
Any ideas on why the given suffix is not being recognized by basename? The quotes around ".foo" are dispensable and the results are the same if they are omitted.
Although basename can work on file extensions, using the shell parameter expansion features is easier:
for file in *.foo; do mv "$file" "${file%.foo}.bar"; done
Your code with basename doesn't work because the basename is only run once, and then xargs just sees {}.bar each time.
for file in *.foo ; do mv $file echo $file | sed 's/\(.*\.\)foo/\1bar/' ; done
Example:
$ ls
1.foo 2.foo
$ for file in *.foo ; do mv $file `echo $file | sed 's/\(.*\.\)foo/\1bar/'` ; done
$ ls
1.bar 2.bar
$
for x in $(find . -name "*.foo"); do mv $x ${x%%foo}bar; done
$ for f in *.foo; do echo mv $f ${f%foo}bar; done
mv a.foo a.bar
mv b.foo b.bar
Remove echo when ready.
If you have installed mmv, you can do
mmv \*.foo \#1.bar
.
Why don't you use "rename" instead of scripts or loops.
RHEL: rename foo bar .*foo
Debian: rename 's/foo/bar/' *.foo
Related
I want duplicates of the files with different name.
I am currently trying out these commands before putting them into my bash script.
$ set dir = /somewhere/states
$ find $dir -name "total.txt" -type f | xargs ls -1
/somewhere/states/florida/fixed.fl_Asite_ttl/somewhere/total.txt
/somewhere/states/hawaii/fixed.hi_Bsite_ttl/somewhere/total.txt
/somewhere/states/kentucky/fixed.ky_Asite_ttl/somewhere/total.txt
/somewhere/states/michigan/fixed.mi_Csite_ttl/somewhere/total.txt
/somewhere/states/texas/fixed.tx_Vsite_ttl/somewhere/total.txt
I know I can rename file using something like this, but it isn't exactly what I want:
$ find $dir -name "total.txt" -exec sh -c 'cp {} `dirname {}`/`basename {} `why.xls' \;
/somewhere/states/florida/fixed.fl_Asite_ttl/somewhere/total.txtwhy.xls
/somewhere/states/hawaii/fixed.hi_Bsite_ttl/somewhere/total.txtwhy.xls
/somewhere/states/kentucky/fixed.ky_Asite_ttl/somewhere/total.txtwhy.xls
/somewhere/states/michigan/fixed.mi_Csite_ttl/somewhere/total.txtwhy.xls
/somewhere/states/texas/fixed.tx_Vsite_ttl/somewhere/total.txtwhy.xls
May I know how to copy the files and have the new files in the same dir?
below are the examples.
I want to name the new files as everything behind "fixed." and before "/somewhere" and changing the file extension as well
/somewhere/states/florida/fixed.fl_Asite_ttl/somewhere/fl_Asite_ttl.xls
/somewhere/states/hawaii/fixed.hi_Bsite_ttl/somewhere/hi_Bsite_ttl.xls
/somewhere/states/kentucky/fixed.ky_Asite_ttl/somewhere/ky_Asite_ttl.xls
/somewhere/states/michigan/fixed.mi_Csite_ttl/somewhere/mi_Csite_ttl.xls
/somewhere/states/texas/fixed.tx_Vsite_ttl/somewhere/tx_Vsite_ttl.xls
Update:
/somewhere/states/florida_fixed_ttl/fixed.fl_Asite_ttl/somewhere/total.txt
Probably not the most elegant but this should work:
find . -name total.txt | while read F ; do [[ $F =~ fixed.[^/]* ]] ; N=$(echo $BASH_REMATCH | sed s/fixed\.//) ; echo "cp $F $(dirname $F)/$N.xls" ; done
If you are happy with the output just remove the last echo, i.e. this:
echo "cp $F $(dirname $F)/$N.xls"
to this:
cp "$F" "$(dirname $F)/$N.xls"
Note, if the .txt and .xls contents will always remain the same you can use ln instead of cp -- one file, two names.
I have a directory which contains multiple files. I need to rename these files.
This is how the file names looks like:
snap-file-name-1.txt
snap-file-name-2.txt
snap-file-name-3.txt
I need to remove "snap" and ".txt" from these files.
-file-name-1
-file-name-2
-file-name-3
How do I do that with mv command?
Use sed to manipulate the file name:
ls | while read file; do
mv -- ${file} $(sed -n 's/snap\(.*\).txt/\1/p' <<<${file})
done
With Bash you could do something like this to rename those files:
#!/bin/bash
files=$(find -type f -name 'snap-file-name-*.txt')
for f in $files
do
mv "$f" "$(echo $f | sed -n 's/snap\(.*\).txt/\1/p')"
done
Use rename command with specific regex pattern:
rename 's/snap([-a-z0-9]+)\.txt$/$1/' *.*
I need to insert text from 1 file at the top of a large number of files in a directory and its subdirectories. I have been able to do this successfully on a file by file basis using ed:
ed -s FileToAddTo.txt <<< $'0r TextToAdd.txt\nw'
However, when I replace FileToAddTo.txt with *.txt, nothing happens. How can I modify this, or use another Unix command such as sed, to add the contents of TextToAdd.txt recursively to all files in a directory ending with a specific extension? e.g
ed -rs *.txt <<< $'0r TextToAdd.txt\nw'
Please note that the code above this line does not work, it merely demonstrates what I would like to achieve.
Like this:
cat TextToAdd.txt FileToAddTo.txt > $$.tmp && mv $$.tmp FileToAddTo.txt
i.e. cat the new header file and the original file into a temporary file and then, if it was successful, rename the temporary file as the original.
And to run recursively !! PLEASE TEST ON BACKED UP DATA!!!
find . -type f -name "*.txt" -exec sh -c "cat TextToAdd.txt {} > $$.tmp && mv $$.tmp {}" \;
This works pretty well for me:
$ for fn in `find . -name '*.txt'`; do; cat textToAdd.txt $fn > $$.tmp && mv $$.tmp $fn; done;
Based on this, you can try:
for fn in `ls -R /folderName`; do cat "$fn" >> fileName; done
What is the good way to add file extension ".jpg" to extension-less files with bash?
# Strip .jpg from all filenames
for f in *.jpg; do mv "$f" "${f%.jpg}"; done
# Add .jpg to all filenames (even those with .jpg already)
for f in *; do mv "$f" "$f.jpg"; done
# Add .jpg to all filenames...unless they are already .jpg
for f in *; do case "$f" in *.jpg) echo skipped $f;; *) mv "$f" "$f".jpg; esac; done
# Add .jpg to all filenames...unless they already have a . extension
for f in *; do case "$f" in *.*) echo skipped $f;; *) mv "$f" "$f".jpg; esac; done
You can use rename:
rename 's/(.*)/$1.jpg/' *
Another way - without loops
find . -type f -not -name "*.*" -print0 |\
xargs -0 file |\
grep 'JPEG image data' |\
sed 's/:.*//' |\
xargs -I % echo mv % %.jpg
Breakdown:
find all files without extension
check the file type
filter out only JPG files
delete filetype info
xargs run the "mv" for each file
the above command is for dry run, after it you should remove the "echo" before mv
EDIT
Some people suggesting that here is needed "Wrap path arguments in quotes; avoids argument splitting on paths with spaces".
Usually, this recommendation is true, in this case isn't. Because, here the % is got replaced not by shell expansion but by the xargs internally (directly), so the % will be substituted correctly even with spaces in filenames.
Simple demo:
$ mkdir xargstest
$ cd xargstest
# create two files with spaces in names
$ touch 'a b' 'c d'
$ find . -type f -print
./c d
./a b
# notice, here are spaces in the above paths
#the actual xargs mv WITHOUT quotes
$ find . -type f -print | xargs -I % mv % %.ext
$ find . -type f -print
./a b.ext
./c d.ext
# the result is correct even in case with spaces in the filenames...
Simple,
cd to the directory where your files are and:
for f in *;do mv $f $f.jpg;done
dry run:
rename -n s/$/.jpg/ *
actual renaming:
rename s/$/.jpg/ *
find . | while read FILE; do if [ $(file --mime-type -b "$FILE") == "image/jpeg" ]; then mv "$FILE" "$FILE".jpg; fi; done;
In my case i was not aware of the filetype so i used the mv command with the help of the file command to examine and possibly find the file type. This solution might not be perfect for all files since the file command might not recognize the filetype but it worked mostly good for me.
for f in *; do ext=$(file $f | awk '{print $2;}'); mv -n "$f" "$f.$ext"; done
The use of awk is to strip the second word of the string returned from the command file that is actually the extension.
rename --dry-run * -a ".jpg" # test
* -a ".jpg" # rename
You can use move multiple files. I am a maintainer of this project. The syntax is simple.
mmf files*
It will open your $EDITOR with all files names, or vim by default and you can simply highlight the end of all file names using Ctrl+v+G in vim , save the file,quit and that it , all your files are renamed
Ryan Li
The correct syntax for adding a file extension to multiple files within a directory which do not have a file extension is
find . | while read FILE; do if [[ -n `file --mime-type "$FILE" | grep 'message/rfc822'` ]]; then mv "$FILE" "$FILE".eml; fi; done;
I have a number of files in a folder, and I want to replace every space character in all file names with underscores. How can I achieve this?
This should do it:
for file in *; do mv "$file" `echo $file | tr ' ' '_'` ; done
I prefer to use the command 'rename', which takes Perl-style regexes:
rename "s/ /_/g" *
You can do a dry run with the -n flag:
rename -n "s/ /_/g" *
Use sh...
for i in *' '*; do mv "$i" `echo $i | sed -e 's/ /_/g'`; done
If you want to try this out before pulling the trigger just change mv to echo mv.
If you use bash:
for file in *; do mv "$file" ${file// /_}; done
What if you want to apply the replace task recursively? How would you do that?
Well, I just found the answer myself. Not the most elegant solution, (also tries to rename files that do not comply with the condition) but it works. (BTW, in my case I needed to rename the files with '%20', not with an underscore)
#!/bin/bash
find . -type d | while read N
do
(
cd "$N"
if test "$?" = "0"
then
for file in *; do mv "$file" ${file// /%20}; done
fi
)
done
Here is another solution:
ls | awk '{printf("\"%s\"\n", $0)}' | sed 'p; s/\ /_/g' | xargs -n2 mv
uses awk to add quotes around the name of the file
uses sed to replace space with underscores; prints the original name with quotes(from awk); then the substituted name
xargs takes 2 lines at a time and passes it to mv
Try something like this, assuming all of your files were .txt's:
for files in *.txt; do mv “$files” `echo $files | tr ‘ ‘ ‘_’`; done
Quote your variables:
for file in *; do echo mv "'$file'" "${file// /_}"; done
Remove the "echo" to do the actual rename.
To rename all the files with a .py extension use,
find . -iname "*.py" -type f | xargs -I% rename "s/ /_/g" "%"
Sample output,
$ find . -iname "*.py" -type f
./Sample File.py
./Sample/Sample File.py
$ find . -iname "*.py" -type f | xargs -I% rename "s/ /_/g" "%"
$ find . -iname "*.py" -type f
./Sample/Sample_File.py
./Sample_File.py
This will replace ' ' with '_' in every folder and file name recursivelly in Linux with Python >= 3.5. Change path_to_your_folder with your path.
Only list files and folders:
python -c "import glob;[print(x) for x in glob.glob('path_to_your_folder/**', recursive=True)]"
Replace ' ' with '_' in every folder and file name
python -c "import os;import glob;[os.rename(x,x.replace(' ','_')) for x in glob.glob('path_to_your_folder/**', recursive=True)]"
With Python < 3.5, you can install glob2
pip install glob2
python -c "import os;import glob2;[os.rename(x,x.replace(' ','_')) for x in glob2.glob('path_to_your_folder/**')]"
The easiest way to replace a string (space character in your case) with another string in Linux is using sed. You can do it as follows
sed -i 's/\s/_/g' *
Hope this helps.